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<article xmlns="http://specifications.silverchair.com/xsd/article/1/0/SCJATS-journalpublishing1-0.xsd" xmlns:xlink="http://www.w3.org/1999/xlink" article-type="research-article" xml:lang="EN">
<front>
<journal-meta>
<journal-id journal-id-type="publisher-id">ptep</journal-id>
<journal-title-group>
<journal-title>Progress of Theoretical and Experimental Physics</journal-title>
</journal-title-group>
<issn pub-type="epub">2050-3911</issn>
<publisher>
<publisher-name>Oxford University Press</publisher-name>
</publisher>
</journal-meta>
<article-meta>
<article-id pub-id-type="doi">10.1093/ptep/ptx149</article-id>
<article-id pub-id-type="publisher-id">ptx149</article-id>
<article-id pub-id-type="arxiv">arXiv:1710.05125</article-id>
<article-categories>
<subj-group subj-group-type="category-toc-heading">
<subject>Papers</subject>
<subj-group subj-group-type="category-toc-heading">
<subject>Theoretical Particle Physics</subject>
</subj-group>
</subj-group>
<subj-group subj-group-type="category-journal-collection">
<subject>PTEP/B00</subject>
<subject>PTEP/B03</subject>
</subj-group>
</article-categories>
<title-group>
<article-title>Condensate <inline-formula><tex-math notation="LaTeX" id="ImEquation1"><![CDATA[$\langle A_{\mu}^+A_{\mu}^-\rangle$]]></tex-math></inline-formula> and massive magnetic potential in Euclidean gauge theories</article-title>
</title-group>
<contrib-group>
<contrib contrib-type="author" corresp="yes">
<name><surname>Sawayanagi</surname><given-names>Hirohumi</given-names></name>
<xref ref-type="aff" rid="AFF1"/>
<xref ref-type="corresp" rid="COR1"/>
<email xlink:type="simple">sawa@kushiro-ct.ac.jp</email>
</contrib>
</contrib-group>
<aff id="AFF1"><italic>National Institute of Technology, Kushiro College, Kushiro 084-0916, Japan</italic></aff>
<author-notes>
<corresp id="COR1"><label>*</label>E-mail: <email>sawa@kushiro-ct.ac.jp</email></corresp>
</author-notes>
<pub-date pub-type="cover">
<month>11</month>
<year>2017</year>
</pub-date>
<pub-date pub-type="collection">
<day>01</day>
<month>11</month>
<year>2017</year>
</pub-date>
<pub-date pub-type="epub" iso-8601-date="2017-11-29">
<day>29</day>
<month>11</month>
<year>2017</year>
</pub-date>
<volume>2017</volume>
<issue>11</issue>
<elocation-id>113B02</elocation-id>
<history>
<date date-type="received">
<day>7</day>
<month>3</month>
<year>2017</year>
</date>
<date date-type="rev-recd">
<day>11</day>
<month>10</month>
<year>2017</year>
</date>
<date date-type="accepted">
<day>12</day>
<month>10</month>
<year>2017</year>
</date>
</history>
<permissions>
<copyright-statement>&#x00A9; The Author(s) 2017. Published by Oxford University Press on behalf of the Physical Society of Japan.</copyright-statement>
<copyright-year>2017</copyright-year>
<license license-type="cc-by" xlink:href="http://creativecommons.org/licenses/by/4.0/">
<license-p>This is an Open Access article distributed under the terms of the Creative Commons Attribution License (<ext-link ext-link-type="uri" xmlns:xlink="http://www.w3.org/1999/xlink" xlink:href="http://creativecommons.org/licenses/by/4.0/">http://creativecommons.org/licenses/by/4.0/</ext-link>), which permits unrestricted reuse, distribution, and reproduction in any medium, provided the original work is properly cited.</license-p>
<license-p>Funded by SCOAP<sup>3</sup></license-p>
</license>
</permissions>
<self-uri xlink:href="ptx149.pdf"/>
<abstract abstract-type="abstract"><title>Abstract</title>
<p>Euclidean SU(2) gauge theory is studied in a nonlinear gauge. In this theory, ghost condensation happens and gauge fields acquire tachyonic masses. It is shown that these tachyonic masses are removed by a gauge field condensate <inline-formula><tex-math notation="LaTeX" id="ImEquation2"><![CDATA[$\langle A_{\mu}^+A_{\mu}^-\rangle$]]></tex-math></inline-formula>. Because of the ghost condensation, monopole solutions are included naturally. We find that the condensate <inline-formula><tex-math notation="LaTeX" id="ImEquation3"><![CDATA[$\langle A_{\mu}^+A_{\mu}^-\rangle$]]></tex-math></inline-formula> makes the magnetic potential massive.</p>
</abstract>
<kwd-group kwd-group-type="jel">
<kwd>B00</kwd>
<kwd>B03</kwd>
<kwd>B06</kwd>
</kwd-group>
<counts>
<page-count count="18"/>
</counts>
</article-meta>
</front>
<body>
<sec sec-type="intro" id="SEC1"><title>1. Introduction</title>
<p>In non-Abelian gauge theories, a magnetic monopole may play an important role. In the dual superconductor model of color confinement (see, e.g., Ref. [<xref ref-type="bibr" rid="B1">1</xref>]), monopole condensation is expected. As a result, a dual gauge field [<xref ref-type="bibr" rid="B2">2</xref>] acquires a mass, and color confinement may happen.</p>
<p>How can monopoles appear without Higgs fields? One way is the Abelian projection by &#x2019;t Hooft [<xref ref-type="bibr" rid="B3">3</xref>]. Let us consider a field <inline-formula><tex-math notation="LaTeX" id="ImEquation4"><![CDATA[$X(x)$]]></tex-math></inline-formula>, which belongs to the adjoint representation, and perform the Abelian gauge fixing. When we diagonalize <inline-formula><tex-math notation="LaTeX" id="ImEquation5"><![CDATA[$X(x)$]]></tex-math></inline-formula>, there may be points at which the eigenvalues of <inline-formula><tex-math notation="LaTeX" id="ImEquation6"><![CDATA[$X(x)$]]></tex-math></inline-formula> degenerate. Monopoles appear at these points. Another way is to introduce a unit color vector <inline-formula><tex-math notation="LaTeX" id="ImEquation7"><![CDATA[$\hat{n}^A(x)$]]></tex-math></inline-formula> in the internal space [<xref ref-type="bibr" rid="B4">4</xref>,<xref ref-type="bibr" rid="B5">5</xref>]. A non-Abelian magnetic potential is defined by
<disp-formula id="ptx149-M1-1"><label>(1.1)</label><tex-math notation="LaTeX" id="Equation1"><![CDATA[
\begin{equation}
C_{\mu}^A = \frac{-1}{g}(\hat{n}\times \partial_{\mu}\hat{n})^A, \label{101}
\end{equation}
]]></tex-math></disp-formula>
and the gauge field <inline-formula><tex-math notation="LaTeX" id="ImEquation8"><![CDATA[$A_{\mu}^A(x)$]]></tex-math></inline-formula> is decomposed by using <inline-formula><tex-math notation="LaTeX" id="ImEquation9"><![CDATA[$\hat{n}^A$]]></tex-math></inline-formula>. This model is called extended quantum chromodynamics (QCD) [<xref ref-type="bibr" rid="B6">6</xref>].</p>
<p>What is the origin of <inline-formula><tex-math notation="LaTeX" id="ImEquation10"><![CDATA[$\hat{n}^A$]]></tex-math></inline-formula>? Is it possible to make the magnetic potential massive? In this paper, we propose a scenario that produces <inline-formula><tex-math notation="LaTeX" id="ImEquation11"><![CDATA[$\hat{n}^A$]]></tex-math></inline-formula> and massive <inline-formula><tex-math notation="LaTeX" id="ImEquation12"><![CDATA[$C_{\mu}^A$]]></tex-math></inline-formula>. For simplicity, we consider the SU(2) gauge theory in Euclidean space-time, and sometimes call the gauge field a gluon. In the next section, we briefly review ghost condensation and tachyonic gluon masses. In <xref ref-type="sec" rid="SEC3">Sect. 3</xref>, it is shown that these tachyonic masses are removed by the vacuum expectation value (VEV) <inline-formula><tex-math notation="LaTeX" id="ImEquation13"><![CDATA[$\langle A_{\mu}^+A_{\mu}^-\rangle$]]></tex-math></inline-formula>. Under the ghost condensation, we can include a magnetic monopole as a classical solution. In <xref ref-type="sec" rid="SEC4">Sect. 4</xref>, we introduce it in the Abelian gauge. In the presence of the VEV <inline-formula><tex-math notation="LaTeX" id="ImEquation14"><![CDATA[$\langle A_{\mu}^+A_{\mu}^-\rangle$]]></tex-math></inline-formula>, a magnetic potential is expected to become massive. By using the background covariant gauge, we confirm this expectation in <xref ref-type="sec" rid="SEC5">Sect. 5</xref>. In <xref ref-type="sec" rid="SEC6">Sect. 6</xref>, to remove the Dirac string, we perform a singular gauge transformation, and derive the extended QCD with massive <inline-formula><tex-math notation="LaTeX" id="ImEquation15"><![CDATA[$C_{\mu}^A$]]></tex-math></inline-formula>. In <xref ref-type="sec" rid="SEC7">Sect. 7</xref>, the case of 3D space-time is discussed briefly. Section 8 is devoted to a summary and comments. In <xref ref-type="sec" rid="SECA">Appendix A</xref>, it is shown that <inline-formula><tex-math notation="LaTeX" id="ImEquation16"><![CDATA[$\langle (A_{\mu}^3)^2\rangle$]]></tex-math></inline-formula> vanishes. The tachyonic gluon mass is derived in the background covariant gauge in <xref ref-type="sec" rid="SECB">Appendix B</xref>. The singular gauge transformation used in <xref ref-type="sec" rid="SEC6">Sect. 6</xref> is summarized in <xref ref-type="sec" rid="SECC">Appendix C</xref>. The Becchi&#x2013;Rouet&#x2013;Stora (BRS) symmetry and the breakdown of the global gauge symmetry are explained in <xref ref-type="sec" rid="SECD">Appendix D</xref>.</p>
</sec>
<sec id="SEC2"><title>2. Ghost condensation and tachyonic gluon mass</title>
<p>We consider the SU(2) gauge theory with structure constants <inline-formula><tex-math notation="LaTeX" id="ImEquation17"><![CDATA[$f_{ABC}$]]></tex-math></inline-formula>. Using the notations
<disp-formula id="ptx149-UM1"><tex-math notation="LaTeX" id="Equation2"><![CDATA[
\[ F\cdot G=F^AG^A, \quad (F\times )^{AB}=f_{ACB}F^C, \quad
(F\times G)^A=f_{ABC}F^BG^C, \quad
A=1,2,3, \]
]]></tex-math></disp-formula>
the Lagrangian in the nonlinear gauge is given by [<xref ref-type="bibr" rid="B7">7</xref>]
<disp-formula id="ptx149-M2-1"><label>(2.1)</label><tex-math notation="LaTeX" id="Equation3"><![CDATA[
\begin{align}
\mathcal{L} &= \mathcal{L}_\mathrm{inv}+ \mathcal{L}_\mathrm{NL},\quad \mathcal{L}_\mathrm{inv}=\frac{1}{4}F_{\mu\nu}^2, \notag \\
\mathcal{L}_\mathrm{NL} &= B\cdot \partial_{\mu}A_{\mu}+i\bar{c}\cdot\partial_{\mu}D_{\mu}c-
\frac{\alpha_1}{2}B^2-\frac{\alpha_2}{2}\bar{B}^2 -B\cdot w, \label{201}
\end{align}
]]></tex-math></disp-formula>
where <inline-formula><tex-math notation="LaTeX" id="ImEquation18"><![CDATA[$\bar{B} = -B+ ig\bar{c} \times c$]]></tex-math></inline-formula>, <inline-formula><tex-math notation="LaTeX" id="ImEquation19"><![CDATA[$\alpha_1$]]></tex-math></inline-formula> and <inline-formula><tex-math notation="LaTeX" id="ImEquation20"><![CDATA[$\alpha_2$]]></tex-math></inline-formula> are gauge parameters, and <inline-formula><tex-math notation="LaTeX" id="ImEquation21"><![CDATA[$w$]]></tex-math></inline-formula> is a constant. Introducing the auxiliary field <inline-formula><tex-math notation="LaTeX" id="ImEquation22"><![CDATA[$\varphi$]]></tex-math></inline-formula>, which represents <inline-formula><tex-math notation="LaTeX" id="ImEquation23"><![CDATA[$\alpha_2 \bar{B}$]]></tex-math></inline-formula>, <inline-formula><tex-math notation="LaTeX" id="ImEquation24"><![CDATA[$\mathcal{L}_\mathrm{NL}$]]></tex-math></inline-formula> is rewritten as
<disp-formula id="ptx149-M2-2"><label>(2.2)</label><tex-math notation="LaTeX" id="Equation4"><![CDATA[
\begin{equation}
\mathcal{L}_{\varphi}=-\frac{\alpha_1}{2}B^2
+B\cdot (\partial_{\mu}A_{\mu}+\varphi -w)+i\bar{c} \cdot(\partial_{\mu}D_{\mu}+g\varphi \times )c
+\frac{\varphi^2}{2\alpha_2}. \label{202}
\end{equation}
]]></tex-math></disp-formula></p>
<p>In Ref. [<xref ref-type="bibr" rid="B8">8</xref>], we have shown that <inline-formula><tex-math notation="LaTeX" id="ImEquation25"><![CDATA[$g \varphi$]]></tex-math></inline-formula> acquires the VEV <inline-formula><tex-math notation="LaTeX" id="ImEquation26"><![CDATA[$v=g\varphi_0$]]></tex-math></inline-formula> under an energy scale <inline-formula><tex-math notation="LaTeX" id="ImEquation27"><![CDATA[$\mu_0$]]></tex-math></inline-formula>. Dividing the quantum fluctuation <inline-formula><tex-math notation="LaTeX" id="ImEquation28"><![CDATA[$\tilde{\varphi}(x)$]]></tex-math></inline-formula> from <inline-formula><tex-math notation="LaTeX" id="ImEquation29"><![CDATA[$\varphi_0$]]></tex-math></inline-formula>, we substitute <inline-formula><tex-math notation="LaTeX" id="ImEquation30"><![CDATA[$\varphi(x)=\varphi_0 + \tilde{\varphi}(x)$]]></tex-math></inline-formula> into Eq. (<xref ref-type="disp-formula" rid="ptx149-M2-2">2.2</xref>), and choose the constant <inline-formula><tex-math notation="LaTeX" id="ImEquation31"><![CDATA[$w=\varphi_0$]]></tex-math></inline-formula>. This choice is necessary to maintain the BRS symmetry [<xref ref-type="bibr" rid="B9">9</xref>].</p>
<p>Then Eq. (<xref ref-type="disp-formula" rid="ptx149-M2-2">2.2</xref>) becomes
<disp-formula id="ptx149-M2-3"><label>(2.3)</label><tex-math notation="LaTeX" id="Equation5"><![CDATA[
\begin{equation}
\mathcal{L}_{\varphi}'=-\frac{\alpha_1}{2}B^2
+B\cdot (\partial_{\mu}A_{\mu}+\tilde{\varphi} )+i\bar{c} \cdot(\partial_{\mu}D_{\mu}+g\tilde{\varphi} \times + g\varphi_0 \times )c .
\label{203}
\end{equation}
]]></tex-math></disp-formula></p>
<p>Because of the VEV <inline-formula><tex-math notation="LaTeX" id="ImEquation32"><![CDATA[$\varphi_0$]]></tex-math></inline-formula>, the global SU(2) symmetry breaks down to U(1). The relation between this breaking and BRS-invariant Green functions is explained in Ref. [<xref ref-type="bibr" rid="B10">10</xref>].<xref ref-type="fn" rid="FN1"><sup>1</sup></xref></p>
<p>Under the ghost condensation, the ghost-loop contribution to the gluon propagator was calculated. When the gluon momentum becomes small, it is found that the gluon acquires tachyonic mass [<xref ref-type="bibr" rid="B7">7</xref>,<xref ref-type="bibr" rid="B11">11</xref>]. The term <inline-formula><tex-math notation="LaTeX" id="ImEquation33"><![CDATA[$g\varphi_0\times$]]></tex-math></inline-formula> in the ghost propagator <inline-formula><tex-math notation="LaTeX" id="ImEquation34"><![CDATA[$(\partial_{\mu}^2+g\varphi_0\times)^{-1}$]]></tex-math></inline-formula> gives rise to the tachyonic mass. Now we choose the VEV in the third direction as <inline-formula><tex-math notation="LaTeX" id="ImEquation35"><![CDATA[$\langle \varphi^A\rangle=\varphi_0\delta^{A3}$]]></tex-math></inline-formula>, and use the notation <inline-formula><tex-math notation="LaTeX" id="ImEquation36"><![CDATA[$(A_{\mu}^a)^2=(A_{\mu}^1)^2+(A_{\mu}^2)^2$]]></tex-math></inline-formula>. Then, the scale <inline-formula><tex-math notation="LaTeX" id="ImEquation37"><![CDATA[$\mu_0$]]></tex-math></inline-formula>, the value of the VEV <inline-formula><tex-math notation="LaTeX" id="ImEquation38"><![CDATA[$v=g\varphi_0$]]></tex-math></inline-formula>, and the tachyonic gluon mass term in 4D Euclidean space (<inline-formula><tex-math notation="LaTeX" id="ImEquation39"><![CDATA[$D=4$]]></tex-math></inline-formula>) are summarized as
<disp-formula id="ptx149-M2-4"><label>(2.4)</label><tex-math notation="LaTeX" id="Equation6"><![CDATA[
\begin{equation}
\mu_0=\Lambda e^{-4\pi^2/(\alpha_2g^2)},\ v=\left\{\frac{\mu_0^4-\mu^4}{1-e^{-16\pi^2/(\alpha_2g^2)}}\right\}^{1/2},
\ \frac{1}{2}\left(\frac{-g^2v}{64\pi}\right)\left\{(A_{\mu}^a)^2+2(A_{\mu}^3)^2\right\}\!, \label{204}
\end{equation}
]]></tex-math></disp-formula>
where <inline-formula><tex-math notation="LaTeX" id="ImEquation40"><![CDATA[$\Lambda$]]></tex-math></inline-formula> is a momentum cut-off, and <inline-formula><tex-math notation="LaTeX" id="ImEquation41"><![CDATA[$\mu$]]></tex-math></inline-formula> is the momentum scale satisfying <inline-formula><tex-math notation="LaTeX" id="ImEquation42"><![CDATA[$\mu<\mu_0$]]></tex-math></inline-formula>. The coupling constant <inline-formula><tex-math notation="LaTeX" id="ImEquation43"><![CDATA[$g$]]></tex-math></inline-formula> and the gauge parameter <inline-formula><tex-math notation="LaTeX" id="ImEquation44"><![CDATA[$\alpha_2$]]></tex-math></inline-formula> in Eq. (<xref ref-type="disp-formula" rid="ptx149-M2-4">2.4</xref>) are the quantities at the scale <inline-formula><tex-math notation="LaTeX" id="ImEquation45"><![CDATA[$\Lambda$]]></tex-math></inline-formula>. In the same way, the corresponding quantities in 3D Euclidean space (<inline-formula><tex-math notation="LaTeX" id="ImEquation46"><![CDATA[$D=3$]]></tex-math></inline-formula>) are
<disp-formula id="ptx149-M2-5"><label>(2.5)</label><tex-math notation="LaTeX" id="Equation7"><![CDATA[
\begin{equation}
\mu_0=\frac{\alpha_2g_3^2\Lambda}{ \pi^2\Lambda+\alpha_2g_3^2},\ v_3=\frac{2}{16\pi^2}(\alpha_2g_3^2)^2,
\ \frac{1}{2}\left(\frac{-\alpha_2}{24\pi^2}g_3^4\right)\left\{(A_{\mu}^a)^2+\frac{3}{2}(A_{\mu}^3)^2\right\}\!,
\label{205}
\end{equation}
]]></tex-math></disp-formula>
where <inline-formula><tex-math notation="LaTeX" id="ImEquation47"><![CDATA[$g_3$]]></tex-math></inline-formula> and <inline-formula><tex-math notation="LaTeX" id="ImEquation48"><![CDATA[$v_3$]]></tex-math></inline-formula> are the coupling constant and the VEV <inline-formula><tex-math notation="LaTeX" id="ImEquation49"><![CDATA[$g\varphi_0$]]></tex-math></inline-formula> in <inline-formula><tex-math notation="LaTeX" id="ImEquation50"><![CDATA[$D=3$]]></tex-math></inline-formula>, respectively.</p>
</sec>
<sec id="SEC3"><title>3. Condensate <inline-formula><tex-math notation="LaTeX" id="ImEquation51"><![CDATA[$\boldsymbol{\langle A_{\mu}^+A_{\mu}^-\rangle}$]]></tex-math></inline-formula></title>
<p>From now on, we concentrate on the <inline-formula><tex-math notation="LaTeX" id="ImEquation52"><![CDATA[$D=4$]]></tex-math></inline-formula> case, and try to remove the tachyonic gluon mass. We write Eq. (<xref ref-type="disp-formula" rid="ptx149-M2-4">2.4</xref>) as
<disp-formula id="ptx149-M3-1"><label>(3.1)</label><tex-math notation="LaTeX" id="Equation8"><![CDATA[
\begin{equation}
-m_4^2 \left[A_{\mu}^+A_{\mu}^- + \frac{\kappa_4}{2} (A_{\mu}^3)^2\right],\ m_4^2=\frac{g^2v}{64\pi}, \ \kappa_4=2,
\label{301}
\end{equation}
]]></tex-math></disp-formula>
where <inline-formula><tex-math notation="LaTeX" id="ImEquation53"><![CDATA[$A_{\mu}^{\pm}=(A_{\mu}^1\pm iA_{\mu}^2)/\sqrt{2}$]]></tex-math></inline-formula>.</p>
<sec id="SEC3.1"><title>3.1. The effective potential for <inline-formula><tex-math notation="LaTeX" id="ImEquation54"><![CDATA[$\langle A_{\mu}^+A_{\mu}^-\rangle$]]></tex-math></inline-formula></title>
<p>When the tachyonic mass term (<xref ref-type="disp-formula" rid="ptx149-M3-1">3.1</xref>) exists, the gluon propagator blows up as <inline-formula><tex-math notation="LaTeX" id="ImEquation55"><![CDATA[$p^2\to m_4^2$]]></tex-math></inline-formula>. To avoid this, we return to the Lagrangian <inline-formula><tex-math notation="LaTeX" id="ImEquation56"><![CDATA[$\mathcal{L}_\mathrm{inv}+\mathcal{L}_{\varphi}'$]]></tex-math></inline-formula>, and introduce the source term <inline-formula><tex-math notation="LaTeX" id="ImEquation57"><![CDATA[$KA_{\mu}^+A_{\mu}^-$]]></tex-math></inline-formula> for the local composite operator (LCO) <inline-formula><tex-math notation="LaTeX" id="ImEquation58"><![CDATA[$A_{\mu}^+(x)A_{\mu}^-(x)$]]></tex-math></inline-formula>.<xref ref-type="fn" rid="FN2"><sup>2</sup></xref> The partition function is
<disp-formula id="ptx149-UM2"><tex-math notation="LaTeX" id="Equation9"><![CDATA[
\[
Z(J,K) = \int D\mu \exp \left[ -\frac{1}{\hslash}\left\{S+\int dx J\Psi+ \int dx K A_{\mu}^+A_{\mu}^- \right\} \right],
\]
]]></tex-math></disp-formula>
where the usual source terms are
<disp-formula id="ptx149-UM3"><tex-math notation="LaTeX" id="Equation10"><![CDATA[
\[ J\Psi=\bar{c} \eta + \bar{\eta}c + A_{\mu}^3J_{\mu}^3 + A_{\mu}^+J_{\mu}^- + A_{\mu}^-J_{\mu}^+. \]
]]></tex-math></disp-formula></p>
<p>Dividing the action <inline-formula><tex-math notation="LaTeX" id="ImEquation59"><![CDATA[$S$]]></tex-math></inline-formula> into free and interaction parts as <inline-formula><tex-math notation="LaTeX" id="ImEquation60"><![CDATA[$S=S_\mathrm{free}+S_\mathrm{int}$]]></tex-math></inline-formula>, and performing the Gaussian integration, we obtain
<disp-formula id="ptx149-UM4"><tex-math notation="LaTeX" id="Equation11"><![CDATA[
\[
Z(K) = \exp\left[-\frac{1}{\hslash}W(K)\right],\quad W(K)=W_1(K)+W_2(K)+\cdots ,
\]
]]></tex-math></disp-formula>
where <inline-formula><tex-math notation="LaTeX" id="ImEquation61"><![CDATA[$W_n$]]></tex-math></inline-formula> is <inline-formula><tex-math notation="LaTeX" id="ImEquation62"><![CDATA[$O(\hslash^n)$]]></tex-math></inline-formula>, and we set <inline-formula><tex-math notation="LaTeX" id="ImEquation63"><![CDATA[$J=0$]]></tex-math></inline-formula> after constructing <inline-formula><tex-math notation="LaTeX" id="ImEquation64"><![CDATA[$W(J,K)$]]></tex-math></inline-formula>. From <inline-formula><tex-math notation="LaTeX" id="ImEquation65"><![CDATA[$Z(K)$]]></tex-math></inline-formula>, we find
<disp-formula id="ptx149-M3-2"><label>(3.2)</label><tex-math notation="LaTeX" id="Equation12"><![CDATA[
\begin{equation}
\frac{\delta W}{\delta K(x)}= \langle A_{\mu}^+(x)A_{\mu}^-(x) \rangle =\hslash \Phi_4(x), \label{302}
\end{equation}
]]></tex-math></disp-formula>
and we define the effective action as
<disp-formula id="ptx149-M3-3"><label>(3.3)</label><tex-math notation="LaTeX" id="Equation13"><![CDATA[
\begin{equation}
\Gamma(\Phi_4)= W(K)- \hslash \int dx K\Phi_4. \label{303}
\end{equation}
]]></tex-math></disp-formula></p>
<p>If we write the <inline-formula><tex-math notation="LaTeX" id="ImEquation66"><![CDATA[$A_{\mu}^{\pm}$]]></tex-math></inline-formula>-related part in <inline-formula><tex-math notation="LaTeX" id="ImEquation67"><![CDATA[$S_\mathrm{free}$]]></tex-math></inline-formula> as <inline-formula><tex-math notation="LaTeX" id="ImEquation68"><![CDATA[$-A_{\mu}^+\Delta_{\mu\nu}A_{\nu}^-$]]></tex-math></inline-formula>, the <inline-formula><tex-math notation="LaTeX" id="ImEquation69"><![CDATA[$K$]]></tex-math></inline-formula>-dependent term in <inline-formula><tex-math notation="LaTeX" id="ImEquation70"><![CDATA[$W_1$]]></tex-math></inline-formula> becomes
<disp-formula id="ptx149-UM5"><tex-math notation="LaTeX" id="Equation14"><![CDATA[
\[ W_1(K)= \hslash \mathrm{Tr}\ln (-\Delta + K). \]
]]></tex-math></disp-formula></p>
<p>Thus, at <inline-formula><tex-math notation="LaTeX" id="ImEquation71"><![CDATA[$O(\hslash)$]]></tex-math></inline-formula>, Eq. (<xref ref-type="disp-formula" rid="ptx149-M3-2">3.2</xref>) gives
<disp-formula id="ptx149-M3-4"><label>(3.4)</label><tex-math notation="LaTeX" id="Equation15"><![CDATA[
\begin{equation}
\Phi_4(x) = \langle x|\left(-\Delta + K \right)^{-1}_{\mu\mu}|x \rangle. \label{304}
\end{equation}
]]></tex-math></disp-formula></p>
<p>From <inline-formula><tex-math notation="LaTeX" id="ImEquation72"><![CDATA[$S_\mathrm{int}$]]></tex-math></inline-formula>, the diagrams depicted in <xref ref-type="fig" rid="F1">Fig. 1</xref> contribute to <inline-formula><tex-math notation="LaTeX" id="ImEquation73"><![CDATA[$W_2$]]></tex-math></inline-formula>. Since the kinetic term <inline-formula><tex-math notation="LaTeX" id="ImEquation74"><![CDATA[$(F_{\mu\nu}^A)^2/4$]]></tex-math></inline-formula> contains the terms</p>
<fig id="F1" orientation="portrait" position="float"><label>Fig. 1.</label><caption><p>The diagrams that contribute to the effective potential <inline-formula><tex-math notation="LaTeX" id="ImEquation75"><![CDATA[$\Gamma(\Phi_4)$]]></tex-math></inline-formula> at <inline-formula><tex-math notation="LaTeX" id="ImEquation76"><![CDATA[$O(\hslash^2)$]]></tex-math></inline-formula>. The solid line represents <inline-formula><tex-math notation="LaTeX" id="ImEquation77"><![CDATA[$A_{\mu}^{+}A_{\nu}^{-}$]]></tex-math></inline-formula>, the dotted line is <inline-formula><tex-math notation="LaTeX" id="ImEquation78"><![CDATA[$c \bar{c}$]]></tex-math></inline-formula>, and the dashed line represents <inline-formula><tex-math notation="LaTeX" id="ImEquation79"><![CDATA[$A_{\mu}^3A_{\nu}^3$]]></tex-math></inline-formula>.</p></caption>
<graphic xmlns:xlink="http://www.w3.org/1999/xlink" orientation="portrait" position="float" xlink:href="ptx149F1.tif"/></fig>
<p><disp-formula id="ptx149-M3-5"><label>(3.5)</label><tex-math notation="LaTeX" id="Equation16"><![CDATA[
\begin{eqnarray}
\frac{g^2}{4}(f^{ABC}A_{\mu}^BA_{\nu}^C)^2&=&
\frac{g^2}{2}(A_{\mu}^+A_{\mu}^-)^2
+g^2(A_{\mu}^+A_{\mu}^-)(A_{\nu}^3)^2 \nonumber \\
& & - \frac{g^2}{2}(A_{\mu}^+)^2(A_{\nu}^-)^2
-g^2(A_{\mu}^+A_{\mu}^3)(A_{\nu}^-A_{\nu}^3), \label{305}
\end{eqnarray}
]]></tex-math></disp-formula>
the diagram in <xref ref-type="fig" rid="F1">Fig. 1(a)</xref> comes from the vertex <inline-formula><tex-math notation="LaTeX" id="ImEquation80"><![CDATA[$\frac{g^2}{2}(A_{\mu}^+A_{\mu}^-)^2$]]></tex-math></inline-formula> in Eq. (<xref ref-type="disp-formula" rid="ptx149-M3-5">3.5</xref>). Applying Eq. (<xref ref-type="disp-formula" rid="ptx149-M3-4">3.4</xref>), it gives <inline-formula><tex-math notation="LaTeX" id="ImEquation81"><![CDATA[$\hslash^2\frac{g^2}{2}\Phi_4^2$]]></tex-math></inline-formula>. The ghost loop in <xref ref-type="fig" rid="F1">Fig. 1(b)</xref> yields the term <inline-formula><tex-math notation="LaTeX" id="ImEquation82"><![CDATA[$-m_4^2 \hslash \delta_{\mu\nu}$]]></tex-math></inline-formula>, which makes <inline-formula><tex-math notation="LaTeX" id="ImEquation83"><![CDATA[$A_{\mu}^{\pm}$]]></tex-math></inline-formula> tachyonic. Using Eq. (<xref ref-type="disp-formula" rid="ptx149-M3-4">3.4</xref>) again, <xref ref-type="fig" rid="F1">Fig. 1(b)</xref> gives <inline-formula><tex-math notation="LaTeX" id="ImEquation84"><![CDATA[$-m_4^2 \hslash^2 \Phi_4$]]></tex-math></inline-formula>. The diagrams in <xref ref-type="fig" rid="F1">Fig. 1(c)</xref> contain the loops with <inline-formula><tex-math notation="LaTeX" id="ImEquation85"><![CDATA[$A_{\mu}^3$]]></tex-math></inline-formula>. In the dimensional regularization, as <inline-formula><tex-math notation="LaTeX" id="ImEquation86"><![CDATA[$\int d^4k (1/k^2)=0$]]></tex-math></inline-formula>, these diagrams vanish. If the source <inline-formula><tex-math notation="LaTeX" id="ImEquation87"><![CDATA[$K$]]></tex-math></inline-formula> is constant, it plays the role of mass-squared <inline-formula><tex-math notation="LaTeX" id="ImEquation88"><![CDATA[$M_4^2$]]></tex-math></inline-formula> for the <inline-formula><tex-math notation="LaTeX" id="ImEquation89"><![CDATA[$A_{\mu}^{\pm}$]]></tex-math></inline-formula>. So the diagrams in <xref ref-type="fig" rid="F1">Fig. 1(d)</xref> can produce the term <inline-formula><tex-math notation="LaTeX" id="ImEquation90"><![CDATA[$z_1K\hslash^2\Phi_4$]]></tex-math></inline-formula>, where <inline-formula><tex-math notation="LaTeX" id="ImEquation91"><![CDATA[$z_1$]]></tex-math></inline-formula> is a divergent constant. This divergence should be removed by the renormalization of <inline-formula><tex-math notation="LaTeX" id="ImEquation92"><![CDATA[$K$]]></tex-math></inline-formula>. By summing up these results, <inline-formula><tex-math notation="LaTeX" id="ImEquation93"><![CDATA[$W_2$]]></tex-math></inline-formula> becomes <inline-formula><tex-math notation="LaTeX" id="ImEquation94"><![CDATA[$\Gamma_2(\Phi_4)=\hslash^2V(\Phi_4)$]]></tex-math></inline-formula>, where
<disp-formula id="ptx149-M3-6"><label>(3.6)</label><tex-math notation="LaTeX" id="Equation17"><![CDATA[
\begin{equation}
V(\Phi_4)=\frac{g^2}{2}\Phi_4^2-m_4^2\Phi_4. \label{306}
\end{equation}
]]></tex-math></disp-formula></p>
<p>Thus, up to <inline-formula><tex-math notation="LaTeX" id="ImEquation95"><![CDATA[$O(\hslash^2)$]]></tex-math></inline-formula>, we obtain
<disp-formula id="ptx149-M3-7"><label>(3.7)</label><tex-math notation="LaTeX" id="Equation18"><![CDATA[
\begin{equation}
\Gamma(\Phi_4)= W_1(K) + \hslash^2 V(\Phi_4)- \hslash \int dx K\Phi_4. \label{307}
\end{equation}
]]></tex-math></disp-formula></p>
<p>This <inline-formula><tex-math notation="LaTeX" id="ImEquation96"><![CDATA[$\Gamma$]]></tex-math></inline-formula> satisfies
<disp-formula id="ptx149-M3-8"><label>(3.8)</label><tex-math notation="LaTeX" id="Equation19"><![CDATA[
\begin{equation}
\frac{\delta \Gamma}{\delta \Phi_4}= \left(\frac{\delta W_1}{\delta K}-\hslash
\Phi_4\right) \frac{\delta K}{\delta \Phi_4} + \hslash^2 \frac{d V}{d
\Phi_4}-\hslash K=\hslash^2 \frac{d V}{d \Phi_4}-\hslash K, \label{308}
\end{equation}
]]></tex-math></disp-formula>
where Eq. (<xref ref-type="disp-formula" rid="ptx149-M3-4">3.4</xref>) has been used. Since <inline-formula><tex-math notation="LaTeX" id="ImEquation97"><![CDATA[$\Gamma$]]></tex-math></inline-formula> satisfies <inline-formula><tex-math notation="LaTeX" id="ImEquation98"><![CDATA[$\delta \Gamma/\delta \Phi_4=-\hslash K$]]></tex-math></inline-formula>, from Eq. (<xref ref-type="disp-formula" rid="ptx149-M3-8">3.8</xref>), we obtain <inline-formula><tex-math notation="LaTeX" id="ImEquation99"><![CDATA[$dV/d\Phi_4=0$]]></tex-math></inline-formula>.</p>
<p>In <xref ref-type="fig" rid="F2">Fig. 2(a)</xref>, the diagrams that contribute to <inline-formula><tex-math notation="LaTeX" id="ImEquation100"><![CDATA[$V(\Phi_4)$]]></tex-math></inline-formula> are depicted. The closed loop with a solid line represents <inline-formula><tex-math notation="LaTeX" id="ImEquation101"><![CDATA[$\Phi_4(x)$]]></tex-math></inline-formula>. As we show in <xref ref-type="fig" rid="F2">Fig. 2(b)</xref>, by removing one closed loop, the diagrams that correspond to <inline-formula><tex-math notation="LaTeX" id="ImEquation102"><![CDATA[$dV/d \Phi_4$]]></tex-math></inline-formula> are obtained. If we cut one closed loop as in <xref ref-type="fig" rid="F2">Fig. 2(c)</xref>, the diagrams that contribute to the mass term for <inline-formula><tex-math notation="LaTeX" id="ImEquation103"><![CDATA[$A_{\mu}^+(x)A_{\mu}^-(x)$]]></tex-math></inline-formula> are obtained. Therefore, when the condition <inline-formula><tex-math notation="LaTeX" id="ImEquation104"><![CDATA[$dV/d\Phi_4=0$]]></tex-math></inline-formula> holds, the two diagrams in <xref ref-type="fig" rid="F2">Fig. 2(c)</xref> cancel out. In the same way, in <inline-formula><tex-math notation="LaTeX" id="ImEquation105"><![CDATA[$D=4$]]></tex-math></inline-formula>, the diagrams depicted in <xref ref-type="fig" rid="F1">Fig. 1(d)</xref> cancel out. Namely, the diagrams in <xref ref-type="fig" rid="F2">Figs. 2(c)</xref> and <xref ref-type="fig" rid="F2">(d)</xref> do not contribute to the masses for <inline-formula><tex-math notation="LaTeX" id="ImEquation106"><![CDATA[$A_{\mu}^{\pm}$]]></tex-math></inline-formula> and <inline-formula><tex-math notation="LaTeX" id="ImEquation107"><![CDATA[$A_{\mu}^3$]]></tex-math></inline-formula>, respectively.</p>
<fig id="F2" orientation="portrait" position="float"><label>Fig. 2.</label><caption><p>The diagrams that contribute to <inline-formula><tex-math notation="LaTeX" id="ImEquation108"><![CDATA[$V(\Phi)$]]></tex-math></inline-formula>, <inline-formula><tex-math notation="LaTeX" id="ImEquation109"><![CDATA[$dV/d\Phi_4=0$]]></tex-math></inline-formula>, and the mass terms for <inline-formula><tex-math notation="LaTeX" id="ImEquation110"><![CDATA[$A_{\mu}^{\pm}$]]></tex-math></inline-formula> and <inline-formula><tex-math notation="LaTeX" id="ImEquation111"><![CDATA[$A_{\mu}^{3}$]]></tex-math></inline-formula>.</p></caption>
<graphic xmlns:xlink="http://www.w3.org/1999/xlink" orientation="portrait" position="float" xlink:href="ptx149F2.tif"/></fig>
<p>We summarize the results. Up to <inline-formula><tex-math notation="LaTeX" id="ImEquation112"><![CDATA[$O(\hslash^2)$]]></tex-math></inline-formula>, the effective potential <inline-formula><tex-math notation="LaTeX" id="ImEquation113"><![CDATA[$\Gamma$]]></tex-math></inline-formula> is Eq. (<xref ref-type="disp-formula" rid="ptx149-M3-7">3.7</xref>). As it satisfies <inline-formula><tex-math notation="LaTeX" id="ImEquation114"><![CDATA[$\delta \Gamma/\delta \Phi_4=-\hslash K$]]></tex-math></inline-formula>, we obtain Eq. (<xref ref-type="disp-formula" rid="ptx149-M3-4">3.4</xref>) and <inline-formula><tex-math notation="LaTeX" id="ImEquation115"><![CDATA[$dV/d\Phi_4=0$]]></tex-math></inline-formula>. Using Eq. (<xref ref-type="disp-formula" rid="ptx149-M3-6">3.6</xref>), <inline-formula><tex-math notation="LaTeX" id="ImEquation116"><![CDATA[$dV/d\Phi_4=0$]]></tex-math></inline-formula> gives
<disp-formula id="ptx149-M3-9"><label>(3.9)</label><tex-math notation="LaTeX" id="Equation20"><![CDATA[
\begin{equation}
\Phi_4=\langle A_{\mu}^+A_{\mu}^- \rangle=\frac{m_4^2}{g^2}=\frac{v}{64\pi}, \label{309}
\end{equation}
]]></tex-math></disp-formula>
and Eqs. (<xref ref-type="disp-formula" rid="ptx149-M3-4">3.4</xref>) and (<xref ref-type="disp-formula" rid="ptx149-M3-9">3.9</xref>) give
<disp-formula id="ptx149-M3-10"><label>(3.10)</label><tex-math notation="LaTeX" id="Equation21"><![CDATA[
\begin{equation}
\frac{m_4^2}{g^2}= \langle x|\left(-\Delta+M_4^2 \right)^{-1}_{\mu\mu}|x \rangle, \label{310}
\end{equation}
]]></tex-math></disp-formula>
where we set <inline-formula><tex-math notation="LaTeX" id="ImEquation117"><![CDATA[$K=M_4^2$]]></tex-math></inline-formula>. Thus, when <inline-formula><tex-math notation="LaTeX" id="ImEquation118"><![CDATA[$m_4\neq 0$]]></tex-math></inline-formula>, the condensate <inline-formula><tex-math notation="LaTeX" id="ImEquation119"><![CDATA[$\Phi_4$]]></tex-math></inline-formula> exists, and the mass <inline-formula><tex-math notation="LaTeX" id="ImEquation120"><![CDATA[$M_4$]]></tex-math></inline-formula> for <inline-formula><tex-math notation="LaTeX" id="ImEquation121"><![CDATA[$A_{\mu}^{\pm}$]]></tex-math></inline-formula> is determined by Eq. (<xref ref-type="disp-formula" rid="ptx149-M3-10">3.10</xref>).</p>
<p>As <inline-formula><tex-math notation="LaTeX" id="ImEquation122"><![CDATA[$\Delta_{\mu\nu}$]]></tex-math></inline-formula> contains a gauge parameter, Eq. (<xref ref-type="disp-formula" rid="ptx149-M3-10">3.10</xref>) is gauge-dependent and requires regularization. So, although Eq. (<xref ref-type="disp-formula" rid="ptx149-M3-10">3.10</xref>) implies that <inline-formula><tex-math notation="LaTeX" id="ImEquation123"><![CDATA[$M_4\neq 0$]]></tex-math></inline-formula>, the determination of this must be done carefully. We do not try to determine <inline-formula><tex-math notation="LaTeX" id="ImEquation124"><![CDATA[$M_4$]]></tex-math></inline-formula> in this paper, and make it a future task.</p>
</sec>
<sec id="SEC3.2"><title>3.2. Expedient procedure</title>
<p>The above results are obtained simply by the following procedure. Add the tachyonic mass term (<xref ref-type="disp-formula" rid="ptx149-M3-1">3.1</xref>) to the Lagrangian. Then replace <inline-formula><tex-math notation="LaTeX" id="ImEquation125"><![CDATA[$A_{\mu}^+A_{\mu}^-$]]></tex-math></inline-formula> as
<disp-formula id="ptx149-M3-11"><label>(3.11)</label><tex-math notation="LaTeX" id="Equation22"><![CDATA[
\begin{equation}
A_{\mu}^+A_{\mu}^- \to \Phi_4 + A_{\mu}^+A_{\mu}^-, \quad
\Phi_4=\langle A_{\mu}^+A_{\mu}^- \rangle, \label{311}
\end{equation}
]]></tex-math></disp-formula>
and add the source term <inline-formula><tex-math notation="LaTeX" id="ImEquation126"><![CDATA[$M_4^2 A_{\mu}^+A_{\mu}^-$]]></tex-math></inline-formula>. Then we obtain the following terms that contain <inline-formula><tex-math notation="LaTeX" id="ImEquation127"><![CDATA[$m_4^2, M_4^2$]]></tex-math></inline-formula>, or <inline-formula><tex-math notation="LaTeX" id="ImEquation128"><![CDATA[$\Phi_4$]]></tex-math></inline-formula>:
<disp-formula id="ptx149-M3-12"><label>(3.12)</label><tex-math notation="LaTeX" id="Equation23"><![CDATA[
\begin{equation}
V(\Phi_4) + (g^2\Phi_4 -m_4^2)[A_{\mu}^+A_{\mu}^- + (A_{\mu}^3)^2]+M_4^2 A_{\mu}^+A_{\mu}^-, \label{312}
\end{equation}
]]></tex-math></disp-formula>
where Eq. (<xref ref-type="disp-formula" rid="ptx149-M3-5">3.5</xref>) has been used. From <inline-formula><tex-math notation="LaTeX" id="ImEquation129"><![CDATA[$dV/d\Phi_4=0$]]></tex-math></inline-formula>, Eq. (<xref ref-type="disp-formula" rid="ptx149-M3-9">3.9</xref>) holds and Eq. (<xref ref-type="disp-formula" rid="ptx149-M3-12">3.12</xref>) becomes <inline-formula><tex-math notation="LaTeX" id="ImEquation130"><![CDATA[$M_4^2 A_{\mu}^+A_{\mu}^-$]]></tex-math></inline-formula>. Namely, the tachyonic masses are removed and, whereas <inline-formula><tex-math notation="LaTeX" id="ImEquation131"><![CDATA[$A_{\mu}^3$]]></tex-math></inline-formula> is massless, <inline-formula><tex-math notation="LaTeX" id="ImEquation132"><![CDATA[$A_{\mu}^{\pm}$]]></tex-math></inline-formula> acquire the mass <inline-formula><tex-math notation="LaTeX" id="ImEquation133"><![CDATA[$M_4$]]></tex-math></inline-formula>. In the following sections, we apply this procedure for simplicity.</p>
<p>We note, although the component <inline-formula><tex-math notation="LaTeX" id="ImEquation134"><![CDATA[$A_{\mu}^3$]]></tex-math></inline-formula> has the tachyonic mass in Eq. (<xref ref-type="disp-formula" rid="ptx149-M3-1">3.1</xref>) as well, we did not take the source term for <inline-formula><tex-math notation="LaTeX" id="ImEquation135"><![CDATA[$(A_{\mu}^3)^2$]]></tex-math></inline-formula> and the VEV <inline-formula><tex-math notation="LaTeX" id="ImEquation136"><![CDATA[$\langle (A_{\mu}^3)^2\rangle$]]></tex-math></inline-formula> into account. In <xref ref-type="sec" rid="SECA">Appendix A</xref>, it is shown that the VEV <inline-formula><tex-math notation="LaTeX" id="ImEquation137"><![CDATA[$\langle (A_{\mu}^3)^2\rangle$]]></tex-math></inline-formula> vanishes.</p>
</sec>
</sec>
<sec id="SEC4"><title>4. Inclusion of monopoles</title>
<p>The Lagrangian <inline-formula><tex-math notation="LaTeX" id="ImEquation138"><![CDATA[$\mathcal{L}_{\varphi}$]]></tex-math></inline-formula> is invariant under the BRS transformation <inline-formula><tex-math notation="LaTeX" id="ImEquation139"><![CDATA[$\delta_B$]]></tex-math></inline-formula>, if the field <inline-formula><tex-math notation="LaTeX" id="ImEquation140"><![CDATA[$\varphi$]]></tex-math></inline-formula> transforms as <inline-formula><tex-math notation="LaTeX" id="ImEquation141"><![CDATA[$\delta_B \varphi=g\varphi \times c$]]></tex-math></inline-formula>. That is, <inline-formula><tex-math notation="LaTeX" id="ImEquation142"><![CDATA[$\varphi$]]></tex-math></inline-formula> behaves like a Higgs field in the adjoint representation. As <inline-formula><tex-math notation="LaTeX" id="ImEquation143"><![CDATA[$\varphi$]]></tex-math></inline-formula> acquires the VEV <inline-formula><tex-math notation="LaTeX" id="ImEquation144"><![CDATA[$\langle \varphi^A\rangle =(v/g)\delta^{A3}$]]></tex-math></inline-formula>, we can introduce Abelian monopoles in the <inline-formula><tex-math notation="LaTeX" id="ImEquation145"><![CDATA[$A=3$]]></tex-math></inline-formula> direction [<xref ref-type="bibr" rid="B14">14</xref>]. Let us consider the classical field <inline-formula><tex-math notation="LaTeX" id="ImEquation146"><![CDATA[$b_{\mu}^A=\tilde{C}_{\mu}\delta^{A3}$]]></tex-math></inline-formula>, which satisfies the equation of motion
<disp-formula id="ptx149-UM6"><tex-math notation="LaTeX" id="Equation24"><![CDATA[
\[ \partial_{\nu}^2 b_{\mu}^A-\partial_{\mu}\partial_{\nu}b_{\nu}^A=0. \]
]]></tex-math></disp-formula></p>
<p>Except for a string singularity, it is known that the configuration
<disp-formula id="ptx149-UM7"><tex-math notation="LaTeX" id="Equation25"><![CDATA[
\[ \tilde{C}_{\mu}=\frac{n}{g}(\cos \theta -a)\partial_{\mu}\phi \]
]]></tex-math></disp-formula>
satisfies this equation, where <inline-formula><tex-math notation="LaTeX" id="ImEquation147"><![CDATA[$n$]]></tex-math></inline-formula> is an integer, and <inline-formula><tex-math notation="LaTeX" id="ImEquation148"><![CDATA[$(r, \theta, \phi)$]]></tex-math></inline-formula> are spherical coordinates. If <inline-formula><tex-math notation="LaTeX" id="ImEquation149"><![CDATA[$a=1$]]></tex-math></inline-formula> (<inline-formula><tex-math notation="LaTeX" id="ImEquation150"><![CDATA[$a=-1$]]></tex-math></inline-formula>), the Dirac string appears on the negative (positive) <inline-formula><tex-math notation="LaTeX" id="ImEquation151"><![CDATA[$z$]]></tex-math></inline-formula>-axis. In <xref ref-type="sec" rid="SEC6">Sect. 6</xref>, we choose <inline-formula><tex-math notation="LaTeX" id="ImEquation152"><![CDATA[$a=1$]]></tex-math></inline-formula> as a concrete example, i.e.,
<disp-formula id="ptx149-M4-1"><label>(4.1)</label><tex-math notation="LaTeX" id="Equation26"><![CDATA[
\begin{equation}
\tilde{C}_{\mu}=\frac{n}{g}(\cos \theta -1)\partial_{\mu}\phi=\frac{n}{g}\frac{z-r}{r(x^2+y^2)}(0,-y,x,0). \label{401}
\end{equation}
]]></tex-math></disp-formula></p>
<p>This monopole satisfies the equation of motion
<disp-formula id="ptx149-UM8"><tex-math notation="LaTeX" id="Equation27"><![CDATA[
\[ \partial_{\nu}(\partial_{\nu} \tilde{C}_{\mu}-\partial_{\mu}\tilde{C}_{\nu})=\epsilon_{\nu\mu\alpha\beta}\partial_{\nu}\frac{n_{\alpha}}{n_{\rho} \partial_{\rho}}k_{\beta}, \]
]]></tex-math></disp-formula>
where
<disp-formula id="ptx149-UM9"><tex-math notation="LaTeX" id="Equation28"><![CDATA[
\[ n_{\alpha}=\delta_{\alpha 3},\quad k_{\beta}=\delta_{\beta 0}\frac{4\pi n}{g} \delta(x)\delta(y)\delta(z). \]
]]></tex-math></disp-formula></p>
<p>We call <inline-formula><tex-math notation="LaTeX" id="ImEquation153"><![CDATA[$\tilde{C}_{\mu}$]]></tex-math></inline-formula> a magnetic potential.</p>
<p>In <xref ref-type="sec" rid="SEC3">Sect. 3</xref>, we have shown that the VEV <inline-formula><tex-math notation="LaTeX" id="ImEquation154"><![CDATA[$\Phi_4=\langle A_{\mu}^+A_{\mu}^-\rangle$]]></tex-math></inline-formula> removes the tachyonic mass for the gluon. What happens for the classical solution <inline-formula><tex-math notation="LaTeX" id="ImEquation155"><![CDATA[$b_{\mu}^A$]]></tex-math></inline-formula>? If we substitute <inline-formula><tex-math notation="LaTeX" id="ImEquation156"><![CDATA[$A_{\mu}^A=a_{\mu}^A+b_{\mu}^A$]]></tex-math></inline-formula> into Eq. (<xref ref-type="disp-formula" rid="ptx149-M3-5">3.5</xref>), Eq. (<xref ref-type="disp-formula" rid="ptx149-M3-12">3.12</xref>) changes to
<disp-formula id="ptx149-M4-2"><label>(4.2)</label><tex-math notation="LaTeX" id="Equation29"><![CDATA[
\begin{equation}
V(\Phi_4) + (g^2\Phi_4 -m_4^2)[a_{\mu}^+a_{\mu}^- + (a_{\mu}^3)^2] + M_4^2a_{\mu}^+a_{\mu}^-
+g^2\Phi_4[2b_{\mu}^3a_{\mu}^3 + (b_{\mu}^3)^2]. \label{402}
\end{equation}
]]></tex-math></disp-formula></p>
<p>As <inline-formula><tex-math notation="LaTeX" id="ImEquation157"><![CDATA[$\Phi_4$]]></tex-math></inline-formula> is given by Eq. (<xref ref-type="disp-formula" rid="ptx149-M3-5">3.5</xref>), the mass term for the magnetic potential appears as
<disp-formula id="ptx149-M4-3"><label>(4.3)</label><tex-math notation="LaTeX" id="Equation30"><![CDATA[
\begin{equation}
g^2\Phi_4 (b_{\mu}^3)^2=m_4^2\tilde{C}_{\mu}\tilde{C}_{\mu}. \label{403}
\end{equation}
]]></tex-math></disp-formula></p>
<p>In the next section, we study the mass for <inline-formula><tex-math notation="LaTeX" id="ImEquation158"><![CDATA[$\tilde{C}_{\mu}$]]></tex-math></inline-formula> by using the background covariant gauge.</p>
</sec>
<sec id="SEC5"><title>5. Massive magnetic potential</title>
<p>First we derive the Lagrangian with the field <inline-formula><tex-math notation="LaTeX" id="ImEquation159"><![CDATA[$\varphi^A$]]></tex-math></inline-formula> and the magnetic potential <inline-formula><tex-math notation="LaTeX" id="ImEquation160"><![CDATA[$\tilde{C}_{\mu}$]]></tex-math></inline-formula> in the background covariant gauge [<xref ref-type="bibr" rid="B15">15</xref>]. We divide <inline-formula><tex-math notation="LaTeX" id="ImEquation161"><![CDATA[$A_{\mu}^A$]]></tex-math></inline-formula> into the classical part <inline-formula><tex-math notation="LaTeX" id="ImEquation162"><![CDATA[$b_{\mu}^A$]]></tex-math></inline-formula> and the quantum fluctuation <inline-formula><tex-math notation="LaTeX" id="ImEquation163"><![CDATA[$a_{\mu}^A$]]></tex-math></inline-formula> as<xref ref-type="fn" rid="FN3"><sup>3</sup></xref>
<disp-formula id="ptx149-UM10"><tex-math notation="LaTeX" id="Equation31"><![CDATA[
\[ A_{\mu}^A = b_{\mu}^A + a_{\mu}^A, \quad b_{\mu}^A=\tilde{C}_{\mu}\delta^{A3}. \]
]]></tex-math></disp-formula></p>
<p>Then the gauge transformation
<disp-formula id="ptx149-M5-1"><label>(5.1)</label><tex-math notation="LaTeX" id="Equation32"><![CDATA[
\begin{equation}
\delta A_{\mu} = D_{\mu}(A) \varepsilon \label{501}
\end{equation}
]]></tex-math></disp-formula>
is satisfied by
<disp-formula id="ptx149-M5-2"><label>(5.2)</label><tex-math notation="LaTeX" id="Equation33"><![CDATA[
\begin{equation}
\delta a_{\mu} = D_{\mu}(b+a) \varepsilon,\ \delta b_{\mu} = 0, \label{502}
\end{equation}
]]></tex-math></disp-formula>
where the notation <inline-formula><tex-math notation="LaTeX" id="ImEquation164"><![CDATA[$D_{\mu}(A)=(\partial_{\mu}+gA_{\mu}\times)$]]></tex-math></inline-formula> has been used. Choosing the gauge-fixing function
<disp-formula id="ptx149-UM11"><tex-math notation="LaTeX" id="Equation34"><![CDATA[
\[ \tilde{G}(a)=D_{\mu}(b)a_{\mu}+\varphi-w=(\partial_{\mu}+gb_{\mu}\times)a_{\mu}+\varphi-w, \]
]]></tex-math></disp-formula>
and applying the transformation (<xref ref-type="disp-formula" rid="ptx149-M5-2">5.2</xref>), we obtain the Lagrangian
<disp-formula id="ptx149-M5-3"><label>(5.3)</label><tex-math notation="LaTeX" id="Equation35"><![CDATA[
\begin{align}
\mathcal{L}&= \mathcal{L}_\mathrm{inv}(b+a)+ \tilde{\mathcal{L}}_{\varphi}(a,b), \nonumber \\
\tilde{\mathcal{L}}_{\varphi}(a,b)&= -\frac{\alpha_1}{2}B^2
+B\cdot [D_{\mu}(b)a_{\mu}+\varphi -w]+i\bar{c} \cdot[D_{\mu}(b)D_{\mu}(b+a)+g\varphi \times ]c+\frac{\varphi^2}{2\alpha_2}, \label{503}
\end{align}
]]></tex-math></disp-formula>
where <inline-formula><tex-math notation="LaTeX" id="ImEquation165"><![CDATA[$w$]]></tex-math></inline-formula> is a constant. We require that <inline-formula><tex-math notation="LaTeX" id="ImEquation166"><![CDATA[$\varphi^A$]]></tex-math></inline-formula> belongs to the adjoint representation, and it transforms as <inline-formula><tex-math notation="LaTeX" id="ImEquation167"><![CDATA[$\delta \varphi= g\varphi\times \varepsilon$]]></tex-math></inline-formula>. The last term <inline-formula><tex-math notation="LaTeX" id="ImEquation168"><![CDATA[$\varphi^2/(2\alpha_2)$]]></tex-math></inline-formula> is added because it is gauge-invariant and necessary to yield the quartic ghost interaction term <inline-formula><tex-math notation="LaTeX" id="ImEquation169"><![CDATA[$-\alpha_2\bar{B}^2/2$]]></tex-math></inline-formula> in Eq. (<xref ref-type="disp-formula" rid="ptx149-M2-1">2.1</xref>).</p>
<p>Since the ghost condensation happens by the quartic ghost interaction [<xref ref-type="bibr" rid="B16">16</xref>], the condensate <inline-formula><tex-math notation="LaTeX" id="ImEquation170"><![CDATA[$v=g\varphi_0$]]></tex-math></inline-formula> appears irrespective of <inline-formula><tex-math notation="LaTeX" id="ImEquation171"><![CDATA[$b_{\mu}$]]></tex-math></inline-formula>. Thus, after the ghost condensation, <inline-formula><tex-math notation="LaTeX" id="ImEquation172"><![CDATA[$\tilde{\mathcal{L}}_{\varphi}(a,b)$]]></tex-math></inline-formula> becomes
<disp-formula id="ptx149-M5-4"><label>(5.4)</label><tex-math notation="LaTeX" id="Equation36"><![CDATA[
\begin{equation}
\tilde{\mathcal{L}}_{\varphi}(a,b)= -\frac{\alpha_1}{2}B^2
+B\cdot [D_{\mu}(b)a_{\mu}+\tilde{\varphi} ]+i\bar{c} \cdot[D_{\mu}(b)D_{\mu}(b+a)+g(\varphi_0+\tilde{\varphi}) \times ]c, \label{504}
\end{equation}
]]></tex-math></disp-formula>
where <inline-formula><tex-math notation="LaTeX" id="ImEquation173"><![CDATA[$\varphi(x)=\varphi_0 + \tilde{\varphi}(x)$]]></tex-math></inline-formula> and <inline-formula><tex-math notation="LaTeX" id="ImEquation174"><![CDATA[$w=\varphi_0$]]></tex-math></inline-formula>. We note that Eq. (<xref ref-type="disp-formula" rid="ptx149-M5-4">5.4</xref>) is obtained from Eq. (<xref ref-type="disp-formula" rid="ptx149-M2-3">2.3</xref>) by replacing <inline-formula><tex-math notation="LaTeX" id="ImEquation175"><![CDATA[$\partial_{\mu}$]]></tex-math></inline-formula> to <inline-formula><tex-math notation="LaTeX" id="ImEquation176"><![CDATA[$D_{\mu}(b)$]]></tex-math></inline-formula>. As we explained in <xref ref-type="sec" rid="SEC4">Sect. 4</xref>, the VEV <inline-formula><tex-math notation="LaTeX" id="ImEquation177"><![CDATA[$g\langle \varphi^A\rangle=v\delta^{A3}$]]></tex-math></inline-formula> selects the unbroken U(1) direction, and the Abelian monopole <inline-formula><tex-math notation="LaTeX" id="ImEquation178"><![CDATA[$b_{\mu}^A=\tilde{C}_{\mu}\delta^{A3}$]]></tex-math></inline-formula> is included in the Lagrangian consistently.</p>
<p>Next we study mass terms. Without <inline-formula><tex-math notation="LaTeX" id="ImEquation179"><![CDATA[$b_{\mu}$]]></tex-math></inline-formula>, a ghost loop brings about the tachyonic gluon mass term (<xref ref-type="disp-formula" rid="ptx149-M3-1">3.1</xref>). We show that Eq. (<xref ref-type="disp-formula" rid="ptx149-M3-1">3.1</xref>) is obtained even if <inline-formula><tex-math notation="LaTeX" id="ImEquation180"><![CDATA[$b_{\mu}$]]></tex-math></inline-formula> exists. To show this, we introduce the background gauge transformation
<disp-formula id="ptx149-M5-5"><label>(5.5)</label><tex-math notation="LaTeX" id="Equation37"><![CDATA[
\begin{equation}
\delta b_{\mu} = D_{\mu}(b) \varepsilon, \quad \delta a_{\mu} = g a_{\mu} \times \varepsilon, \quad
\delta \tilde{\varphi} =g \tilde{\varphi} \times \varepsilon, \label{505}
\end{equation}
]]></tex-math></disp-formula>
which satisfies the transformation (<xref ref-type="disp-formula" rid="ptx149-M5-1">5.1</xref>). When <inline-formula><tex-math notation="LaTeX" id="ImEquation181"><![CDATA[$v=0$]]></tex-math></inline-formula>, the Lagrangian <inline-formula><tex-math notation="LaTeX" id="ImEquation182"><![CDATA[$\mathcal{L}_\mathrm{inv}(b+a)$]]></tex-math></inline-formula> and <inline-formula><tex-math notation="LaTeX" id="ImEquation183"><![CDATA[$\tilde{\mathcal{L}}_{\varphi}(a,b)$]]></tex-math></inline-formula> in Eq. (<xref ref-type="disp-formula" rid="ptx149-M5-4">5.4</xref>) are invariant under the transformation (<xref ref-type="disp-formula" rid="ptx149-M5-5">5.5</xref>), if <inline-formula><tex-math notation="LaTeX" id="ImEquation184"><![CDATA[$\bar{c}^A$]]></tex-math></inline-formula>, <inline-formula><tex-math notation="LaTeX" id="ImEquation185"><![CDATA[$c^A$]]></tex-math></inline-formula>, and <inline-formula><tex-math notation="LaTeX" id="ImEquation186"><![CDATA[$B^A$]]></tex-math></inline-formula> transform in the adjoint representation. When <inline-formula><tex-math notation="LaTeX" id="ImEquation187"><![CDATA[$v\delta^{A3}\neq 0$]]></tex-math></inline-formula>, the ghost determinant
<disp-formula id="ptx149-M5-6"><label>(5.6)</label><tex-math notation="LaTeX" id="Equation38"><![CDATA[
\begin{equation}
\int DcD\bar{c} \exp[-\int dx i\bar{c} \cdot(D_{\mu}(b)D_{\mu}(b+a)+v \times )c ]
= \det [D_{\mu}(b)D_{\mu}(b+a)+v\times ] \label{506}
\end{equation}
]]></tex-math></disp-formula>
breaks the symmetry (<xref ref-type="disp-formula" rid="ptx149-M5-5">5.5</xref>). However, if we restrict Eq. (<xref ref-type="disp-formula" rid="ptx149-M5-5">5.5</xref>) to the U(1) transformation
<disp-formula id="ptx149-UM12"><tex-math notation="LaTeX" id="Equation39"><![CDATA[
\[ \delta b_{\mu}=-\frac{1}{g}\partial_{\mu}\varepsilon , \quad \delta
a_{\mu}^A=-\varepsilon f_{A3B}a_{\mu}^B,\quad|\varepsilon|\ll 1, \]
]]></tex-math></disp-formula>
the determinant (<xref ref-type="disp-formula" rid="ptx149-M5-6">5.6</xref>) is invariant. As tachyonic mass terms come from Eq. (<xref ref-type="disp-formula" rid="ptx149-M5-6">5.6</xref>), they must respect this U(1) symmetry. So the terms <inline-formula><tex-math notation="LaTeX" id="ImEquation188"><![CDATA[$b_{\mu}^2$]]></tex-math></inline-formula> and <inline-formula><tex-math notation="LaTeX" id="ImEquation189"><![CDATA[$b_{\mu}a_{\mu}^3$]]></tex-math></inline-formula> are forbidden, and the terms <inline-formula><tex-math notation="LaTeX" id="ImEquation190"><![CDATA[$-L_1^2(a_{\mu}^a)^2$]]></tex-math></inline-formula> and <inline-formula><tex-math notation="LaTeX" id="ImEquation191"><![CDATA[$-L_2^2(a_{\mu}^3)^2$]]></tex-math></inline-formula> are allowed. We calculate the determinant (<xref ref-type="disp-formula" rid="ptx149-M5-6">5.6</xref>) in <xref ref-type="sec" rid="SECB">Appendix B</xref>, and obtain the tachyonic mass term
<disp-formula id="ptx149-M5-7"><label>(5.7)</label><tex-math notation="LaTeX" id="Equation40"><![CDATA[
\begin{equation}
-m_4^2 [a_{\mu}^+a_{\mu}^- + (a_{\mu}^3)^2] \label{507}
\end{equation}
]]></tex-math></disp-formula>
as expected.</p>
<p>Finally, to remove the tachyonic mass, the procedure in <xref ref-type="sec" rid="SEC3.2">Sect. 3.2</xref> is applied. We replace <inline-formula><tex-math notation="LaTeX" id="ImEquation192"><![CDATA[$a_{\mu}^+a_{\mu}^-$]]></tex-math></inline-formula> with <inline-formula><tex-math notation="LaTeX" id="ImEquation193"><![CDATA[$\Phi_4 + a_{\mu}^+a_{\mu}^-$]]></tex-math></inline-formula>, where <inline-formula><tex-math notation="LaTeX" id="ImEquation194"><![CDATA[$\Phi_4=\langle a_{\mu}^+a_{\mu}^- \rangle$]]></tex-math></inline-formula>, and add the source term <inline-formula><tex-math notation="LaTeX" id="ImEquation195"><![CDATA[$M_4^2a_{\mu}^+a_{\mu}^-$]]></tex-math></inline-formula>. As <inline-formula><tex-math notation="LaTeX" id="ImEquation196"><![CDATA[$\mathcal{L}_\mathrm{inv}(b+a)$]]></tex-math></inline-formula> contains the term
<disp-formula id="ptx149-M5-8"><label>(5.8)</label><tex-math notation="LaTeX" id="Equation41"><![CDATA[
\begin{align}
\frac{g^2}{4}\{f_{ABC}(b+a)_{\mu}^B(b+a)_{\nu}^C\}^2&=
\frac{g^2}{2}(a_{\mu}^+a_{\mu}^-)^2
+g^2(a_{\mu}^+a_{\mu}^-)\{(b_{\nu}^3+a_{\nu}^3)^2\} \nonumber \\
&\quad{} - \frac{g^2}{2}(a_{\mu}^+)^2(a_{\nu}^-)^2
-g^2\{a_{\mu}^+(b_{\mu}^3+a_{\mu}^3)\}\{a_{\nu}^-(b_{\nu}^3+a_{\nu}^3)\}\!, \label{508}
\end{align}
]]></tex-math></disp-formula></p>
<p>Eqs. (<xref ref-type="disp-formula" rid="ptx149-M5-7">5.7</xref>) and (<xref ref-type="disp-formula" rid="ptx149-M5-8">5.8</xref>) lead to
<disp-formula id="ptx149-M5-9"><label>(5.9)</label><tex-math notation="LaTeX" id="Equation42"><![CDATA[
\begin{equation}
V(\Phi_4) + (g^2\Phi_4 -m_4^2)\{a_{\mu}^+a_{\mu}^- + (a_{\mu}^3)^2\} +M_4^2a_{\mu}^+a_{\mu}^-
+g^2\Phi_4\{2b_{\mu}^3a_{\mu}^3 + (b_{\mu}^3)^2\}\!. \label{509}
\end{equation}
]]></tex-math></disp-formula></p>
<p>As <inline-formula><tex-math notation="LaTeX" id="ImEquation197"><![CDATA[$V(\Phi_4)$]]></tex-math></inline-formula> takes the minimum value at <inline-formula><tex-math notation="LaTeX" id="ImEquation198"><![CDATA[$g^2\Phi_4=m_4^2$]]></tex-math></inline-formula>, Eq. (<xref ref-type="disp-formula" rid="ptx149-M5-9">5.9</xref>) becomes
<disp-formula id="ptx149-UM13"><tex-math notation="LaTeX" id="Equation43"><![CDATA[
\[
M_4^2a_{\mu}^+a_{\mu}^- + m_4^2\{2b_{\mu}^3a_{\mu}^3 + (b_{\mu}^3)^2\} .
\]
]]></tex-math></disp-formula></p>
<p>Namely, the magnetic potential <inline-formula><tex-math notation="LaTeX" id="ImEquation199"><![CDATA[$\tilde{C}_{\mu}$]]></tex-math></inline-formula> has the mass term (<xref ref-type="disp-formula" rid="ptx149-M4-3">4.3</xref>).</p>
<p>Except for string singularity, the magnetic potential <inline-formula><tex-math notation="LaTeX" id="ImEquation200"><![CDATA[$\tilde{C}_{\mu}$]]></tex-math></inline-formula> must be modified to satisfy the massive equation of motion<xref ref-type="fn" rid="FN4"><sup>4</sup></xref>
<disp-formula id="ptx149-M5-10"><label>(5.10)</label><tex-math notation="LaTeX" id="Equation44"><![CDATA[
\begin{equation}
\left(\frac{\delta \mathcal{L}}{\delta \tilde{C}_{\mu}}-\partial_{\nu}\frac{\delta \mathcal{L}}{\delta
\partial_{\nu}\tilde{C}_{\mu}}\right)_{a_{\rho}^A=0} = \partial_{\nu}^2
\tilde{C}_{\mu}-\partial_{\mu}\partial_{\nu}\tilde{C}_{\nu}-2m_4^2\tilde{C}_{\nu}=0. \label{510}
\end{equation}
]]></tex-math></disp-formula></p>
<p>Then the term linear with respect to <inline-formula><tex-math notation="LaTeX" id="ImEquation201"><![CDATA[$a_{\mu}^A$]]></tex-math></inline-formula>
<disp-formula id="ptx149-UM14"><tex-math notation="LaTeX" id="Equation45"><![CDATA[
\[
a_{\mu}^3\left(\frac{\delta \mathcal{L}}{\delta \tilde{C}_{\mu}}-\partial_{\nu}\frac{\delta
\mathcal{L}}{\delta \partial_{\nu}\tilde{C}_{\mu}}\right)_{a_{\rho}^A=0}
\]
]]></tex-math></disp-formula>
vanishes. Thus the final Lagrangian with massive magnetic potential becomes
<disp-formula id="ptx149-M5-11"><label>(5.11)</label><tex-math notation="LaTeX" id="Equation46"><![CDATA[
\begin{equation}
\frac{1}{4}\left(\partial_{\mu}\tilde{C}_{\nu}-\partial_{\nu}\tilde{C}_{\mu}\right)^2 +m_4^2\tilde{C}_{\mu}\tilde{C}_{\mu}
+ \mathcal{L}_\mathrm{inv}(a)+ M_4^2a_{\mu}^+a_{\mu}^- + \cdots, \label{511}
\end{equation}
]]></tex-math></disp-formula>
where interaction terms with <inline-formula><tex-math notation="LaTeX" id="ImEquation202"><![CDATA[$a_{\mu}^A$]]></tex-math></inline-formula> and <inline-formula><tex-math notation="LaTeX" id="ImEquation203"><![CDATA[$\tilde{C}_{\mu}$]]></tex-math></inline-formula> are neglected.</p>
</sec>
<sec id="SEC6"><title>6. Massive non-Abelian magnetic potential</title>
<p>The magnetic potential <inline-formula><tex-math notation="LaTeX" id="ImEquation204"><![CDATA[$\tilde{C}_{\mu}$]]></tex-math></inline-formula> has string singularity. We remove it by a singular gauge transformation [<xref ref-type="bibr" rid="B14">14</xref>]. In this section, we use the matrix notation <inline-formula><tex-math notation="LaTeX" id="ImEquation205"><![CDATA[$D_{\mu}(b)=\partial_{\mu} -ig b_{\mu}^AT_A$]]></tex-math></inline-formula> with <inline-formula><tex-math notation="LaTeX" id="ImEquation206"><![CDATA[$(T_A)_{BC}=if_{BAC}$]]></tex-math></inline-formula>. We perform a singular gauge transformation for <inline-formula><tex-math notation="LaTeX" id="ImEquation207"><![CDATA[$A^A_{\mu}=b^A_{\mu}+a^A_{\mu}$]]></tex-math></inline-formula> and <inline-formula><tex-math notation="LaTeX" id="ImEquation208"><![CDATA[$\varphi^A=\varphi_0 \delta^{A3}+\tilde{\varphi}^A$]]></tex-math></inline-formula> as
<disp-formula id="ptx149-M6-1"><label>(6.1)</label><tex-math notation="LaTeX" id="Equation47"><![CDATA[
\begin{equation}
A'^A_{\mu}T_A= U^{\dagger}A^A_{\mu}T_AU + \frac{i}{g}U^{\dagger}\partial_{\mu}U\ ,\quad
\varphi'^AT_A = U^{\dagger}(\varphi_0 \delta^{A3}+\tilde{\varphi}^A)T_AU. \label{601}
\end{equation}
]]></tex-math></disp-formula></p>
<p>The matrix <inline-formula><tex-math notation="LaTeX" id="ImEquation209"><![CDATA[$U$]]></tex-math></inline-formula>, which corresponds to the monopole <inline-formula><tex-math notation="LaTeX" id="ImEquation210"><![CDATA[$\tilde{C}_{\mu}$]]></tex-math></inline-formula> in Eq. (<xref ref-type="disp-formula" rid="ptx149-M4-1">4.1</xref>), is <inline-formula><tex-math notation="LaTeX" id="ImEquation211"><![CDATA[$U=e^{-in\phi T_3}e^{i\theta T_2}e^{in\phi T_3}$]]></tex-math></inline-formula>. As we explain in <xref ref-type="sec" rid="SECC">Appendix C</xref>, using this matrix <inline-formula><tex-math notation="LaTeX" id="ImEquation212"><![CDATA[$U$]]></tex-math></inline-formula> and the monopole solution <inline-formula><tex-math notation="LaTeX" id="ImEquation213"><![CDATA[$b^A_{\mu}T_A=\tilde{C}_{\mu}T_3$]]></tex-math></inline-formula>, Eq. (<xref ref-type="disp-formula" rid="ptx149-M6-1">6.1</xref>) becomes
<disp-formula id="ptx149-M6-2"><label>(6.2)</label><tex-math notation="LaTeX" id="Equation48"><![CDATA[
\begin{equation}
A'^A_{\mu}T_A= \left[a^1_{\mu}\hat{n}^A_1 +a^2_{\mu}\hat{n}^A_2+a^3_{\mu}\hat{n}^A
-\frac{1}{g}(\hat{n}\times \partial_{\mu}\hat{n})^A \right]T_A \label{602}
\end{equation}
]]></tex-math></disp-formula>
and
<disp-formula id="ptx149-M6-3"><label>(6.3)</label><tex-math notation="LaTeX" id="Equation49"><![CDATA[
\begin{equation}
\varphi'^AT_A= \left(\varphi_0\hat{n}^A + \tilde{\varphi}^B\hat{n}_B^A \right)T_A, \label{603}
\end{equation}
]]></tex-math></disp-formula>
where <inline-formula><tex-math notation="LaTeX" id="ImEquation214"><![CDATA[$\hat{n}_1, \hat{n}_2$]]></tex-math></inline-formula>, and <inline-formula><tex-math notation="LaTeX" id="ImEquation215"><![CDATA[$\hat{n}_3=\hat{n}$]]></tex-math></inline-formula> are defined in Eq. (<xref ref-type="disp-formula" rid="ptx149-MC-2">C.2</xref>) with <inline-formula><tex-math notation="LaTeX" id="ImEquation216"><![CDATA[$\alpha=\theta$]]></tex-math></inline-formula> and <inline-formula><tex-math notation="LaTeX" id="ImEquation217"><![CDATA[$\beta= -\gamma= n\phi$]]></tex-math></inline-formula>. We note that the right-hand side of Eq. (<xref ref-type="disp-formula" rid="ptx149-M6-2">6.2</xref>) is the gauge field decomposition by Cho [<xref ref-type="bibr" rid="B6">6</xref>], and Eq. (<xref ref-type="disp-formula" rid="ptx149-M6-3">6.3</xref>) shows that the color vector <inline-formula><tex-math notation="LaTeX" id="ImEquation218"><![CDATA[$\hat{n}^A$]]></tex-math></inline-formula> comes from the VEV <inline-formula><tex-math notation="LaTeX" id="ImEquation219"><![CDATA[$\varphi_0\delta^{A3}$]]></tex-math></inline-formula>.</p>
<p>Now we regard the transformation (<xref ref-type="disp-formula" rid="ptx149-M6-1">6.1</xref>) as the background gauge transformation. The classical field has the inhomogeneous part as
<disp-formula id="ptx149-M6-4"><label>(6.4)</label><tex-math notation="LaTeX" id="Equation50"><![CDATA[
\begin{equation}
b'_{\mu}=U^{\dagger}b_{\mu}U+\frac{i}{g}U^{\dagger}\partial_{\mu}U, \quad
a_{\mu}'=U^{\dagger}a_{\mu}U. \label{604}
\end{equation}
]]></tex-math></disp-formula></p>
<p>Then, as we show in <xref ref-type="sec" rid="SECC">Appendix C</xref>, Eqs. (<xref ref-type="disp-formula" rid="ptx149-M6-2">6.2</xref>) and (<xref ref-type="disp-formula" rid="ptx149-M6-4">6.4</xref>) indicate that the background gauge transformation is realized simply by the replacement
<disp-formula id="ptx149-M6-5"><label>(6.5)</label><tex-math notation="LaTeX" id="Equation51"><![CDATA[
\begin{equation}
a_{\mu}^A \to a_{\mu}^B\hat{n}_B^A, \quad
\tilde{C}_{\mu}\delta^{3A} \to C_{\mu}^A=-\frac{1}{g}(\hat{n}\times
\partial_{\mu}\hat{n})^A . \label{605}
\end{equation}
]]></tex-math></disp-formula></p>
<p>We call <inline-formula><tex-math notation="LaTeX" id="ImEquation220"><![CDATA[$C_{\mu}^A$]]></tex-math></inline-formula> a non-Abelian magnetic potential. Let us give an example. If we choose <inline-formula><tex-math notation="LaTeX" id="ImEquation221"><![CDATA[$n=1$]]></tex-math></inline-formula>, <inline-formula><tex-math notation="LaTeX" id="ImEquation222"><![CDATA[$\hat{n}$]]></tex-math></inline-formula> and <inline-formula><tex-math notation="LaTeX" id="ImEquation223"><![CDATA[$C_{\mu}^A$]]></tex-math></inline-formula> become
<disp-formula id="ptx149-UM15"><tex-math notation="LaTeX" id="Equation52"><![CDATA[
\[ \hat{n}=\left(
\begin{array}{c}
\sin \theta \cos \phi \\
\sin \theta \sin \phi \\
\cos \theta
\end{array}
\right), \quad
C_{\mu}^A=\epsilon_{A\mu k}\frac{x^k}{gr^2}.
\]
]]></tex-math></disp-formula></p>
<p>Although this configuration found by Wu and Yang [<xref ref-type="bibr" rid="B17">17</xref>] is singular at the origin, it has no string.</p>
<p>Applying Eq. (<xref ref-type="disp-formula" rid="ptx149-M6-5">6.5</xref>) to the Lagrangian <inline-formula><tex-math notation="LaTeX" id="ImEquation224"><![CDATA[$\mathcal{L}_\mathrm{inv}(b+a)$]]></tex-math></inline-formula> in Eq. (<xref ref-type="disp-formula" rid="ptx149-M5-3">5.3</xref>), we obtain
<disp-formula id="ptx149-M6-6"><label>(6.6)</label><tex-math notation="LaTeX" id="Equation53"><![CDATA[
\begin{align}
\mathcal{L}_\mathrm{inv}=& \frac{1}{4}(F_{\mu\nu}+H_{\mu\nu})^2 +\frac{1}{4}(\hat{D}_{\mu}X_{\nu}-\hat{D}_{\nu}X_{\mu})^2 \nonumber\\
&+\frac{g}{2}(F_{\mu\nu}+H_{\mu\nu})\hat{n}\cdot (X_{\mu}\times X_{\nu})+\frac{g^2}{4}(X_{\mu}\times X_{\nu})^2, \label{606}
\end{align}
]]></tex-math></disp-formula>
where the following notation in Ref. [<xref ref-type="bibr" rid="B6">6</xref>] has been used:
<disp-formula id="ptx149-M6-7"><label>(6.7)</label><tex-math notation="LaTeX" id="Equation54"><![CDATA[
\begin{align}
\hat{A}^A_{\mu}&=a^3_{\mu}\hat{n}^A + C_{\mu}^A, \quad X^A_{\mu}=a^1_{\mu}\hat{n}^A_1 +a^2_{\mu}\hat{n}^A_2, \nonumber \\
\hat{D}_{\mu}&= \partial_{\mu} +g\hat{A}_{\mu}\times ,\quad F_{\mu\nu}=\partial_{\mu}a^3_{\nu}-\partial_{\nu}a^3_{\mu}, \nonumber \\
H_{\mu\nu}\hat{n}^A&=\partial{\mu}C_{\nu}^A-\partial_{\nu}C_{\mu}^A+g(C_{\mu}\times C_{\nu})^A
=-\frac{1}{g}(\partial_{\mu}\hat{n}\times \partial_{\nu}\hat{n})^A. \label{607}
\end{align}
]]></tex-math></disp-formula></p>
<p>Equation (<xref ref-type="disp-formula" rid="ptx149-M6-6">6.6</xref>) is the Lagrangian of the extended QCD [<xref ref-type="bibr" rid="B6">6</xref>]. Next we apply the transformation (<xref ref-type="disp-formula" rid="ptx149-M6-5">6.5</xref>) to <inline-formula><tex-math notation="LaTeX" id="ImEquation225"><![CDATA[$\tilde{\mathcal{L}}_{\varphi}(a,b)$]]></tex-math></inline-formula> in Eq. (<xref ref-type="disp-formula" rid="ptx149-M5-4">5.4</xref>) as well. However, as <inline-formula><tex-math notation="LaTeX" id="ImEquation226"><![CDATA[$\hat{n}_B\cdot\hat{n}_C=\delta_{BC}$]]></tex-math></inline-formula>, the tachyonic mass term (<xref ref-type="disp-formula" rid="ptx149-M5-7">5.7</xref>) is obtained again. Replacing <inline-formula><tex-math notation="LaTeX" id="ImEquation227"><![CDATA[$a_{\mu}^+a_{\mu}^-$]]></tex-math></inline-formula> with <inline-formula><tex-math notation="LaTeX" id="ImEquation228"><![CDATA[$a_{\mu}^+a_{\mu}^- + \Phi_4$]]></tex-math></inline-formula>, and adding the source term <inline-formula><tex-math notation="LaTeX" id="ImEquation229"><![CDATA[$M_4^2a_{\mu}^+a_{\mu}^-$]]></tex-math></inline-formula>, the part that depends on <inline-formula><tex-math notation="LaTeX" id="ImEquation230"><![CDATA[$\Phi_4, m_4^2$]]></tex-math></inline-formula>, or <inline-formula><tex-math notation="LaTeX" id="ImEquation231"><![CDATA[$M_4^2$]]></tex-math></inline-formula> becomes
<disp-formula id="ptx149-M6-8"><label>(6.8)</label><tex-math notation="LaTeX" id="Equation55"><![CDATA[
\begin{equation}
V(\Phi_4) + (g^2\Phi_4 -m_4^2)[a_{\mu}^+a_{\mu}^- + (a_{\mu}^3)^2] + M_4^2a_{\mu}^+a_{\mu}^-
+g^2\Phi_4[2C_{\mu}^Aa_{\mu}^3\hat{n}^A + (C_{\mu}^A)^2]. \label{608}
\end{equation}
]]></tex-math></disp-formula></p>
<p>Equation (<xref ref-type="disp-formula" rid="ptx149-M6-8">6.8</xref>) is derived directly by applying the transformation (<xref ref-type="disp-formula" rid="ptx149-M6-5">6.5</xref>) to Eq. (<xref ref-type="disp-formula" rid="ptx149-M5-9">5.9</xref>). However, there is a difference between Eqs. (<xref ref-type="disp-formula" rid="ptx149-M5-9">5.9</xref>) and (<xref ref-type="disp-formula" rid="ptx149-M6-8">6.8</xref>). Since <inline-formula><tex-math notation="LaTeX" id="ImEquation232"><![CDATA[$C_{\mu}^A\hat{n}^A=0$]]></tex-math></inline-formula>, the cross-term <inline-formula><tex-math notation="LaTeX" id="ImEquation233"><![CDATA[$g^2\Phi_4[2C_{\mu}^Aa_{\mu}^3\hat{n}^A]$]]></tex-math></inline-formula> vanishes without using the equation of motion for <inline-formula><tex-math notation="LaTeX" id="ImEquation234"><![CDATA[$C_{\mu}^A$]]></tex-math></inline-formula>. Now we set <inline-formula><tex-math notation="LaTeX" id="ImEquation235"><![CDATA[$g^2\Phi_4=m_4^2$]]></tex-math></inline-formula>. Then, from Eqs. (<xref ref-type="disp-formula" rid="ptx149-M6-6">6.6</xref>) and (<xref ref-type="disp-formula" rid="ptx149-M6-8">6.8</xref>), we obtain the Lagrangian
<disp-formula id="ptx149-M6-9"><label>(6.9)</label><tex-math notation="LaTeX" id="Equation56"><![CDATA[
\begin{equation}
\frac{1}{4}(F_{\mu\nu}+H_{\mu\nu})^2 + m_4^2 (C_{\mu}^A)^2
+\frac{1}{4}(\hat{D}_{\mu}X_{\nu}-\hat{D}_{\nu}X_{\mu})^2 +
\frac{M_4^2}{2}(X_{\mu}^A)^2 + \cdots, \label{609}
\end{equation}
]]></tex-math></disp-formula>
where <inline-formula><tex-math notation="LaTeX" id="ImEquation236"><![CDATA[$2a_{\mu}^+a_{\mu}^-=(X_{\mu}^A)^2$]]></tex-math></inline-formula> has been used. Equation (<xref ref-type="disp-formula" rid="ptx149-M6-9">6.9</xref>) is the extended QCD with the massive non-Abelian magnetic potential and the massive off-diagonal gluons.</p>
<p>We make a comment. Neglecting the quantum fields, the Lagrangian (<xref ref-type="disp-formula" rid="ptx149-M6-9">6.9</xref>) becomes
<disp-formula id="ptx149-M6-10"><label>(6.10)</label><tex-math notation="LaTeX" id="Equation57"><![CDATA[
\begin{equation}
\mathcal{L}_\mathrm{SF}=\frac{1}{4}H_{\mu\nu}^2+m_4^2(C_{\mu}^A)^2=\frac{1}{4g^2}(\partial_{\mu}\hat{n}\times
\partial_{\mu}\hat{n})^2 +\frac{m_4^2}{g^2}(\partial_{\mu}\hat{n})^2. \label{610}
\end{equation}
]]></tex-math></disp-formula></p>
<p>This is the Skyrme&#x2013;Faddeev Lagrangian [<xref ref-type="bibr" rid="B18">18</xref>]. The equation of motion for <inline-formula><tex-math notation="LaTeX" id="ImEquation237"><![CDATA[$\hat{n}$]]></tex-math></inline-formula> comes from
<disp-formula id="ptx149-UM16"><tex-math notation="LaTeX" id="Equation58"><![CDATA[
\[ Q^A(\hat{n})\delta \hat{n}^A=0,\quad
Q^A(\hat{n})=\left( \frac{\delta \mathcal{L}_\mathrm{SF}}{\delta
\hat{n}^A}-\partial_{\mu}\frac{\delta \mathcal{L}_\mathrm{SF}}{\delta \partial_{\mu}\hat{n}^A}
\right)\!. \]
]]></tex-math></disp-formula></p>
<p>As <inline-formula><tex-math notation="LaTeX" id="ImEquation238"><![CDATA[$\delta \hat{n}^A$]]></tex-math></inline-formula> satisfies <inline-formula><tex-math notation="LaTeX" id="ImEquation239"><![CDATA[$\hat{n}\cdot \delta \hat{n}=0$]]></tex-math></inline-formula>, this equation means that the component of <inline-formula><tex-math notation="LaTeX" id="ImEquation240"><![CDATA[$Q^A(\hat{n})$]]></tex-math></inline-formula> that is perpendicular to <inline-formula><tex-math notation="LaTeX" id="ImEquation241"><![CDATA[$\hat{n}^A$]]></tex-math></inline-formula> vanishes. So, from Eq. (<xref ref-type="disp-formula" rid="ptx149-M6-10">6.10</xref>), we obtain
<disp-formula id="ptx149-M6-11"><label>(6.11)</label><tex-math notation="LaTeX" id="Equation59"><![CDATA[
\begin{equation}
Q^A(\hat{n})= \frac{1}{g^2}\partial_{\mu}[\partial_{\nu}\hat{n}\times
(\partial_{\mu}\hat{n}\times \partial_{\nu}\hat{n})]^A
+\frac{m_4^2}{g^2}\partial_{\mu}^2\hat{n}^A, \label{611}
\end{equation}
]]></tex-math></disp-formula>
and the perpendicular component gives [<xref ref-type="bibr" rid="B6">6</xref>]
<disp-formula id="ptx149-M6-12"><label>(6.12)</label><tex-math notation="LaTeX" id="Equation60"><![CDATA[
\begin{equation}
-\frac{1}{g}\partial_{\mu}(H_{\mu\nu})\partial_{\nu}\hat{n}+\frac{m_4^2}{g^2}\hat{n}\times \partial_{\mu}^2\hat{n} =0. \label{612}
\end{equation}
]]></tex-math></disp-formula></p>
<p>Now we give an example. The color vector <inline-formula><tex-math notation="LaTeX" id="ImEquation242"><![CDATA[$\hat{n}$]]></tex-math></inline-formula> in Eq. (<xref ref-type="disp-formula" rid="ptx149-MC-7">C.7</xref>) satisfies <inline-formula><tex-math notation="LaTeX" id="ImEquation243"><![CDATA[$\partial_{\mu}(H_{\mu\nu})=0$]]></tex-math></inline-formula>. When <inline-formula><tex-math notation="LaTeX" id="ImEquation244"><![CDATA[$m_4^2\neq 0$]]></tex-math></inline-formula>, it must be modified to satisfy Eq. (<xref ref-type="disp-formula" rid="ptx149-M6-12">6.12</xref>). However, we find that it satisfies
<disp-formula id="ptx149-UM17"><tex-math notation="LaTeX" id="Equation61"><![CDATA[
\[
\partial_{\mu}^2\hat{n}=-\frac{2}{r^2}\hat{n}+\frac{1-n^2}{r^2\sin\theta}\left(
\begin{array}{c}
\cos n\phi \\
\sin n\phi \\
0
\end{array}
\right).
\]
]]></tex-math></disp-formula></p>
<p>So, if we choose <inline-formula><tex-math notation="LaTeX" id="ImEquation245"><![CDATA[$n=\pm 1$]]></tex-math></inline-formula>, the equations
<disp-formula id="ptx149-UM18"><tex-math notation="LaTeX" id="Equation62"><![CDATA[
\[ \partial_{\mu}(H_{\mu\nu})=0,\quad \hat{n}\times \partial_{\mu}^2\hat{n}=0 \]
]]></tex-math></disp-formula>
hold, and Eq. (<xref ref-type="disp-formula" rid="ptx149-M6-12">6.12</xref>) is fulfilled. As <inline-formula><tex-math notation="LaTeX" id="ImEquation246"><![CDATA[$\int F_{\mu\nu}H_{\mu\nu} dx = -2\int a_{\nu}^3\partial_{\mu}(H_{\mu\nu}) dx=0$]]></tex-math></inline-formula>, Eq. (<xref ref-type="disp-formula" rid="ptx149-M6-9">6.9</xref>) becomes
<disp-formula id="ptx149-UM19"><tex-math notation="LaTeX" id="Equation63"><![CDATA[
\[ \frac{1}{4}H_{\mu\nu}^2 + m_4^2 (C_{\mu}^A)^2 + \frac{1}{4}F_{\mu\nu}^2
+\frac{1}{4}(\hat{D}_{\mu}X_{\nu}-\hat{D}_{\nu}X_{\mu})^2 + \frac{M_4^2}{2}(X_{\mu}^A)^2 + \cdots. \]
]]></tex-math></disp-formula></p>
</sec>
<sec id="SEC7"><title>7. Comment on the <inline-formula><tex-math notation="LaTeX" id="ImEquation247"><![CDATA[$\boldsymbol{D=3}$]]></tex-math></inline-formula> case</title>
<p>In <inline-formula><tex-math notation="LaTeX" id="ImEquation248"><![CDATA[$D=3$]]></tex-math></inline-formula>, ghost condensation happens as well. From Eq. (<xref ref-type="disp-formula" rid="ptx149-M2-5">2.5</xref>), the tachyonic gluon mass term is
<disp-formula id="ptx149-UM20"><tex-math notation="LaTeX" id="Equation64"><![CDATA[
\[ -m_3^2 \left\{a_{\mu}^+a_{\mu}^- +\frac{\kappa_3}{2}(a_{\mu}^3)^2\right\},\quad
m_3^2 = \frac{\alpha_2}{24\pi^2}g_3^4=\frac{\sqrt{2v_3}g_3^2}{12\pi}, \quad \kappa_3=\frac{3}{2}. \]
]]></tex-math></disp-formula></p>
<p>As in <xref ref-type="sec" rid="SEC5">Sect. 5</xref>, we divide the gluon as <inline-formula><tex-math notation="LaTeX" id="ImEquation249"><![CDATA[$A_{\mu}^A=b_{\mu}^A+a_{\mu}^A$]]></tex-math></inline-formula>, add the source term <inline-formula><tex-math notation="LaTeX" id="ImEquation250"><![CDATA[$M_3^2 a_{\mu}^+a_{\mu}^-$]]></tex-math></inline-formula>, and introduce <inline-formula><tex-math notation="LaTeX" id="ImEquation251"><![CDATA[$\Phi_3$]]></tex-math></inline-formula> as
<disp-formula id="ptx149-UM21"><tex-math notation="LaTeX" id="Equation65"><![CDATA[
\[ a_{\mu}^+a_{\mu}^- \to \Phi_3 + a_{\mu}^+a_{\mu}^-, \quad \Phi_3=\langle a_{\mu}^+a_{\mu}^-\rangle. \]
]]></tex-math></disp-formula></p>
<p>The terms that contain <inline-formula><tex-math notation="LaTeX" id="ImEquation252"><![CDATA[$\Phi_3, m_3^2$]]></tex-math></inline-formula>, or <inline-formula><tex-math notation="LaTeX" id="ImEquation253"><![CDATA[$M_3^2$]]></tex-math></inline-formula> are
<disp-formula id="ptx149-M7-1"><label>(7.1)</label><tex-math notation="LaTeX" id="Equation66"><![CDATA[
\begin{equation}
V(\Phi_3) + (g_3^2\Phi_3 -m_3^2+M_3^2)a_{\mu}^+a_{\mu}^- + \left(g_3^2\Phi_3 -\frac{\kappa_3}{2} m_3^2\right)(a_{\mu}^3)^2
+g_3^2\Phi_3\{2b_{\mu}^3a_{\mu}^3 + (b_{\mu}^3)^2\}\!, \label{701}
\end{equation}
]]></tex-math></disp-formula>
where
<disp-formula id="ptx149-UM22"><tex-math notation="LaTeX" id="Equation67"><![CDATA[
\[
V(\Phi_3)=\frac{g_3^2}{2}\Phi_3^2 -m_3^2\Phi_3,\quad \Phi_3=\langle x|(-\Delta +M_3^2)^{-1}_{\mu\mu}|x \rangle.
\]
]]></tex-math></disp-formula></p>
<p>The minimum of <inline-formula><tex-math notation="LaTeX" id="ImEquation254"><![CDATA[$V(\Phi_3)$]]></tex-math></inline-formula> determines the VEV <inline-formula><tex-math notation="LaTeX" id="ImEquation255"><![CDATA[$\Phi_3$]]></tex-math></inline-formula> and the mass <inline-formula><tex-math notation="LaTeX" id="ImEquation256"><![CDATA[$M_3$]]></tex-math></inline-formula> as
<disp-formula id="ptx149-M7-2"><label>(7.2)</label><tex-math notation="LaTeX" id="Equation68"><![CDATA[
\begin{equation}
\Phi_3=\langle a_{\mu}^+a_{\mu}^- \rangle=\frac{m_3^2}{g_3^2}=\frac{\sqrt{2v_3}}{12\pi}, \quad
\frac{m_3^2}{g_3^2}=\langle x|(-\Delta +M_3^2)^{-1}_{\mu\mu}|x \rangle. \label{702}
\end{equation}
]]></tex-math></disp-formula></p>
<p>Substituting Eq. (<xref ref-type="disp-formula" rid="ptx149-M7-2">7.2</xref>) into Eq. (<xref ref-type="disp-formula" rid="ptx149-M7-1">7.1</xref>), we find the mass terms
<disp-formula id="ptx149-M7-3"><label>(7.3)</label><tex-math notation="LaTeX" id="Equation69"><![CDATA[
\begin{equation}
M_3^2a_{\mu}^+a_{\mu}^- + \frac{m_3^2}{4}(a_{\mu}^3)^2+ m_3^2\{2b_{\mu}^3a_{\mu}^3 + (b_{\mu}^3)^2\}\!. \label{703}
\end{equation}
]]></tex-math></disp-formula></p>
<p>Namely, the components <inline-formula><tex-math notation="LaTeX" id="ImEquation257"><![CDATA[$a_{\mu}^{\pm}$]]></tex-math></inline-formula> have the mass <inline-formula><tex-math notation="LaTeX" id="ImEquation258"><![CDATA[$M_3$]]></tex-math></inline-formula>, and the classical part <inline-formula><tex-math notation="LaTeX" id="ImEquation259"><![CDATA[$b_{\mu}^A$]]></tex-math></inline-formula> acquires the mass <inline-formula><tex-math notation="LaTeX" id="ImEquation260"><![CDATA[$\sqrt{2}m_3$]]></tex-math></inline-formula>. However, unlike the <inline-formula><tex-math notation="LaTeX" id="ImEquation261"><![CDATA[$D=4$]]></tex-math></inline-formula> case, the component <inline-formula><tex-math notation="LaTeX" id="ImEquation262"><![CDATA[$a_{\mu}^3$]]></tex-math></inline-formula> acquires the mass <inline-formula><tex-math notation="LaTeX" id="ImEquation263"><![CDATA[$m_3/\sqrt{2}=O(g_3^2)$]]></tex-math></inline-formula>. The value <inline-formula><tex-math notation="LaTeX" id="ImEquation264"><![CDATA[$\kappa_3=\frac{3}{2}\neq 2$]]></tex-math></inline-formula> is crucial.</p>
<p>As the gauge field in <inline-formula><tex-math notation="LaTeX" id="ImEquation265"><![CDATA[$D=3$]]></tex-math></inline-formula> (or <inline-formula><tex-math notation="LaTeX" id="ImEquation266"><![CDATA[$D=2+1$]]></tex-math></inline-formula>) is expected to have masses of this order (see, e.g., Refs. [<xref ref-type="bibr" rid="B19">19</xref>,<xref ref-type="bibr" rid="B20">20</xref>]). It is known that the <inline-formula><tex-math notation="LaTeX" id="ImEquation267"><![CDATA[$D=3+1$]]></tex-math></inline-formula> gauge theory at high temperature becomes the effective <inline-formula><tex-math notation="LaTeX" id="ImEquation268"><![CDATA[$D=3$]]></tex-math></inline-formula> gauge theory with the coupling constant <inline-formula><tex-math notation="LaTeX" id="ImEquation269"><![CDATA[$g_3=g\sqrt{T}$]]></tex-math></inline-formula> [<xref ref-type="bibr" rid="B21">21</xref>]. The mass of <inline-formula><tex-math notation="LaTeX" id="ImEquation270"><![CDATA[$O(g^2T)$]]></tex-math></inline-formula>, which is called the magnetic mass, is expected [<xref ref-type="bibr" rid="B22">22</xref>]. The mass terms <inline-formula><tex-math notation="LaTeX" id="ImEquation271"><![CDATA[$M_3^2a_{\mu}^+a_{\mu}^-$]]></tex-math></inline-formula> and <inline-formula><tex-math notation="LaTeX" id="ImEquation272"><![CDATA[$m_3^2(a_{\mu}^3)^2/4$]]></tex-math></inline-formula> may imply the existence of the magnetic mass at high <inline-formula><tex-math notation="LaTeX" id="ImEquation273"><![CDATA[$T$]]></tex-math></inline-formula>.</p>
</sec>
<sec id="SEC8"><title>8. Summary and comments</title>
<p>We have studied the SU(2) gauge theory in the nonlinear gauge. In 4D Euclidean space, the ghost condensation <inline-formula><tex-math notation="LaTeX" id="ImEquation274"><![CDATA[$\langle \varphi^A \rangle =\varphi_0\delta^{A3}\neq 0$]]></tex-math></inline-formula> happens under the scale <inline-formula><tex-math notation="LaTeX" id="ImEquation275"><![CDATA[$\mu_0$]]></tex-math></inline-formula>, and the ghost loop yields the tachyonic gluon mass term <inline-formula><tex-math notation="LaTeX" id="ImEquation276"><![CDATA[$-m_4^2\{A_{\mu}^+A_{\mu}^- + (A_{\mu}^3)^2\}$]]></tex-math></inline-formula>. We considered the effective potential for the LCO <inline-formula><tex-math notation="LaTeX" id="ImEquation277"><![CDATA[$A_{\mu}^+A_{\mu}^-$]]></tex-math></inline-formula> up to <inline-formula><tex-math notation="LaTeX" id="ImEquation278"><![CDATA[$O(\hslash^2)$]]></tex-math></inline-formula>, and showed that <inline-formula><tex-math notation="LaTeX" id="ImEquation279"><![CDATA[$g^2\langle A_{\mu}^+A_{\mu}^-\rangle=m_4^2$]]></tex-math></inline-formula> gives the minimum of the potential. The VEV <inline-formula><tex-math notation="LaTeX" id="ImEquation280"><![CDATA[$\Phi_4=\langle A_{\mu}^+A_{\mu}^-\rangle$]]></tex-math></inline-formula> makes the diagonal gluon <inline-formula><tex-math notation="LaTeX" id="ImEquation281"><![CDATA[$A_{\mu}^3$]]></tex-math></inline-formula> massless. In contrast, the off-diagonal gluons <inline-formula><tex-math notation="LaTeX" id="ImEquation282"><![CDATA[$A_{\mu}^{\pm}$]]></tex-math></inline-formula> acquire the mass <inline-formula><tex-math notation="LaTeX" id="ImEquation283"><![CDATA[$M_4$]]></tex-math></inline-formula> determined by Eq. (<xref ref-type="disp-formula" rid="ptx149-M3-10">3.10</xref>).</p>
<p>The field <inline-formula><tex-math notation="LaTeX" id="ImEquation284"><![CDATA[$\varphi^A$]]></tex-math></inline-formula> belongs to the adjoint representation of SU(2). Since the VEV <inline-formula><tex-math notation="LaTeX" id="ImEquation285"><![CDATA[$\varphi_0\delta^{A3}$]]></tex-math></inline-formula> selects the <inline-formula><tex-math notation="LaTeX" id="ImEquation286"><![CDATA[$A=3$]]></tex-math></inline-formula> direction, the Abelian monopole solution <inline-formula><tex-math notation="LaTeX" id="ImEquation287"><![CDATA[$\tilde{C}_{\mu}$]]></tex-math></inline-formula> can be introduced in this direction. Combining the VEV <inline-formula><tex-math notation="LaTeX" id="ImEquation288"><![CDATA[$\langle A_{\mu}^+A_{\mu}^-\rangle$]]></tex-math></inline-formula> and <inline-formula><tex-math notation="LaTeX" id="ImEquation289"><![CDATA[$\tilde{C}_{\mu}$]]></tex-math></inline-formula>, we find that the magnetic potential <inline-formula><tex-math notation="LaTeX" id="ImEquation290"><![CDATA[$\tilde{C}_{\mu}$]]></tex-math></inline-formula> becomes massive.</p>
<p>To remove the string singularity of the monopole solution <inline-formula><tex-math notation="LaTeX" id="ImEquation291"><![CDATA[$\tilde{C}_{\mu}$]]></tex-math></inline-formula>, we performed the singular gauge transformation in the background covariant gauge. As <inline-formula><tex-math notation="LaTeX" id="ImEquation292"><![CDATA[$\varphi_0\delta^{A3}$]]></tex-math></inline-formula> transforms into <inline-formula><tex-math notation="LaTeX" id="ImEquation293"><![CDATA[$\varphi_0 \hat{n}^A$]]></tex-math></inline-formula>, the field <inline-formula><tex-math notation="LaTeX" id="ImEquation294"><![CDATA[$\hat{n}^A$]]></tex-math></inline-formula> that specifies the color direction appears, and the extended QCD [<xref ref-type="bibr" rid="B6">6</xref>] is derived. In addition, the non-Abelian magnetic potential <inline-formula><tex-math notation="LaTeX" id="ImEquation295"><![CDATA[$C_{\mu}^A$]]></tex-math></inline-formula> transformed from <inline-formula><tex-math notation="LaTeX" id="ImEquation296"><![CDATA[$\tilde{C}_{\mu}\delta^{A3}$]]></tex-math></inline-formula> becomes massive. If quantum fields are neglected, the Skyrme&#x2013;Faddeev Lagrangian is obtained.</p>
<p>In 3D Euclidean space, phenomena similar to the <inline-formula><tex-math notation="LaTeX" id="ImEquation297"><![CDATA[$D=4$]]></tex-math></inline-formula> case happen. However, unlike the <inline-formula><tex-math notation="LaTeX" id="ImEquation298"><![CDATA[$D=4$]]></tex-math></inline-formula> case, the diagonal component <inline-formula><tex-math notation="LaTeX" id="ImEquation299"><![CDATA[$a_{\mu}^3$]]></tex-math></inline-formula> becomes massive.</p>
<p>We make some comments.</p>
<p><list list-type="simple">
<list-item><p>(1) In the maximally Abelian gauge, the lattice simulation shows that the off-diagonal gluons are massive and the diagonal gluons are nearly massless [<xref ref-type="bibr" rid="B23">23</xref>,<xref ref-type="bibr" rid="B24">24</xref>]. In the present model, the VEV <inline-formula><tex-math notation="LaTeX" id="ImEquation300"><![CDATA[$\varphi_0$]]></tex-math></inline-formula> breaks the global SU(2) symmetry to U(1), so the result that <inline-formula><tex-math notation="LaTeX" id="ImEquation301"><![CDATA[$A_{\mu}^{\pm}$]]></tex-math></inline-formula> and <inline-formula><tex-math notation="LaTeX" id="ImEquation302"><![CDATA[$A_{\mu}^3$]]></tex-math></inline-formula> have different masses may be reasonable. In addition, the masslessness of the component <inline-formula><tex-math notation="LaTeX" id="ImEquation303"><![CDATA[$A_{\mu}^3$]]></tex-math></inline-formula> may be related to the remaining U(1) symmetry.</p></list-item>
<list-item><p>(2) Since the magnetic potential <inline-formula><tex-math notation="LaTeX" id="ImEquation304"><![CDATA[$\tilde{C}_{\mu}$]]></tex-math></inline-formula> couples with the off-diagonal components <inline-formula><tex-math notation="LaTeX" id="ImEquation305"><![CDATA[$A_{\mu}^{\pm}$]]></tex-math></inline-formula>, <inline-formula><tex-math notation="LaTeX" id="ImEquation306"><![CDATA[$\tilde{C}_{\mu}$]]></tex-math></inline-formula> can become massive by the VEV <inline-formula><tex-math notation="LaTeX" id="ImEquation307"><![CDATA[$\langle A_{\mu}^+A_{\mu}^-\rangle$]]></tex-math></inline-formula>. Namely we can obtain a massive magnetic potential without monopole condensation.</p></list-item>
<list-item><p>(3) To show the quark confinement, Abelian dominance is often assumed [<xref ref-type="bibr" rid="B25">25</xref>,<xref ref-type="bibr" rid="B26">26</xref>]. In this assumption, the off-diagonal components <inline-formula><tex-math notation="LaTeX" id="ImEquation308"><![CDATA[$A_{\mu}^{\pm}$]]></tex-math></inline-formula> are neglected. Our result insists that these components play an important role in realizing the Abelian dominance.<xref ref-type="fn" rid="FN5"><sup>5</sup></xref></p></list-item>
<list-item><p>(4) In Ref. [<xref ref-type="bibr" rid="B27">27</xref>], based on the LCO formalism in Refs. [<xref ref-type="bibr" rid="B28">28</xref>,<xref ref-type="bibr" rid="B29">29</xref>], the LCO <inline-formula><tex-math notation="LaTeX" id="ImEquation309"><![CDATA[$(\bar{c}\times c)^A$]]></tex-math></inline-formula> is studied in the Landau gauge, together with the LCO <inline-formula><tex-math notation="LaTeX" id="ImEquation310"><![CDATA[$(A_{\mu}^A)^2=(A_{\mu}^a)^2+(A_{\mu}^3)^2$]]></tex-math></inline-formula>. This formalism introduces sources <inline-formula><tex-math notation="LaTeX" id="ImEquation311"><![CDATA[$\omega^A$]]></tex-math></inline-formula> and <inline-formula><tex-math notation="LaTeX" id="ImEquation312"><![CDATA[$J$]]></tex-math></inline-formula> for <inline-formula><tex-math notation="LaTeX" id="ImEquation313"><![CDATA[$\bar{c}\times c$]]></tex-math></inline-formula> and <inline-formula><tex-math notation="LaTeX" id="ImEquation314"><![CDATA[$(A_{\mu}^A)^2$]]></tex-math></inline-formula>, respectively, in a BRS-exact form. From the renormalizability, the terms <inline-formula><tex-math notation="LaTeX" id="ImEquation315"><![CDATA[$(\omega^A)^2$]]></tex-math></inline-formula> and <inline-formula><tex-math notation="LaTeX" id="ImEquation316"><![CDATA[$J^2$]]></tex-math></inline-formula> are necessary. To delete these terms, the Hubbard&#x2013;Stratonovich transformation is applied, and the fields <inline-formula><tex-math notation="LaTeX" id="ImEquation317"><![CDATA[$\phi^A$]]></tex-math></inline-formula> and <inline-formula><tex-math notation="LaTeX" id="ImEquation318"><![CDATA[$\sigma$]]></tex-math></inline-formula>, which correspond to <inline-formula><tex-math notation="LaTeX" id="ImEquation319"><![CDATA[$\bar{c}\times c$]]></tex-math></inline-formula> and <inline-formula><tex-math notation="LaTeX" id="ImEquation320"><![CDATA[$(A_{\mu}^A)^2$]]></tex-math></inline-formula>, respectively, are introduced. The final Lagrangian they used is <inline-formula><tex-math notation="LaTeX" id="ImEquation321"><![CDATA[$\mathcal{L}=\mathcal{L}_\mathrm{YM}+\mathcal{L}_\mathrm{GF}+\mathcal{L}_\mathrm{ext}$]]></tex-math></inline-formula>, where
<disp-formula id="ptx149-UM23"><tex-math notation="LaTeX" id="Equation70"><![CDATA[
\begin{align*}
\mathcal{L}_\mathrm{YM}&=\frac{1}{4}(F_{\mu\nu}^A)^2, \quad \mathcal{L}_\mathrm{GF}=B^A(\partial_{\mu}A_{\mu}^A), \\
\mathcal{L}_\mathrm{ext}&=\mathcal{L}_\mathrm{ext}(\phi) + \mathcal{L}_\mathrm{ext}(\sigma),\\
\mathcal{L}_\mathrm{ext}(\phi)&=\frac{(\phi^A)^2}{2g^2\rho}+\frac{1}{\rho}\phi^A(\bar{c}\times c)^A
+\frac{g^2}{2\rho}(\bar{c}\times c)^2 - \omega^A\frac{\phi^A}{g}, \\
\mathcal{L}_\mathrm{ext}(\sigma)&=\frac{\sigma}{2g^2\zeta}+\frac{\sigma}{2g\zeta}(A_{\mu}^A)^2
+\frac{1}{8\zeta}(A_{\mu}^AA_{\mu}^A)^2 - J\frac{\sigma}{g}.
\end{align*}
]]></tex-math></disp-formula></p>
<p>The one-loop effective potential <inline-formula><tex-math notation="LaTeX" id="ImEquation322"><![CDATA[$V(\phi)+V(\sigma)$]]></tex-math></inline-formula> was calculated by using the free propagators derived from <inline-formula><tex-math notation="LaTeX" id="ImEquation323"><![CDATA[$\mathcal{L}_\mathrm{YM}+\mathcal{L}_\mathrm{GF}$]]></tex-math></inline-formula> and the interactions in <inline-formula><tex-math notation="LaTeX" id="ImEquation324"><![CDATA[$\mathcal{L}_\mathrm{ext}$]]></tex-math></inline-formula>. Then the conditions <inline-formula><tex-math notation="LaTeX" id="ImEquation325"><![CDATA[$\frac{dV(\phi)}{d\phi}=0$]]></tex-math></inline-formula> and <inline-formula><tex-math notation="LaTeX" id="ImEquation326"><![CDATA[$\frac{dV(\sigma)}{d\sigma}=0$]]></tex-math></inline-formula> give the VEVs <inline-formula><tex-math notation="LaTeX" id="ImEquation327"><![CDATA[$\langle \phi^3 \rangle=-g^2\langle (\bar{c}\times c)^3 \rangle$]]></tex-math></inline-formula> and <inline-formula><tex-math notation="LaTeX" id="ImEquation328"><![CDATA[$\langle \sigma \rangle=-\frac{g}{2}\langle (A_{\mu}^A)^2 \rangle$]]></tex-math></inline-formula>, respectively.</p>
<p>When the VEV <inline-formula><tex-math notation="LaTeX" id="ImEquation329"><![CDATA[$\langle (\bar{c}\times c)^3 \rangle$]]></tex-math></inline-formula> exists, the ghost loop yields the tachyonic gluon masses. As in <xref ref-type="sec" rid="SEC2">Sect. 2</xref>, the magnitude for <inline-formula><tex-math notation="LaTeX" id="ImEquation330"><![CDATA[$A_{\mu}^3$]]></tex-math></inline-formula> is twice that for <inline-formula><tex-math notation="LaTeX" id="ImEquation331"><![CDATA[$A_{\mu}^{\pm}$]]></tex-math></inline-formula>. In the presence of the VEV <inline-formula><tex-math notation="LaTeX" id="ImEquation332"><![CDATA[$\langle (A_{\mu}^A)^2 \rangle$]]></tex-math></inline-formula>, gluons acquire a mass. The latter mass compensates the former tachyonic masses. Thus gluons have the usual masses, and the mass for <inline-formula><tex-math notation="LaTeX" id="ImEquation333"><![CDATA[$A_{\mu}^3$]]></tex-math></inline-formula> is different from that for <inline-formula><tex-math notation="LaTeX" id="ImEquation334"><![CDATA[$A_{\mu}^{\pm}$]]></tex-math></inline-formula>.</p>
<p>In their approach, the interactions that yield these VEVs are introduced irrelevant to the original Lagrangian <inline-formula><tex-math notation="LaTeX" id="ImEquation335"><![CDATA[$\mathcal{L}_\mathrm{YM}+\mathcal{L}_\mathrm{GF}$]]></tex-math></inline-formula>. As a result, the VEV <inline-formula><tex-math notation="LaTeX" id="ImEquation336"><![CDATA[$\langle (A_{\mu}^A)^2 \rangle$]]></tex-math></inline-formula> appears irrespective of the VEV <inline-formula><tex-math notation="LaTeX" id="ImEquation337"><![CDATA[$\langle (\bar{c}\times c)^3 \rangle$]]></tex-math></inline-formula>.</p></list-item>
<list-item><p>(5) In our procedure, we need the action in the nonlinear gauge. The quartic ghost interaction yields the VEV <inline-formula><tex-math notation="LaTeX" id="ImEquation338"><![CDATA[$\langle (\bar{c}\times c)^3 \rangle$]]></tex-math></inline-formula>, and the ghost loop brings about the tachyonic gluon masses. The VEV <inline-formula><tex-math notation="LaTeX" id="ImEquation339"><![CDATA[$\langle A_{\mu}^+A_{\mu}^-\rangle=\frac{1}{2}\langle A_{\mu}^aA_{\mu}^a\rangle$]]></tex-math></inline-formula> appears to eliminate the tachyonic mass for <inline-formula><tex-math notation="LaTeX" id="ImEquation340"><![CDATA[$A_{\mu}^{\pm}$]]></tex-math></inline-formula>.</p>
<p>In the Landau gauge, there is no quartic ghost interaction. However, in the low energy region, gauge field configurations on the Gribov horizon contribute to the partition function <inline-formula><tex-math notation="LaTeX" id="ImEquation341"><![CDATA[$Z$]]></tex-math></inline-formula>. These configurations give rise to zero-modes of the ghost operator <inline-formula><tex-math notation="LaTeX" id="ImEquation342"><![CDATA[$\partial_{\mu}D_{\mu}$]]></tex-math></inline-formula>, and make <inline-formula><tex-math notation="LaTeX" id="ImEquation343"><![CDATA[$Z$]]></tex-math></inline-formula> vanish.</p>
<p>However, these zero-modes can produce the quartic ghost interaction [<xref ref-type="bibr" rid="B10">10</xref>]. The Landau gauge changes automatically to the nonlinear gauge. Thus, even if we start from the Landau gauge, effective quartic ghost interaction is produced, and we can apply the scenario proposed in this article.</p>
<p>We note that the scale <inline-formula><tex-math notation="LaTeX" id="ImEquation344"><![CDATA[$\mu_0$]]></tex-math></inline-formula> in Eq. (<xref ref-type="disp-formula" rid="ptx149-M2-4">2.4</xref>) depends on the parameter <inline-formula><tex-math notation="LaTeX" id="ImEquation345"><![CDATA[$\alpha_2$]]></tex-math></inline-formula> at the cut-off scale <inline-formula><tex-math notation="LaTeX" id="ImEquation346"><![CDATA[$\Lambda$]]></tex-math></inline-formula>. One-loop calculation shows that <inline-formula><tex-math notation="LaTeX" id="ImEquation347"><![CDATA[$\alpha_2$]]></tex-math></inline-formula> has the ultraviolet fixed point <inline-formula><tex-math notation="LaTeX" id="ImEquation348"><![CDATA[$\alpha_2=\beta_0/2$]]></tex-math></inline-formula>, where <inline-formula><tex-math notation="LaTeX" id="ImEquation349"><![CDATA[$\beta_0$]]></tex-math></inline-formula> is the coefficient of the beta function <inline-formula><tex-math notation="LaTeX" id="ImEquation350"><![CDATA[$\beta=-\frac{\beta_0}{16\pi^2}g^3$]]></tex-math></inline-formula>. By substituting <inline-formula><tex-math notation="LaTeX" id="ImEquation351"><![CDATA[$\alpha_2=\beta_0/2$]]></tex-math></inline-formula> into <inline-formula><tex-math notation="LaTeX" id="ImEquation352"><![CDATA[$\mu_0$]]></tex-math></inline-formula>, we find that <inline-formula><tex-math notation="LaTeX" id="ImEquation353"><![CDATA[$\mu_0$]]></tex-math></inline-formula> coincides with the QCD scale parameter <inline-formula><tex-math notation="LaTeX" id="ImEquation354"><![CDATA[$\Lambda_{\mathrm{QCD}}$]]></tex-math></inline-formula> [<xref ref-type="bibr" rid="B8">8</xref>].</p></list-item>
</list></p>
</sec>
</body>
<back>
<sec><title>Funding</title>
<p>Open Access funding: SCOAP<inline-formula><tex-math notation="LaTeX" id="ImEquation355"><![CDATA[$^3$]]></tex-math></inline-formula>.</p>
</sec>
<sec id="SECA"><title>Appendix A. <inline-formula><tex-math notation="LaTeX" id="ImEquation356"><![CDATA[$\boldsymbol{\langle (A_{\mu}^3)^2\rangle=0}$]]></tex-math></inline-formula></title>
<p>To eliminate the tachyonic mass terms
<disp-formula id="ptx149-MA-1"><label>(A.1)</label><tex-math notation="LaTeX" id="Equation71"><![CDATA[
\begin{equation}
-m_D^2A_{\mu}^+A_{\mu}^- -m_D^2 \frac{\kappa_D}{2}(A_{\mu}^3)^2, \label{a01}
\end{equation}
]]></tex-math></disp-formula>
the VEV <inline-formula><tex-math notation="LaTeX" id="ImEquation357"><![CDATA[$\langle A_{\mu}^+A_{\mu}^-\rangle$]]></tex-math></inline-formula> is necessary. In this appendix, we show, in contrast with <inline-formula><tex-math notation="LaTeX" id="ImEquation358"><![CDATA[$\langle A_{\mu}^+A_{\mu}^-\rangle$]]></tex-math></inline-formula>, the VEV <inline-formula><tex-math notation="LaTeX" id="ImEquation359"><![CDATA[$\langle (A_{\mu}^3)^2\rangle$]]></tex-math></inline-formula> vanishes.</p>
<p>To apply the procedure in <xref ref-type="sec" rid="SEC3.2">Sect. 3.2</xref>, we substitute
<disp-formula id="ptx149-MA-2"><label>(A.2)</label><tex-math notation="LaTeX" id="Equation72"><![CDATA[
\begin{equation}
A_{\mu}^+A_{\mu}^- \to \Phi_D + A_{\mu}^+A_{\mu}^-,\ \Phi_D=\langle A_{\mu}^+A_{\mu}^-\rangle, \quad
(A_{\mu}^3)^2 \to \Psi_D + (A_{\mu}^3)^2,\ \Psi_D=\langle (A_{\mu}^3)^2\rangle \label{a02}
\end{equation}
]]></tex-math></disp-formula>
into Eqs. (<xref ref-type="disp-formula" rid="ptx149-M3-5">3.5</xref>) and (<xref ref-type="disp-formula" rid="ptx149-MA-1">A.1</xref>). Then the part that contains <inline-formula><tex-math notation="LaTeX" id="ImEquation360"><![CDATA[$\Phi_D$]]></tex-math></inline-formula> or <inline-formula><tex-math notation="LaTeX" id="ImEquation361"><![CDATA[$\Psi_D$]]></tex-math></inline-formula> is given by
<disp-formula id="ptx149-UM24"><tex-math notation="LaTeX" id="Equation73"><![CDATA[
\[
V(\Phi_D,\Psi_D) = V_1+V_2,\quad V_1=\frac{g^2}{2}\Phi_D^2 - m_D^2\Phi_D,\quad
V_2= \left(g^2\Phi_D - m_D^2\frac{\kappa_D}{2}\right)\Psi_D.
\]
]]></tex-math></disp-formula></p>
<p>If we set <inline-formula><tex-math notation="LaTeX" id="ImEquation362"><![CDATA[$g^2\Phi_D=\lambda m_D^2$]]></tex-math></inline-formula>, we obtain
<disp-formula id="ptx149-MA-3"><label>(A.3)</label><tex-math notation="LaTeX" id="Equation74"><![CDATA[
\begin{equation}
V(\Phi_D,\Psi_D) = V_1(\lambda)+V_2(\lambda), \quad V_1(\lambda)=\frac{m_D^4}{2g^2}\lambda(\lambda-2), \quad
V_2(\lambda)= m_D^2\left(\lambda - \frac{\kappa_D}{2}\right)\Psi_D. \label{a03}
\end{equation}
]]></tex-math></disp-formula></p>
<p>The potential <inline-formula><tex-math notation="LaTeX" id="ImEquation363"><![CDATA[$V_1$]]></tex-math></inline-formula> has the minimum value <inline-formula><tex-math notation="LaTeX" id="ImEquation364"><![CDATA[$-\frac{m_D^4}{2g^2}$]]></tex-math></inline-formula> at <inline-formula><tex-math notation="LaTeX" id="ImEquation365"><![CDATA[$\lambda=1$]]></tex-math></inline-formula>. As <inline-formula><tex-math notation="LaTeX" id="ImEquation366"><![CDATA[$\Psi_D \geq 0$]]></tex-math></inline-formula>, and <inline-formula><tex-math notation="LaTeX" id="ImEquation367"><![CDATA[$V_2$]]></tex-math></inline-formula> is linear with respect to <inline-formula><tex-math notation="LaTeX" id="ImEquation368"><![CDATA[$\Psi_D$]]></tex-math></inline-formula>, the coefficient must satisfy <inline-formula><tex-math notation="LaTeX" id="ImEquation369"><![CDATA[$(g^2\Phi_D - \kappa_D m_D^2/2)\geq 0$]]></tex-math></inline-formula>. Thus we find that
<disp-formula id="ptx149-MA-4"><label>(A.4)</label><tex-math notation="LaTeX" id="Equation75"><![CDATA[
\begin{equation}
V_2(\lambda)=m_D^2\left(\lambda - \frac{\kappa_D}{2}\right)\Psi_D \geq 0. \label{a04}
\end{equation}
]]></tex-math></disp-formula></p>
<p>Since the local minimum condition <inline-formula><tex-math notation="LaTeX" id="ImEquation370"><![CDATA[$\frac{\delta V}{\delta \Phi_D}=0$]]></tex-math></inline-formula> leads to
<disp-formula id="ptx149-MA-5"><label>(A.5)</label><tex-math notation="LaTeX" id="Equation76"><![CDATA[
\begin{equation}
g^2\Phi_D+g^2\Psi_D-m_D^2 = (\lambda -1)m_D^2 +g^2\Psi_D=0, \label{a05}
\end{equation}
]]></tex-math></disp-formula>
from Eqs. (<xref ref-type="disp-formula" rid="ptx149-MA-4">A.4</xref>) and (<xref ref-type="disp-formula" rid="ptx149-MA-5">A.5</xref>), we obtain
<disp-formula id="ptx149-UM25"><tex-math notation="LaTeX" id="Equation77"><![CDATA[
\[
\frac{\kappa_D}{2}\leq \lambda \leq 1.
\]
]]></tex-math></disp-formula></p>
<p>Now we show that <inline-formula><tex-math notation="LaTeX" id="ImEquation371"><![CDATA[$\Psi_D=0$]]></tex-math></inline-formula>. When <inline-formula><tex-math notation="LaTeX" id="ImEquation372"><![CDATA[$D=4$]]></tex-math></inline-formula>, as <inline-formula><tex-math notation="LaTeX" id="ImEquation373"><![CDATA[$\kappa_4=2$]]></tex-math></inline-formula>, <inline-formula><tex-math notation="LaTeX" id="ImEquation374"><![CDATA[$V_1$]]></tex-math></inline-formula> and <inline-formula><tex-math notation="LaTeX" id="ImEquation375"><![CDATA[$V_2$]]></tex-math></inline-formula> have their minimum values at <inline-formula><tex-math notation="LaTeX" id="ImEquation376"><![CDATA[$\lambda=1$]]></tex-math></inline-formula>, and Eq. (<xref ref-type="disp-formula" rid="ptx149-MA-5">A.5</xref>) leads to <inline-formula><tex-math notation="LaTeX" id="ImEquation377"><![CDATA[$\Psi_4=0$]]></tex-math></inline-formula>. When <inline-formula><tex-math notation="LaTeX" id="ImEquation378"><![CDATA[$D=3$]]></tex-math></inline-formula>, there are two possibilities to minimize <inline-formula><tex-math notation="LaTeX" id="ImEquation379"><![CDATA[$V_2$]]></tex-math></inline-formula>. As <inline-formula><tex-math notation="LaTeX" id="ImEquation380"><![CDATA[$\kappa_3=3/2$]]></tex-math></inline-formula>, one way is to choose <inline-formula><tex-math notation="LaTeX" id="ImEquation381"><![CDATA[$\lambda=3/4$]]></tex-math></inline-formula>. However, since <inline-formula><tex-math notation="LaTeX" id="ImEquation382"><![CDATA[$V_1(\lambda=3/4)>V_1(\lambda=1)$]]></tex-math></inline-formula>, <inline-formula><tex-math notation="LaTeX" id="ImEquation383"><![CDATA[$V_1$]]></tex-math></inline-formula> does not have a minimum value. Another way is to set <inline-formula><tex-math notation="LaTeX" id="ImEquation384"><![CDATA[$\Psi_3=0$]]></tex-math></inline-formula>. Then Eq. (<xref ref-type="disp-formula" rid="ptx149-MA-5">A.5</xref>) gives <inline-formula><tex-math notation="LaTeX" id="ImEquation385"><![CDATA[$\lambda=1$]]></tex-math></inline-formula>, and <inline-formula><tex-math notation="LaTeX" id="ImEquation386"><![CDATA[$V_1$]]></tex-math></inline-formula> is minimized.</p>
<p>We make a comment. Historically, the VEV <inline-formula><tex-math notation="LaTeX" id="ImEquation387"><![CDATA[$\langle (A_{\mu}^A)^2\rangle$]]></tex-math></inline-formula> was discussed in the framework of the operator product expansion (OPE) [<xref ref-type="bibr" rid="B30">30</xref>,<xref ref-type="bibr" rid="B31">31</xref>], and the relation with monopoles was considered [<xref ref-type="bibr" rid="B32">32</xref>]. When <inline-formula><tex-math notation="LaTeX" id="ImEquation388"><![CDATA[$k_{\mu} \to \infty$]]></tex-math></inline-formula>, the OPE gives [<xref ref-type="bibr" rid="B30">30</xref>]
<disp-formula id="ptx149-UM26"><tex-math notation="LaTeX" id="Equation78"><![CDATA[
\[ \langle T(A_{\nu}^B(-k)A_{\rho}^C(k))\rangle = (c_0)_{\nu\rho}^{BC}(k) +
(c_2)_{\nu\rho}^{BC}(k)\langle :(A_{\mu}^A)^2:\rangle + \cdots. \]
]]></tex-math></disp-formula></p>
<p>However, the VEV <inline-formula><tex-math notation="LaTeX" id="ImEquation389"><![CDATA[$\langle :(A_{\mu}^A)^2:\rangle $]]></tex-math></inline-formula> is different from <inline-formula><tex-math notation="LaTeX" id="ImEquation390"><![CDATA[$\Phi_D=\langle A_{\mu}^+A_{\mu}^-\rangle$]]></tex-math></inline-formula>, because <inline-formula><tex-math notation="LaTeX" id="ImEquation391"><![CDATA[$\Phi_D$]]></tex-math></inline-formula> appears as <inline-formula><tex-math notation="LaTeX" id="ImEquation392"><![CDATA[$k_{\mu} \to 0$]]></tex-math></inline-formula>, and the component <inline-formula><tex-math notation="LaTeX" id="ImEquation393"><![CDATA[$A_{\mu}^3$]]></tex-math></inline-formula> does not condense. To make <inline-formula><tex-math notation="LaTeX" id="ImEquation394"><![CDATA[$A_{\mu}^{\pm}$]]></tex-math></inline-formula> massive, the VEVs <inline-formula><tex-math notation="LaTeX" id="ImEquation395"><![CDATA[$\langle A_{\mu}^+A_{\mu}^-\rangle$]]></tex-math></inline-formula> and <inline-formula><tex-math notation="LaTeX" id="ImEquation396"><![CDATA[$\langle \bar{c}^a c^a\rangle$]]></tex-math></inline-formula> were considered in Ref. [<xref ref-type="bibr" rid="B33">33</xref>]. In our approach, although <inline-formula><tex-math notation="LaTeX" id="ImEquation397"><![CDATA[$A_{\mu}^{\pm}$]]></tex-math></inline-formula> becomes massive, the significant role of <inline-formula><tex-math notation="LaTeX" id="ImEquation398"><![CDATA[$\Phi_D$]]></tex-math></inline-formula> is to remove the tachyonic masses.</p>
</sec>
<sec id="SECB"><title>Appendix B. Derivation of Eq. (5.7)</title>
<p>We calculate the ghost determinant (<xref ref-type="disp-formula" rid="ptx149-M5-6">5.6</xref>) given by
<disp-formula id="ptx149-UM27"><tex-math notation="LaTeX" id="Equation79"><![CDATA[
\begin{align*}
& \det[D_{\mu}(b)D_{\mu}(A)+v \times] = \exp[-\int dx V_\mathrm{gh}],\\
& V_\mathrm{gh} = -\mathrm{tr}\int\frac{d^Dk}{(2\pi)^D} \ln[D_{\mu}(b)D_{\mu}(A)+v\times ],
\end{align*}
]]></tex-math></disp-formula>
where the classical part is <inline-formula><tex-math notation="LaTeX" id="ImEquation399"><![CDATA[$b_{\mu}^A=b_{\mu}^3\delta^{A3}$]]></tex-math></inline-formula>, and <inline-formula><tex-math notation="LaTeX" id="ImEquation400"><![CDATA[$A_{\mu}^A=b_{\mu}^A+a_{\mu}^A$]]></tex-math></inline-formula>. Up to the second order of the fields, we find
<disp-formula id="ptx149-MB-1"><label>(B.1)</label><tex-math notation="LaTeX" id="Equation80"><![CDATA[
\begin{align}
V_\mathrm{gh}=&-\int\frac{d^Dk}{(2\pi)^D}\ln [k^4 + v^2 +2vigk_{\mu}(A_{\mu}^3+b_{\mu}^3) \nonumber \\
&-g^2k_{\mu}k_{\nu}\{A_{\mu}^aA_{\nu}^a + (A_{\mu}^3+b_{\mu}^3)(A_{\nu}^3+b_{\nu}^3)\}+
2g^2k^2A_{\mu}^3b_{\mu}^3+\cdots ] . \label{b01}
\end{align}
]]></tex-math></disp-formula></p>
<p>The term <inline-formula><tex-math notation="LaTeX" id="ImEquation401"><![CDATA[$-g^2k_{\mu}k_{\nu}\{A_{\mu}^aA_{\nu}^a +(A_{\mu}^3+b_{\mu}^3)(A_{\nu}^3+b_{\nu}^3)\}$]]></tex-math></inline-formula> in Eq. (<xref ref-type="disp-formula" rid="ptx149-MB-1">B.1</xref>) gives
<disp-formula id="ptx149-UM28"><tex-math notation="LaTeX" id="Equation81"><![CDATA[
\[ -\int \frac{d^Dk}{(2\pi)^D} \frac{-g^2k_{\mu}k_{\nu}}{k^4+v^2} \{A_{\mu}^aA_{\nu}^a +(A_{\mu}^3+b_{\mu}^3)(A_{\nu}^3+b_{\nu}^3)\} .\]
]]></tex-math></disp-formula></p>
<p>Using
<disp-formula id="ptx149-UM29"><tex-math notation="LaTeX" id="Equation82"><![CDATA[
\[ \int \frac{d^4k}{(2\pi)^4} \frac{k_{\mu}k_{\nu}}{k^4+v^2} = -\frac{\delta_{\mu\nu}}{2}\frac{v}{64\pi}, \quad
\int \frac{d^4k}{(2\pi)^4} \frac{k_{\mu}k_{\nu}}{(k^4+v^2)^2} = \frac{\delta_{\mu\nu}}{4}\frac{v}{64\pi},\]
]]></tex-math></disp-formula>
we obtain [<xref ref-type="bibr" rid="B7">7</xref>]
<disp-formula id="ptx149-UM30"><tex-math notation="LaTeX" id="Equation83"><![CDATA[
\[
V_{\mathrm{gh}(1)}= \frac{1}{2}\left(-\frac{g^2v}{64\pi}\right)\{(A_{\mu}^a)^2 +(A_{\mu}^3+b_{\mu}^3)^2\}\!.
\]
]]></tex-math></disp-formula></p>
<p>In the same way, the term <inline-formula><tex-math notation="LaTeX" id="ImEquation402"><![CDATA[$2vigk_{\mu}(A_{\mu}^3+b_{\mu}^3)$]]></tex-math></inline-formula> in Eq. (<xref ref-type="disp-formula" rid="ptx149-MB-1">B.1</xref>) gives
<disp-formula id="ptx149-UM31"><tex-math notation="LaTeX" id="Equation84"><![CDATA[
\[ V_{\mathrm{gh}(2)}=-\int \frac{d^Dk}{(2\pi)^D} \frac{2g^2v^2k_{\mu}k_{\nu}}{(k^4+v^2)^2} (A_{\mu}^3+b_{\mu}^3)(A_{\nu}^3+b_{\nu}^3)
= \frac{1}{2}\left(-\frac{g^2v}{64\pi}\right)(A_{\mu}^3+b_{\mu}^3)^2, \]
]]></tex-math></disp-formula>
and the term <inline-formula><tex-math notation="LaTeX" id="ImEquation403"><![CDATA[$2k^2g^2A_{\mu}^3b_{\mu}^3$]]></tex-math></inline-formula> in Eq. (<xref ref-type="disp-formula" rid="ptx149-MB-1">B.1</xref>) gives
<disp-formula id="ptx149-UM32"><tex-math notation="LaTeX" id="Equation85"><![CDATA[
\[ V_{\mathrm{gh}(3)}=-\int \frac{d^Dk}{(2\pi)^D} \frac{2g^2k^2}{k^4+v^2}A_{\mu}^3b_{\mu}^3=\frac{4g^2v}{64\pi}A_{\mu}^3b_{\mu}^3. \]
]]></tex-math></disp-formula></p>
<p>Thus, substituting <inline-formula><tex-math notation="LaTeX" id="ImEquation404"><![CDATA[$A_{\mu}^a=a_{\mu}^a$]]></tex-math></inline-formula> and <inline-formula><tex-math notation="LaTeX" id="ImEquation405"><![CDATA[$A_{\mu}^3=b_{\mu}^3+a_{\mu}^3$]]></tex-math></inline-formula>, we obtain
<disp-formula id="ptx149-UM33"><tex-math notation="LaTeX" id="Equation86"><![CDATA[
\[ V_\mathrm{gh}=\sum_{n=1}^3 V_{\mathrm{gh}(n)}= \frac{1}{2}\left(-\frac{g^2v}{64\pi}\right)\{(a_{\mu}^a)^2 +2(a_{\mu}^3)^2\}\!.
\]
]]></tex-math></disp-formula></p>
</sec>
<sec id="SECC"><title>Appendix C. Singular gauge transformation</title>
<p>Following Ref. [<xref ref-type="bibr" rid="B4">4</xref>], we consider the gauge transformation with the matrix
<disp-formula id="ptx149-UM34"><tex-math notation="LaTeX" id="Equation87"><![CDATA[
\[ U=e^{i\gamma T_3}e^{i\alpha T_2}e^{i\beta T_3}, \]
]]></tex-math></disp-formula>
where <inline-formula><tex-math notation="LaTeX" id="ImEquation406"><![CDATA[$(T_B)_{AC}=i f_{ABC}$]]></tex-math></inline-formula>. This matrix <inline-formula><tex-math notation="LaTeX" id="ImEquation407"><![CDATA[$U$]]></tex-math></inline-formula> satisfies
<disp-formula id="ptx149-MC-1"><label>(C.1)</label><tex-math notation="LaTeX" id="Equation88"><![CDATA[
\begin{equation}
\frac{\langle \varphi\rangle}{\varphi_0}=\begin{pmatrix}0\cr 0\cr 1\cr \end{pmatrix}=U \hat{n},\quad
\hat{n}=\begin{pmatrix}\sin\alpha \cos\beta \cr
\sin\alpha \sin\beta \cr
\cos\alpha \cr \end{pmatrix} \label{c01}
\end{equation}
]]></tex-math></disp-formula>
and <inline-formula><tex-math notation="LaTeX" id="ImEquation408"><![CDATA[$U^{\dagger}T_AU=T_B\hat{n}^B_A$]]></tex-math></inline-formula>, where
<disp-formula id="ptx149-MC-2"><label>(C.2)</label><tex-math notation="LaTeX" id="Equation89"><![CDATA[
\begin{equation}
\hat{n}_1=\begin{pmatrix}\cos\alpha \cos\beta \cos\gamma-\sin\beta\sin\gamma \cr
\cos\alpha \sin\beta \cos\gamma+\cos\beta\sin\gamma \cr
-\sin\alpha \cos\gamma \cr\end{pmatrix},
\hat{n}_2=\begin{pmatrix}-\cos\alpha \cos\beta \sin\gamma-\sin\beta\cos\gamma \cr
-\cos\alpha \sin\beta \sin\gamma+\cos\beta\cos\gamma \cr
\sin\alpha \sin\gamma \cr \end{pmatrix},
\hat{n}_3=\hat{n}. \label{c02}
\end{equation}
]]></tex-math></disp-formula></p>
<p>These color vectors satisfy the orthonormality
<disp-formula id="ptx149-UM35"><tex-math notation="LaTeX" id="Equation90"><![CDATA[
\[ \hat{n}_A^C\hat{n}_B^C=\delta_{AB}. \]
]]></tex-math></disp-formula></p>
<p>Under this transformation, the gauge field transforms as
<disp-formula id="ptx149-MC-3"><label>(C.3)</label><tex-math notation="LaTeX" id="Equation91"><![CDATA[
\begin{align}
A'^A_{\mu}T_A&= U^{\dagger}A^A_{\mu}T_AU + \frac{i}{g}U^{\dagger}\partial_{\mu}U \nonumber \\
&= \left[A^1_{\mu}\hat{n}^A_1 +A^2_{\mu}\hat{n}^A_2+A^3_{\mu}\hat{n}^A-\frac{1}{g}\left\{(\hat{n}\times \partial_{\mu}\hat{n})^A +
(\cos \alpha \partial_{\mu}\beta+\partial_{\mu}\gamma)\hat{n}^A\right\}\right]T_A. \label{c03}
\end{align}
]]></tex-math></disp-formula></p>
<p>If we write
<disp-formula id="ptx149-MC-4"><label>(C.4)</label><tex-math notation="LaTeX" id="Equation92"><![CDATA[
\begin{equation}
A^A_{\mu}=b^A_{\mu}+a^A_{\mu}, \quad b_{\mu}^A=\frac{1}{g}(\cos \alpha \partial_{\mu}\beta+\partial_{\mu}\gamma)\delta^{A3}, \label{c04}
\end{equation}
]]></tex-math></disp-formula></p>
<p>Eq. (<xref ref-type="disp-formula" rid="ptx149-MC-3">C.3</xref>) becomes
<disp-formula id="ptx149-MC-5"><label>(C.5)</label><tex-math notation="LaTeX" id="Equation93"><![CDATA[
\begin{equation}
A'^A_{\mu}T_A= \left[a^1_{\mu}\hat{n}^A_1 +a^2_{\mu}\hat{n}^A_2+a^3_{\mu}\hat{n}^A-
\frac{1}{g}\left\{(\hat{n}\times \partial_{\mu}\hat{n})^A \right\}\right]T_A. \label{c05}
\end{equation}
]]></tex-math></disp-formula></p>
<p>If we regard the transformation (<xref ref-type="disp-formula" rid="ptx149-MC-5">C.5</xref>) as the background gauge transformation
<disp-formula id="ptx149-UM36"><tex-math notation="LaTeX" id="Equation94"><![CDATA[
\[ U^{\dagger}b_{\mu}U+\frac{i}{g}U^{\dagger}\partial_{\mu}U,\quad U^{\dagger}a_{\mu}U, \]
]]></tex-math></disp-formula></p>
<p>Eq. (<xref ref-type="disp-formula" rid="ptx149-MC-5">C.5</xref>) implies that <inline-formula><tex-math notation="LaTeX" id="ImEquation409"><![CDATA[$a_{\mu}^A$]]></tex-math></inline-formula> and <inline-formula><tex-math notation="LaTeX" id="ImEquation410"><![CDATA[$b_{\mu}^A$]]></tex-math></inline-formula> transform as
<disp-formula id="ptx149-MC-6"><label>(C.6)</label><tex-math notation="LaTeX" id="Equation95"><![CDATA[
\begin{equation}
a_{\mu}^A \to a_{\mu}^B\hat{n}_B^A, \quad b^A_{\mu} \to -\frac{1}{g}(\hat{n}\times \partial_{\mu}\hat{n})^A . \label{c06}
\end{equation}
]]></tex-math></disp-formula></p>
<p>Now, using the spherical coordinates <inline-formula><tex-math notation="LaTeX" id="ImEquation411"><![CDATA[$(r,\theta,\phi)$]]></tex-math></inline-formula> and integer <inline-formula><tex-math notation="LaTeX" id="ImEquation412"><![CDATA[$n$]]></tex-math></inline-formula>, we set the angles as <inline-formula><tex-math notation="LaTeX" id="ImEquation413"><![CDATA[$\alpha=\theta, \beta= -\gamma=n \phi$]]></tex-math></inline-formula>. Then <inline-formula><tex-math notation="LaTeX" id="ImEquation414"><![CDATA[$b_{\mu}^A$]]></tex-math></inline-formula> and <inline-formula><tex-math notation="LaTeX" id="ImEquation415"><![CDATA[$\hat{n}^A$]]></tex-math></inline-formula> become
<disp-formula id="ptx149-MC-7"><label>(C.7)</label><tex-math notation="LaTeX" id="Equation96"><![CDATA[
\begin{equation}
b_{\mu}^A=\tilde{C}_{\mu}\delta^{3A},\quad
\hat{n}=\left(
\begin{array}{c}
\sin \theta \cos n\phi \\
\sin \theta \sin n\phi \\
\cos \theta
\end{array}
\right), \label{c07}
\end{equation}
]]></tex-math></disp-formula>
where <inline-formula><tex-math notation="LaTeX" id="ImEquation416"><![CDATA[$\tilde{C}_{\mu}$]]></tex-math></inline-formula> is the Abelian monopole in Eq. (<xref ref-type="disp-formula" rid="ptx149-M4-1">4.1</xref>). The corresponding non-Abelian monopole is
<disp-formula id="ptx149-MC-8"><label>(C.8)</label><tex-math notation="LaTeX" id="Equation97"><![CDATA[
\begin{equation}
C_{\mu}^A=-\frac{1}{g}(\hat{n}\times \partial_{\mu}\hat{n})^A
=\frac{1}{g}\left(
\begin{array}{c}
\sin n\phi \partial_{\mu}\theta + \sin\theta \cos \theta \cos n\phi \partial_{\mu}(n\phi) \\
-\cos n\phi \partial_{\mu}\theta + \sin \theta \cos\theta \sin n\phi \partial_{\mu}(n\phi) \\
-\sin^2 \theta \partial_{\mu}(n\phi)
\end{array}
\right). \label{c08}
\end{equation}
]]></tex-math></disp-formula></p>
<p>The field strength <inline-formula><tex-math notation="LaTeX" id="ImEquation417"><![CDATA[$H_{\mu\nu}$]]></tex-math></inline-formula> is defined in Eq. (<xref ref-type="disp-formula" rid="ptx149-M6-7">6.7</xref>). If we use Eq. (<xref ref-type="disp-formula" rid="ptx149-MC-8">C.8</xref>), it becomes
<disp-formula id="ptx149-UM37"><tex-math notation="LaTeX" id="Equation98"><![CDATA[
\[ H_{\mu\nu}=-\frac{1}{g}\sin\theta \{\partial_{\mu}\theta \partial_{\nu}(n\phi)-\partial_{\nu}\theta \partial_{\mu}(n\phi)\}\!,
\]
]]></tex-math></disp-formula>
and it satisfies <inline-formula><tex-math notation="LaTeX" id="ImEquation418"><![CDATA[$\partial_{\mu}H_{\mu\nu}=0$]]></tex-math></inline-formula>. In the same way, <inline-formula><tex-math notation="LaTeX" id="ImEquation419"><![CDATA[$\hat{n}$]]></tex-math></inline-formula> in Eq. (<xref ref-type="disp-formula" rid="ptx149-MC-7">C.7</xref>) satisfies
<disp-formula id="ptx149-UM38"><tex-math notation="LaTeX" id="Equation99"><![CDATA[
\[ \partial_{\mu}^2\hat{n}=-\frac{2}{r^2}\hat{n}+\frac{1-n^2}{r^2\sin\theta}\left(
\begin{array}{c}
\cos n\phi \\
\sin n\phi \\
0
\end{array}
\right). \]
]]></tex-math></disp-formula></p>
</sec>
<sec id="SECD"><title>Appendix D. BRS symmetry and global gauge symmetry</title>
<p>In this appendix, for the sake of explanation, we use the operator formalism [<xref ref-type="bibr" rid="B34">34</xref>]. The BRS transformation is <inline-formula><tex-math notation="LaTeX" id="ImEquation420"><![CDATA[$\delta_B$]]></tex-math></inline-formula> and the BRS charge is <inline-formula><tex-math notation="LaTeX" id="ImEquation421"><![CDATA[$Q_B$]]></tex-math></inline-formula>. A state <inline-formula><tex-math notation="LaTeX" id="ImEquation422"><![CDATA[$|\mathrm{phys} \rangle$]]></tex-math></inline-formula> in the physical subspace satisfies the condition <inline-formula><tex-math notation="LaTeX" id="ImEquation423"><![CDATA[$Q_B |\mathrm{phys} \rangle=0$]]></tex-math></inline-formula>.</p>
<sec id="SECD.1"><title>D.1. BRS symmetry</title>
<p>First we show that the constant <inline-formula><tex-math notation="LaTeX" id="ImEquation424"><![CDATA[$w$]]></tex-math></inline-formula> in Eq. (<xref ref-type="disp-formula" rid="ptx149-M2-2">2.2</xref>) must be chosen as <inline-formula><tex-math notation="LaTeX" id="ImEquation425"><![CDATA[$w^A=\varphi_0 \delta^{A3}$]]></tex-math></inline-formula> to preserve the BRS symmetry. The Lagrangian (<xref ref-type="disp-formula" rid="ptx149-M2-2">2.2</xref>) is invariant under the BRS transformation
<disp-formula id="ptx149-UM39"><tex-math notation="LaTeX" id="Equation100"><![CDATA[
\[
\delta_B A_{\mu}=D_{\mu}c,\ \delta_B c= -\frac{g}{2}c\times c,\ \delta_B \bar{c} =iB,\
\delta_B \varphi = g\varphi\times c,\ \delta_B w=0.
\]
]]></tex-math></disp-formula></p>
<p>Using the equation of motion for <inline-formula><tex-math notation="LaTeX" id="ImEquation426"><![CDATA[$B^A$]]></tex-math></inline-formula>, we obtain
<disp-formula id="ptx149-MD-1"><label>(D.1)</label><tex-math notation="LaTeX" id="Equation101"><![CDATA[
\begin{equation}
\langle 0|\alpha_1 B^A |0 \rangle = \varphi_0\delta^{A3} -w^A, \label{d01}
\end{equation}
]]></tex-math></disp-formula>
where <inline-formula><tex-math notation="LaTeX" id="ImEquation427"><![CDATA[$\langle 0| A_{\mu}|0 \rangle =0$]]></tex-math></inline-formula> and <inline-formula><tex-math notation="LaTeX" id="ImEquation428"><![CDATA[$\langle 0| \varphi^A|0 \rangle =\varphi_0 \delta^{A3}$]]></tex-math></inline-formula> have been used. As <inline-formula><tex-math notation="LaTeX" id="ImEquation429"><![CDATA[$B=-i\delta_B \bar{c}$]]></tex-math></inline-formula>, we must set <inline-formula><tex-math notation="LaTeX" id="ImEquation430"><![CDATA[$w^A=\varphi_0 \delta^{A3}$]]></tex-math></inline-formula> to obtain <inline-formula><tex-math notation="LaTeX" id="ImEquation431"><![CDATA[$\langle 0| \delta_B \bar{c}|0 \rangle =\langle 0|\{iQ_B, \bar{c}\}|0 \rangle =0$]]></tex-math></inline-formula>.</p>
<p>Next we consider the VEV <inline-formula><tex-math notation="LaTeX" id="ImEquation432"><![CDATA[$\langle 0| A_{\mu}^+A_{\mu}^-|0 \rangle$]]></tex-math></inline-formula>. Since the operator <inline-formula><tex-math notation="LaTeX" id="ImEquation433"><![CDATA[$A_{\mu}^+A_{\mu}^-$]]></tex-math></inline-formula> satisfies
<disp-formula id="ptx149-MD-2"><label>(D.2)</label><tex-math notation="LaTeX" id="Equation102"><![CDATA[
\begin{equation}
\delta_B (A_{\mu}^+A_{\mu}^-) = A_{\mu}^a(D_{\mu}c)^a\neq 0 , \label{d02}
\end{equation}
]]></tex-math></disp-formula>
it is not BRS-invariant. If there is an operator <inline-formula><tex-math notation="LaTeX" id="ImEquation434"><![CDATA[$\Omega$]]></tex-math></inline-formula> that satisfies <inline-formula><tex-math notation="LaTeX" id="ImEquation435"><![CDATA[$\delta_B \Omega = A_{\mu}^+A_{\mu}^-$]]></tex-math></inline-formula>, the BRS symmetry is broken spontaneously by the VEV <inline-formula><tex-math notation="LaTeX" id="ImEquation436"><![CDATA[$\langle 0| A_{\mu}^+A_{\mu}^-|0 \rangle$]]></tex-math></inline-formula>. However, as <inline-formula><tex-math notation="LaTeX" id="ImEquation437"><![CDATA[$\delta_B^2=0$]]></tex-math></inline-formula>, Eq. (<xref ref-type="disp-formula" rid="ptx149-MD-2">D.2</xref>) implies that such an operator <inline-formula><tex-math notation="LaTeX" id="ImEquation438"><![CDATA[$\Omega$]]></tex-math></inline-formula> does not exist.<xref ref-type="fn" rid="FN6"><sup>6</sup></xref> So the VEV <inline-formula><tex-math notation="LaTeX" id="ImEquation439"><![CDATA[$\langle 0|A_{\mu}^+A_{\mu}^-|0\rangle \neq 0$]]></tex-math></inline-formula> does not contradict the BRS invariance of the vacuum.</p>
<p>We make two comments. First, since there is no ghost-number-violating interaction nor such a condensate, the ghost number should be conserved. Therefore, although <inline-formula><tex-math notation="LaTeX" id="ImEquation440"><![CDATA[$\delta_B A_{\mu}^+A_{\mu}^-\neq 0$]]></tex-math></inline-formula>, its VEV satisfies
<disp-formula id="ptx149-UM40"><tex-math notation="LaTeX" id="Equation103"><![CDATA[
\[ \delta_B \langle 0|A_{\mu}^+A_{\mu}^-|0\rangle = \langle 0|A_{\mu}^a(D_{\mu}c)^a|0\rangle = 0. \]
]]></tex-math></disp-formula></p>
<p>Second, the anti-BRS symmetry is broken in this model [<xref ref-type="bibr" rid="B10">10</xref>]. However, the unitarity of the model is guaranteed by the BRS symmetry.</p>
</sec>
<sec id="SECD.2"><title>D.2. Global SU(2) symmetry</title>
<p>Using the constant small parameter <inline-formula><tex-math notation="LaTeX" id="ImEquation441"><![CDATA[$\theta$]]></tex-math></inline-formula>, the global color transformation is defined by <inline-formula><tex-math notation="LaTeX" id="ImEquation442"><![CDATA[$\delta_{\theta} \Sigma = \theta \times \Sigma$]]></tex-math></inline-formula>, where <inline-formula><tex-math notation="LaTeX" id="ImEquation443"><![CDATA[$\Sigma$]]></tex-math></inline-formula> represents all the fields in <inline-formula><tex-math notation="LaTeX" id="ImEquation444"><![CDATA[$\mathcal{L}_{\varphi}$]]></tex-math></inline-formula>. Since <inline-formula><tex-math notation="LaTeX" id="ImEquation445"><![CDATA[$\langle 0|\delta_{\theta}\varphi^A|0 \rangle =f^{AB3}\theta^B\varphi_0$]]></tex-math></inline-formula>, this symmetry breaks down spontaneously to U(1), and the fields <inline-formula><tex-math notation="LaTeX" id="ImEquation446"><![CDATA[$\varphi^{\pm}$]]></tex-math></inline-formula> are Goldstone bosons. In addition, as <inline-formula><tex-math notation="LaTeX" id="ImEquation447"><![CDATA[$\delta_{\theta} \mathcal{L}_{\varphi}=-w\cdot ( \theta \times B)$]]></tex-math></inline-formula>, the nonzero constant <inline-formula><tex-math notation="LaTeX" id="ImEquation448"><![CDATA[$w$]]></tex-math></inline-formula> breaks this symmetry at the Lagrangian level. However, as <inline-formula><tex-math notation="LaTeX" id="ImEquation449"><![CDATA[$B=-i\delta_B\bar{c}$]]></tex-math></inline-formula>, this breaking term <inline-formula><tex-math notation="LaTeX" id="ImEquation450"><![CDATA[$\delta_{\theta}\mathcal{L}_{\varphi}=-i(w\times \theta)\cdot \delta_B \bar{c}$]]></tex-math></inline-formula> is BRS-exact. Since the physical states satisfy <inline-formula><tex-math notation="LaTeX" id="ImEquation451"><![CDATA[$Q_B |\mathrm{phys} \rangle=0$]]></tex-math></inline-formula>, we find that
<disp-formula id="ptx149-UM41"><tex-math notation="LaTeX" id="Equation104"><![CDATA[
\[
\langle \mathrm{phys}_2|\delta_{\theta}\mathcal{L}_{\varphi}|\mathrm{phys}_1 \rangle=(w\times \theta)\cdot \langle
\mathrm{phys}_2|\{Q_B, \bar{c}\}|\mathrm{phys}_1 \rangle=0.
\]
]]></tex-math></disp-formula></p>
<p>Thus the breaking term does not contribute to amplitudes between physical states [<xref ref-type="bibr" rid="B10">10</xref>].</p>
</sec>
</sec>
<fn-group>
<title>Footnotes</title>
<fn id="FN1"><p><sup>1</sup> In <xref ref-type="sec" rid="SECD">Appendix D</xref>, the necessity of <inline-formula><tex-math notation="LaTeX" id="ImEquation452"><![CDATA[$w$]]></tex-math></inline-formula> is explained. The BRS symmetry and the broken global gauge symmetry are also discussed.</p></fn>
<fn id="FN2"><p><sup>2</sup> In this subsection, we write <inline-formula><tex-math notation="LaTeX" id="ImEquation453"><![CDATA[$\hslash$]]></tex-math></inline-formula> explicitly. For scalar fields <inline-formula><tex-math notation="LaTeX" id="ImEquation454"><![CDATA[$\phi(x)$]]></tex-math></inline-formula>, the effective potential for the LCO <inline-formula><tex-math notation="LaTeX" id="ImEquation455"><![CDATA[$\phi^2$]]></tex-math></inline-formula> is studied in Refs. [<xref ref-type="bibr" rid="B12">12</xref>,<xref ref-type="bibr" rid="B13">13</xref>].</p></fn>
<fn id="FN3"><p><sup>3</sup> In this paper, as we are interested in the massive magnetic potential, we choose <inline-formula><tex-math notation="LaTeX" id="ImEquation456"><![CDATA[$b_{\mu}^A=\tilde{C}_{\mu}\delta^{A3}$]]></tex-math></inline-formula>. However, instead of <inline-formula><tex-math notation="LaTeX" id="ImEquation457"><![CDATA[$\tilde{C}_{\mu}$]]></tex-math></inline-formula>, we can introduce other classical solutions <inline-formula><tex-math notation="LaTeX" id="ImEquation458"><![CDATA[$B_{\mu}$]]></tex-math></inline-formula> in the form <inline-formula><tex-math notation="LaTeX" id="ImEquation459"><![CDATA[$b_{\mu}^A=B_{\mu}\delta^{A3}$]]></tex-math></inline-formula>.</p></fn>
<fn id="FN4"><p><sup>4</sup> Equation (<xref ref-type="disp-formula" rid="ptx149-M4-1">4.1</xref>) no longer satisfies Eq. (<xref ref-type="disp-formula" rid="ptx149-M5-10">5.10</xref>). If we use a dual potential, a modified solution is obtained. A concrete solution will be given in the next paper.</p></fn>
<fn id="FN5"><p><sup>5</sup> The components <inline-formula><tex-math notation="LaTeX" id="ImEquation460"><![CDATA[$\rho d\hat{n}$]]></tex-math></inline-formula> and <inline-formula><tex-math notation="LaTeX" id="ImEquation461"><![CDATA[$\sigma d\hat{n}\times \hat{n}$]]></tex-math></inline-formula> in Ref. [<xref ref-type="bibr" rid="B18">18</xref>] correspond to <inline-formula><tex-math notation="LaTeX" id="ImEquation462"><![CDATA[$A_{\mu}^{\pm}$]]></tex-math></inline-formula> in this paper. Condensations related to <inline-formula><tex-math notation="LaTeX" id="ImEquation463"><![CDATA[$\rho$]]></tex-math></inline-formula> and <inline-formula><tex-math notation="LaTeX" id="ImEquation464"><![CDATA[$\sigma$]]></tex-math></inline-formula> are discussed in Ref. [<xref ref-type="bibr" rid="B18">18</xref>].</p></fn>
<fn id="FN6"><p><sup>6</sup> In the case of <inline-formula><tex-math notation="LaTeX" id="ImEquation465"><![CDATA[$\varphi^A$]]></tex-math></inline-formula>, the equation of motion for <inline-formula><tex-math notation="LaTeX" id="ImEquation466"><![CDATA[$B^A$]]></tex-math></inline-formula> gives Eq. (<xref ref-type="disp-formula" rid="ptx149-MD-1">D.1</xref>). However, in the case of <inline-formula><tex-math notation="LaTeX" id="ImEquation467"><![CDATA[$\langle 0| A_{\mu}^+A_{\mu}^-|0 \rangle$]]></tex-math></inline-formula>, any colored fields do not give the equation of motion with <inline-formula><tex-math notation="LaTeX" id="ImEquation468"><![CDATA[$(A_{\mu}^a)^2$]]></tex-math></inline-formula>.</p></fn>
</fn-group>
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