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<front>
<journal-meta>
<journal-id journal-id-type="publisher-id">ptep</journal-id>
<journal-title-group>
<journal-title>Progress of Theoretical and Experimental Physics</journal-title>
<abbrev-journal-title abbrev-type="pubmed">Prog. Theor. Exp. Phys.</abbrev-journal-title>
<abbrev-journal-title abbrev-type="publisher">PTEPHY</abbrev-journal-title>
</journal-title-group>
<issn pub-type="epub">2050-3911</issn>
<publisher>
<publisher-name>Oxford University Press</publisher-name>
</publisher>
</journal-meta>
<article-meta>
<article-id pub-id-type="doi">10.1093/ptep/ptac172</article-id>
<article-id pub-id-type="publisher-id">ptac172</article-id>
<article-id pub-id-type="arxiv">arXiv:2208.05150</article-id>
<article-categories>
<subj-group subj-group-type="category-toc-heading">
<subject>Paper</subject>
<subj-group subj-group-type="category-toc-heading">
<subject>Theoretical Particle Physics</subject>
</subj-group>
</subj-group>
<subj-group subj-group-type="category-taxonomy-collection">
<subject>AcademicSubjects/SCI01970</subject>
</subj-group>
<subj-group subj-group-type="category-taxonomy-collection">
<subject>PTEP/A64</subject>
<subject>PTEP/B30</subject>
<subject>PTEP/B69</subject>
</subj-group>
</article-categories>
<title-group>
<article-title>Massive fermion between two parallel chiral plates</article-title>
</title-group>
<contrib-group>
<contrib contrib-type="author" corresp="yes">
<name><surname>Rohim</surname> <given-names>Ar</given-names></name>
<email xlink:type="simple">ar.rohim73@gmail.com</email>
<aff><institution>Department of Physics, Kyushu University</institution>, <addr-line>Fukuoka, 819-0395</addr-line>, <country country="JP">Japan</country></aff>
<aff><institution>Research Center for Quantum Physics, National Research and Innovation Agency (BRIN)</institution>, <addr-line>South Tangerang 15314</addr-line>, <country country="ID">Indonesia</country></aff>
<xref ref-type="corresp" rid="cor1"/>
</contrib>
<contrib contrib-type="author" corresp="yes">
<name><surname>Adam</surname> <given-names>Apriadi Salim</given-names></name>
<email xlink:type="simple">apriadi.salim.adam@brin.go.id</email>
<aff><institution>Research Center for Quantum Physics, National Research and Innovation Agency (BRIN)</institution>, <addr-line>South Tangerang 15314</addr-line>, <country country="ID">Indonesia</country></aff>
<xref ref-type="corresp" rid="cor2"/>
</contrib>
<contrib contrib-type="author" corresp="yes">
<name><surname>Yamamoto</surname> <given-names>Kazuhiro</given-names></name>
<email xlink:type="simple">yamamoto@phys.kyushu-u.ac.jp</email>
<aff><institution>Department of Physics, Kyushu University</institution>, <addr-line>Fukuoka, 819-0395</addr-line>, <country country="JP">Japan</country></aff>
<aff><institution>Research Center for Advanced Particle Physics, Kyushu University</institution>, <addr-line>Fukuoka 819-0395</addr-line>, <country country="JP">Japan</country></aff>
<xref ref-type="corresp" rid="cor3"/>
</contrib>
</contrib-group>
<author-notes>
<corresp id="cor1">E-mail: <email xlink:type="simple">ar.rohim73@gmail.com</email></corresp>
<corresp id="cor2">E-mail: <email xlink:type="simple">apriadi.salim.adam@brin.go.id</email></corresp>
<corresp id="cor3">E-mail: <email xlink:type="simple">yamamoto@phys.kyushu-u.ac.jp</email></corresp>
</author-notes>
<pub-date pub-type="cover"><month>01</month><year>2023</year></pub-date>
<pub-date pub-type="collection" iso-8601-date="2023-01-10"><day>10</day><month>01</month><year>2023</year></pub-date>
<pub-date pub-type="epub" iso-8601-date="2022-12-16"><day>16</day><month>12</month><year>2022</year></pub-date>
<volume>2023</volume>
<issue>1</issue>
<elocation-id>013B05</elocation-id>
<history>
<date date-type="received"><day>25</day><month>11</month><year>2022</year></date>
<date date-type="rev-recd"><day>09</day><month>12</month><year>2022</year></date>
<date date-type="accepted"><day>14</day><month>12</month><year>2022</year></date>
<date date-type="corrected-typeset"><day>01</day><month>02</month><year>2023</year></date>
</history>
<permissions>
<copyright-statement>&#x00A9; The Author(s) 2022. Published by Oxford University Press on behalf of the Physical Society of Japan.</copyright-statement>
<copyright-statement>2022</copyright-statement>
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<license-p>Funded by SCOAP<sup>3</sup>. SCOAP3 and OUP support the goals of the <ext-link ext-link-type="uri" xmlns:xlink="http://www.w3.org/1999/xlink" xlink:href="https://www.iybssd2022.org/en/home/">International Year of Basic Sciences for Sustainable Development</ext-link></license-p>
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<self-uri xlink:href="ptac172.pdf"/>
<abstract abstract-type="abstract"><title>Abstract</title>
<p>We study the system of a massive fermion field confined between two parallel plates, where the properties of both plates are discussed under chiral MIT boundary conditions. We investigate the effects of the chiral angle on the Casimir energy for a massive fermion field with the general momentum. We find that the Casimir energy as a function of the chiral angle is generally symmetric, and the attractive Casimir force in the chiral case is stronger than that in the nonchiral case. In addition, we investigate the approximate Casimir energy for light and heavy mass cases. The behavior of the discrete momentum and changes of spin orientation are also discussed.</p>
</abstract>
<funding-group>
<award-group award-type="grant">
<funding-source>
<institution-wrap>
<institution>SCOAP</institution>
</institution-wrap>
</funding-source>
</award-group>
</funding-group>
<counts>
<page-count count="15"/>
</counts>
</article-meta>
</front>
<body>
<sec id="sec1" sec-type="intro">
<label>1.</label>
<title>Introduction</title>
<p>The Casimir effect for two parallel conducting plates in a vacuum state that generates an attractive force was first discussed in Ref.&#x00A0;[<xref ref-type="bibr" rid="bib1">1</xref>]. In 1958, an experimental measurement on such a force was performed with rough precision [<xref ref-type="bibr" rid="bib2">2</xref>], and the precision of the measurement has since been increased [<xref ref-type="bibr" rid="bib3 bib4 bib5 bib6">3&#x2013;6</xref>] (see also Refs.&#x00A0;[<xref ref-type="bibr" rid="bib7">7</xref>,<xref ref-type="bibr" rid="bib8">8</xref>] for review). The theoretical discussion was extended for various models (e.g. Refs.&#x00A0;[<xref ref-type="bibr" rid="bib9 bib10 bib11 bib12 bib13 bib14 bib15 bib16 bib17 bib18 bib19 bib20 bib21 bib22 bib23 bib24 bib25 bib26 bib27">9&#x2013;27</xref>]). The Casimir effect is a manifestation of quantum field theory with appropriate boundary conditions. Thus, the choice of boundary condition plays an important role in the Casimir effect. The essential aspect when discussing the Casimir effect is not only the type of boundary condition involved but also the type of quantum field. For the scalar field, variants of the Dirichlet and Neumann boundary conditions are frequently used in the literature [<xref ref-type="bibr" rid="bib13">13</xref>,<xref ref-type="bibr" rid="bib14">14</xref>,<xref ref-type="bibr" rid="bib19">19</xref>,<xref ref-type="bibr" rid="bib22 bib23 bib24">22&#x2013;24</xref>]. For the fermion field, however, these two boundary conditions cannot be applied [<xref ref-type="bibr" rid="bib26">26</xref>]. Instead, one may use alternative boundary conditions, e.g. a bag boundary [<xref ref-type="bibr" rid="bib10 bib11 bib12">10&#x2013;12</xref>,<xref ref-type="bibr" rid="bib18">18</xref>,<xref ref-type="bibr" rid="bib20">20</xref>,<xref ref-type="bibr" rid="bib25 bib26 bib27 bib28 bib29 bib30 bib31">25&#x2013;31</xref>].</p>
<p>Discussing the boundary condition for a Dirac field is nontrivial because the Dirac equation&#x00A0;is a first-order differential equation. To discuss the Casimir effect for the Dirac field, several authors [<xref ref-type="bibr" rid="bib28 bib29 bib30 bib31">28&#x2013;31</xref>] have used the boundary condition in the MIT bag model [<xref ref-type="bibr" rid="bib32 bib33 bib34">32&#x2013;34</xref>] (see also Refs.&#x00A0;[<xref ref-type="bibr" rid="bib35">35</xref>,<xref ref-type="bibr" rid="bib36">36</xref>] for confinement system); this guarantees vanishing flux or normal probability density at the boundary surface. However, this boundary condition leads to a discontinuity of the axial-vector current at the boundary surface that breaks its chiral symmetry. An alternative way to address this issue is to introduce the chiral bag model in the presence of the pion field [<xref ref-type="bibr" rid="bib37">37</xref>].</p>
<p>A more general form of the boundary condition in the MIT bag model that includes the chiral angle is the so-called chiral MIT boundary condition [<xref ref-type="bibr" rid="bib10">10</xref>,<xref ref-type="bibr" rid="bib38">38</xref>,<xref ref-type="bibr" rid="bib39">39</xref>]. Using this boundary, one can investigate the interaction between the particle and boundary surface, which may change the spin orientation depending on the chiral angle [<xref ref-type="bibr" rid="bib40">40</xref>]. Thus, the roles of the chiral angle in boundary conditions for a Dirac field may give essential features (e.g. Refs.&#x00A0;[<xref ref-type="bibr" rid="bib41 bib42 bib43 bib44 bib45">41&#x2013;45</xref>]). Ref.&#x00A0;[<xref ref-type="bibr" rid="bib42">42</xref>] showed that the particle&#x2019;s energy in the confinement system also depends on the chiral angle. There is another general form of the boundary condition in the MIT bag model, the self-adjoint boundary condition, which was used in Ref.&#x00A0;[<xref ref-type="bibr" rid="bib46">46</xref>] to discuss the Casimir effect by including the background magnetic field (see also Ref.&#x00A0;[<xref ref-type="bibr" rid="bib47">47</xref>]).</p>
<p>This study investigates the Casimir effect of a Dirac field confined between two parallel plates. The properties of both plates are described by chiral MIT boundary conditions [<xref ref-type="bibr" rid="bib10">10</xref>]. We propose the general solution for the Dirac equation&#x00A0;in such a system following the arguments in Refs.&#x00A0;[<xref ref-type="bibr" rid="bib35">35</xref>,<xref ref-type="bibr" rid="bib36">36</xref>,<xref ref-type="bibr" rid="bib40">40</xref>]. We write the mass of a particle as a function of position and include an analysis of the spin orientation by distinguishing its field components. Along with the mentioned procedure, we discuss not only the Casimir energy but also the Casimir pressure. Compared with Ref.&#x00A0;[<xref ref-type="bibr" rid="bib10">10</xref>], where the authors applied chiral MIT boundary conditions for the massless case (see also Refs.&#x00A0;[<xref ref-type="bibr" rid="bib18">18</xref>]), in this paper we apply the boundary conditions for the case of a massive fermion field. We also investigate how the spin orientation changes under the interaction between the field and the boundary surface of the plates. Our detailed setup of the boundary condition in the first plate differs from that of Ref.&#x00A0;[<xref ref-type="bibr" rid="bib10">10</xref>], where the author set the specific value of the chiral angle for the first plate and took a general chiral angle for the second plate. In our setup, we set the chiral angle at both plates to the same general value. From the viewpoint of the boundary condition type, the present paper is an extension of the earlier study on the Casimir energy by the authors of Ref.&#x00A0;[<xref ref-type="bibr" rid="bib28">28</xref>], in which they discussed the nonchiral case.</p>
<p>In this paper, we also investigate the energy gap between two states under the effect of the chiral angle. Compared to the work in Ref.&#x00A0;[<xref ref-type="bibr" rid="bib48">48</xref>] where the authors used local boundary conditions, in this study we compute such an energy gap derived using chiral MIT boundary conditions. Thus, we can address the effect of the chiral angle on the electron transport in material such as graphene nanoribbons [<xref ref-type="bibr" rid="bib49 bib50 bib51">49&#x2013;51</xref>]. We also expect that the present study could be applied to nanotubes under chiral MIT boundary conditions. The application to such a system under a nonchiral boundary has been done previously by Ref.&#x00A0;[<xref ref-type="bibr" rid="bib30">30</xref>] (cf. Ref.&#x00A0;[<xref ref-type="bibr" rid="bib16">16</xref>]).</p>
<p>The rest of this paper is organized as follows. In Sect.&#x00A0;<xref ref-type="sec" rid="sec2">2</xref>, we introduce the general setup for our model. In Sect.&#x00A0;<xref ref-type="sec" rid="sec3">3</xref>, we discuss the features under chiral MIT boundary conditions, focusing on the discrete momenta and change of spin orientations. In Sect.&#x00A0;<xref ref-type="sec" rid="sec4">4</xref>, we investigate the Casimir effect of a massive fermion under this boundary condition. Section&#x00A0;<xref ref-type="sec" rid="sec5">5</xref> is devoted to our summary. In Appendix&#x00A0;<xref ref-type="app" rid="sec7">A</xref>, we provide the complementary derivations for discrete momenta. Throughout this paper, we will use natural units <italic>c</italic> &#x003D; &#x210F; &#x003D; 1.</p>
</sec>
<sec id="sec2">
<label>2.</label>
<title>Physical setup</title>
<p>We consider a free massive Dirac fermion confined between two parallel plates in a 3 + 1-dimensional Minkowski spacetime background. The first plate is placed at <italic>x</italic><sub>3</sub> &#x003D; 0 while the second one is placed at <italic>x</italic><sub>3</sub> &#x003D; &#x2113; (see Fig.&#x00A0;<xref ref-type="fig" rid="fig1">1</xref>). Both plates are in parallel with the (<italic>x</italic><sub>1</sub>, <italic>x</italic><sub>2</sub>)-plane. In such a system, the action of a Dirac field with mass <italic>m</italic> is given by
<disp-formula id="update1673781174306">
<label>(1)</label>
<tex-math id="TM0001" notation="LaTeX"><![CDATA[$$\begin{eqnarray}
S=\int {\mathrm{d}}^4x \bar{\Psi }(i\gamma ^\mu \partial _\mu -m) \Psi ,
\end{eqnarray}$$]]></tex-math>
</disp-formula>where <inline-formula><tex-math id="TM0002" notation="LaTeX"><![CDATA[$\bar{\Psi }\equiv \Psi ^\dagger \gamma ^0$]]></tex-math></inline-formula> is the Dirac adjoint and <italic>&#x03B3;<sup>&#x03BC;</sup></italic> are the gamma matrices in the Dirac representation given by
<disp-formula id="equ2">
<label>(2)</label>
<tex-math id="TM0003" notation="LaTeX"><![CDATA[$$\begin{eqnarray}
\gamma ^0= {\begin{pmatrix}I & \quad 0\\
0 & \quad -I \end{pmatrix}} ~~{\rm and}~~ \gamma ^i= {\begin{pmatrix}o & \quad \sigma _i\\
-\sigma _i & \quad 0 \end{pmatrix}}, ~~ i=1,2,3~,
\end{eqnarray}$$]]></tex-math>
</disp-formula>with <italic>I</italic> is a 2 &#x00D7; 2 identity matrix and <italic>&#x03C3;<sub>i</sub></italic> are Pauli matrices. The above gamma matrices satisfy the anticommutation relation {<italic>&#x03B3;<sup>&#x03BC;</sup>, &#x03B3;<sup>&#x03BD;</sup></italic>} &#x003D; 2<italic>&#x03B7;<sup>&#x03BC;&#x03BD;</sup></italic> with <italic>&#x03B7;<sup>&#x03BC;&#x03BD;</sup></italic> &#x003D; diag.(1, &#x2212;1, &#x2212;1, &#x2212;1). Taking the variation of the action in Eq.&#x00A0;(<xref ref-type="disp-formula" rid="update1673781174306">1</xref>) leads to the following Dirac equation,
<disp-formula id="equ3">
<label>(3)</label>
<tex-math id="TM0004" notation="LaTeX"><![CDATA[$$\begin{eqnarray}
(i\gamma ^\mu \partial _\mu -m) \Psi =0.
\end{eqnarray}$$]]></tex-math>
</disp-formula></p>
<fig id="fig1" position="float">
<label>Fig. 1.</label>
<caption><p>Physical setup of a Dirac fermion confined between two parallel plates. We use <italic>L</italic> and &#x2113; to represent the plate&#x2019;s size and distance, respectively. In the present paper, we assume the limit <italic>L</italic> &#x2192; &#x221E; approximately.</p></caption>
<graphic xmlns:xlink="http://www.w3.org/1999/xlink" xlink:href="ptac172fig1.jpg" mimetype="image"/>
</fig>
<p>To propose the specific form of the Dirac field in the region between two parallel plates that satisfies the Dirac equation&#x00A0;(<xref ref-type="disp-formula" rid="equ3">3</xref>), we follow the arguments used in Refs.&#x00A0;[<xref ref-type="bibr" rid="bib35">35</xref>,<xref ref-type="bibr" rid="bib36">36</xref>,<xref ref-type="bibr" rid="bib40">40</xref>] as follows. (i) The particle mass depends on its position, which is originally described by the MIT bag model for hadrons [<xref ref-type="bibr" rid="bib10">10</xref>,<xref ref-type="bibr" rid="bib38">38</xref>,<xref ref-type="bibr" rid="bib39">39</xref>]. Namely, inside the region between two parallel plates, the mass of a Dirac field is finite and becomes infinite at both plates [<xref ref-type="bibr" rid="bib35">35</xref>,<xref ref-type="bibr" rid="bib36">36</xref>]. Under this condition, the Dirac field outside the confinement area vanishes. (ii) The form of a Dirac field consists of two-component fields associated with their spin orientations [<xref ref-type="bibr" rid="bib40">40</xref>]. Based on the arguments above, the proposal for a positive frequency of the massive Dirac field in the region between two parallel plates is given by
<disp-formula id="equ4">
<label>(4)</label>
<tex-math id="TM0005" notation="LaTeX"><![CDATA[$$\begin{eqnarray}
\psi ^{(+)}_{{\boldsymbol k}s}(t,{\boldsymbol x})=e^{-iE t} \psi ^{(+)}_{{\boldsymbol k} s}({\boldsymbol x}),
\end{eqnarray}$$]]></tex-math>
</disp-formula>
<disp-formula id="update1673781413345">
<label>(5)</label>
<tex-math id="TM0006" notation="LaTeX"><![CDATA[$$\begin{eqnarray}
\psi ^{(+)}_{{\boldsymbol k} s}({\boldsymbol x})= B {\begin{pmatrix}\chi _{\mathrm{R}}\\
r\hat{\boldsymbol k}_{\mathrm{R}}\cdot {\boldsymbol \sigma } \chi _{\mathrm{R}} \end{pmatrix}} e^{i{\boldsymbol k}_{\mathrm{R}} \cdot {\boldsymbol x}}+C {\begin{pmatrix}\chi _{\mathrm{L}}\\
r\hat{\boldsymbol k}_{\mathrm{L}}\cdot {\boldsymbol \sigma } \chi _{\mathrm{L}} \end{pmatrix}} e^{i{\boldsymbol k}_{\mathrm{L}} \cdot {\boldsymbol x}},
\end{eqnarray}$$]]></tex-math>
</disp-formula>where <italic>B</italic> and <italic>C</italic> are complex coefficients, <italic>s</italic> represents the spin orientation, <inline-formula><tex-math id="TM0007" notation="LaTeX"><![CDATA[$r=|{\boldsymbol k_{{\mathrm{R}}({\mathrm{L}})}}|/(m+E)$]]></tex-math></inline-formula>, and <inline-formula><tex-math id="TM0008" notation="LaTeX"><![CDATA[$E = \sqrt{k^2_1+k^2_2+k^2_3+m^2}$]]></tex-math></inline-formula> is the energy of a Dirac field. The two-component spinors<italic>&#x03C7;</italic><sub>R(L)</sub> satisfy the normalized condition of <inline-formula><tex-math id="TM0009" notation="LaTeX"><![CDATA[$\chi ^\dagger _{{\mathrm{R}}({\mathrm{L}})}\chi _{{\mathrm{R}}({\mathrm{L}})}=1$]]></tex-math></inline-formula> with subscripts R and L corresponding to the right and left of the Dirac field components, respectively. We also use the notations <inline-formula><tex-math id="TM0010" notation="LaTeX"><![CDATA[${\boldsymbol k}_{\mathrm{R}}=(k_1,k_2,k_3)$]]></tex-math></inline-formula> and <inline-formula><tex-math id="TM0011" notation="LaTeX"><![CDATA[${\boldsymbol k}_{\mathrm{L}}=(k_1,k_2,-k_3)$]]></tex-math></inline-formula> to represent the spatial momentum of the right- and left-moving field components. Note that we have distinguished the two-component spinor for each component of the Dirac field in Eq.&#x00A0;(<xref ref-type="disp-formula" rid="update1673781413345">5</xref>) because their spin orientations may depend on the boundary condition [<xref ref-type="bibr" rid="bib40">40</xref>]. The corresponding form of the negative frequency for the massive Dirac field can be obtained by taking the charge conjugation of the above positive-frequency Dirac field as
<disp-formula id="equ6">
<label>(6)</label>
<tex-math id="TM0012" notation="LaTeX"><![CDATA[$$\begin{eqnarray}
\psi ^{(-)}_{{\boldsymbol k}s}(t,{\boldsymbol x})=\psi ^{(+)\rm C}_{{\boldsymbol k}s}(t,{\boldsymbol x})=i\gamma ^2\psi ^{(+)*}_{{\boldsymbol k}s}(t,{\boldsymbol x}).
\end{eqnarray}$$]]></tex-math>
</disp-formula></p>
<p>In our model, the properties of both plates are described by chiral MIT boundary conditions given as [<xref ref-type="bibr" rid="bib10">10</xref>]
<disp-formula id="equ7">
<label>(7)</label>
<tex-math id="TM0013" notation="LaTeX"><![CDATA[$$\begin{eqnarray}
iN_\mu \gamma ^\mu \psi =e^{-i\Theta \gamma ^5}\psi ,
\end{eqnarray}$$]]></tex-math>
</disp-formula>where <italic>N<sub>&#x03BC;</sub></italic> is an inward normal unit four-vector perpendicular to the boundary surface, &#x0398; &#x02208; [0, 2&#x03C0;) denotes the chiral angle, and <italic>&#x03B3;</italic><sup>5</sup> &#x2261; <italic>i&#x03B3;</italic><sup>0</sup><italic>&#x03B3;</italic><sup>1</sup><italic>&#x03B3;</italic><sup>2</sup><italic>&#x03B3;</italic><sup>3</sup>. The above boundary condition guarantees the vanishing of the normal probability current density at the boundary surface for any chiral angles [<xref ref-type="bibr" rid="bib39">39</xref>]
<disp-formula id="equ8">
<label>(8)</label>
<tex-math id="TM0014" notation="LaTeX"><![CDATA[$$\begin{eqnarray}
N_\mu J^\mu (\equiv N_\mu \bar{\psi }\gamma ^\mu \psi )=0.
\end{eqnarray}$$]]></tex-math>
</disp-formula>In the nonchiral case &#x0398; &#x003D; 0, the boundary condition (<xref ref-type="disp-formula" rid="equ7">7</xref>) reduces to that given in the MIT bag model.</p>
</sec>
<sec id="sec3">
<label>3.</label>
<title>Features under boundary conditions</title>
<p>In this section, we investigate two features of a massive fermion field confined between two parallel plates under chiral MIT boundary conditions [<xref ref-type="bibr" rid="bib10">10</xref>]. Namely, we discuss how the boundary condition affects the structure of the discrete momenta and the changes of the spin orientation following the procedure in Refs.&#x00A0;[<xref ref-type="bibr" rid="bib40">40</xref>,<xref ref-type="bibr" rid="bib42">42</xref>]. However, our system proceeds with the general momentum (see also Refs.&#x00A0;[<xref ref-type="bibr" rid="bib28">28</xref>,<xref ref-type="bibr" rid="bib30">30</xref>,<xref ref-type="bibr" rid="bib31">31</xref>]).</p>
<sec id="sec3-1">
<label>3.1.</label>
<title>Discrete momenta</title>
<p>The boundary condition at the first plate <italic>x</italic><sub>3</sub> &#x003D; 0 is given by
<disp-formula id="equ9">
<label>(9)</label>
<tex-math id="TM0015" notation="LaTeX"><![CDATA[$$\begin{eqnarray}
i\gamma ^3\psi |_{x_3=0} =e^{-i\Theta \gamma ^5}\psi |_{x_3=0},
\end{eqnarray}$$]]></tex-math>
</disp-formula>which is obtained from Eq.&#x00A0;(<xref ref-type="disp-formula" rid="equ7">7</xref>) with the inward normal unit four-vector given as <italic>N<sub>&#x03BC;</sub></italic> &#x003D; (0, 0, 0, 1). It can be rewritten into two equivalent equations&#x00A0;as follows
<disp-formula id="equ10">
<label>(10)</label>
<tex-math id="TM0016" notation="LaTeX"><![CDATA[$$\begin{eqnarray}
i(\sigma _3+\sin \Theta I)\chi _2|_{ x_3=0}-\cos \Theta \chi _1|_{ x_3=0}=0,
\end{eqnarray}$$]]></tex-math>
</disp-formula>
<disp-formula id="equ11">
<label>(11)</label>
<tex-math id="TM0017" notation="LaTeX"><![CDATA[$$\begin{eqnarray}
i(\sigma _3-\sin \Theta I)\chi _1|_{ x_3=0}+\cos \Theta \chi _2|_{ x_3=0}=0,
\end{eqnarray}$$]]></tex-math>
</disp-formula>where <italic>&#x03C7;</italic><sub>1</sub> and <italic>&#x03C7;</italic><sub>2</sub> are the upper and lower two-component Dirac field, respectively. Applying the boundary conditions (<xref ref-type="disp-formula" rid="equ10">10</xref>) or (<xref ref-type="disp-formula" rid="equ11">11</xref>) to the positive frequency Dirac field (<xref ref-type="disp-formula" rid="update1673781413345">5</xref>), we obtain the relation of coefficients <italic>B</italic> and <italic>C</italic> at the first plate as
<disp-formula id="update1673781889659">
<label>(12)</label>
<tex-math id="TM0018" notation="LaTeX"><![CDATA[$$\begin{eqnarray}
\big [i(\sigma _3+\sin \Theta I) r\hat{\boldsymbol k}_{\mathrm{R}}\cdot {\boldsymbol \sigma }-\cos \Theta I\big ] B \chi _{\mathrm{R}} =- \big [i(\sigma _3+\sin \Theta I) r\hat{\boldsymbol k}_{\mathrm{L}}\cdot {\boldsymbol \sigma }-\cos \Theta I\big ] C \chi _{\mathrm{L}}.
\end{eqnarray}$$]]></tex-math>
</disp-formula>Below, we show that this relation is useful for investigating the discrete momenta and the changes of the spin orientation at the first plate.</p>
<p>We next employ the boundary condition at the second plate to know the behavior of discrete momenta. At the surface of the second plate <italic>x</italic><sub>3</sub> &#x003D; &#x2113;, the inward normal unit four-vector reads <italic>N</italic><sub>&#x03BC;</sub> &#x003D; (0, 0, 0, &#x2212;1). Then, the corresponding boundary condition is given by
<disp-formula id="equ13">
<label>(13)</label>
<tex-math id="TM0019" notation="LaTeX"><![CDATA[$$\begin{eqnarray}
-i\gamma ^3\psi |_{x_3=\ell } =e^{-i\Theta \gamma ^5}\psi |_{x_3=\ell },
\end{eqnarray}$$]]></tex-math>
</disp-formula>which leads to the following two equivalent equations
<disp-formula id="equ14">
<label>(14)</label>
<tex-math id="TM0020" notation="LaTeX"><![CDATA[$$\begin{eqnarray}
i(-\sigma _3+\sin \Theta I)\chi _2|_{ x_3=\ell }-\cos \Theta \chi _1|_{ x_3=\ell }=0,
\end{eqnarray}$$]]></tex-math>
</disp-formula>
<disp-formula id="equ15">
<label>(15)</label>
<tex-math id="TM0021" notation="LaTeX"><![CDATA[$$\begin{eqnarray}
i(-\sigma _3-\sin \Theta I)\chi _1|_{ x_3=\ell }+\cos \Theta \chi _2|_{ x_3=\ell }=0.
\end{eqnarray}$$]]></tex-math>
</disp-formula>Applying boundary conditions&#x00A0;(<xref ref-type="disp-formula" rid="equ14">14</xref>) or (<xref ref-type="disp-formula" rid="equ15">15</xref>) to the positive-frequency Dirac field (<xref ref-type="disp-formula" rid="update1673781413345">5</xref>), we have the relation as follows
<disp-formula id="update1673782013092">
<label>(16)</label>
<tex-math id="TM0022" notation="LaTeX"><![CDATA[$$\begin{eqnarray}
\big [i(-\sigma _3+\sin \Theta I) r\hat{\boldsymbol k}_{\mathrm{R}}\cdot {\boldsymbol \sigma }-\cos \Theta I\big ] e^{ik_3\ell } B \chi _{\mathrm{R}} =- \big [i(-\sigma _3+\sin \Theta I) r\hat{\boldsymbol k}_{\mathrm{L}}\cdot {\boldsymbol \sigma }-\cos \Theta I\big ] e^{-ik_3\ell } C \chi _{\mathrm{L}}.
\end{eqnarray}$$]]></tex-math>
</disp-formula>Note that two-component Dirac spinors <italic>&#x03C7;</italic><sub>R</sub> and <italic>&#x03C7;</italic><sub>L</sub> in Eq.&#x00A0;(<xref ref-type="disp-formula" rid="update1673782013092">16</xref>) will be the same as those in Eq.&#x00A0;(<xref ref-type="disp-formula" rid="update1673781889659">12</xref>) when the spin orientations are consistently reflected; namely, the reflected spin orientation at the second plate is the same as the incident spin orientation at the first plate (see Ref.&#x00A0;[<xref ref-type="bibr" rid="bib42">42</xref>] for the one-dimensional case).</p>
<p>Utilizing the relations given in Eqs.&#x00A0;(<xref ref-type="disp-formula" rid="update1673781889659">12</xref>) and (<xref ref-type="disp-formula" rid="update1673782013092">16</xref>), we are able to derive the constraint for the momentum as follows
<disp-formula id="equ17">
<label>(17)</label>
<tex-math id="TM0023" notation="LaTeX"><![CDATA[$$\begin{eqnarray}
m\ell \cos \Theta \sin (k_3 \ell )+k_3\ell \cos (k_3\ell )= 0.
\end{eqnarray}$$]]></tex-math>
</disp-formula>For the detailed derivation, see Appendix&#x00A0;<xref ref-type="app" rid="sec7">A</xref>. The solution for Eq.&#x00A0;(<xref ref-type="disp-formula" rid="equ17">17</xref>) shows that the momentum <italic>k</italic><sub>3</sub> must be discrete and depends on the chiral angle. It also shows that in our system, momenta <italic>k</italic><sub>1</sub> and <italic>k</italic><sub>2</sub> remain because the boundary conditions appear only at the <italic>x</italic><sub>3</sub>-axis in parallel with the (<italic>x, y</italic>)-plane, as mentioned in the previous section.</p>
<p>Next, we define <inline-formula><tex-math id="TM0024" notation="LaTeX"><![CDATA[$k^{\prime }_{3n}\equiv k_3\ell$]]></tex-math></inline-formula> with <italic>n</italic> &#x003D; 1, 2, 3, &#x2026; to denote the solution for Eq.&#x00A0;(<xref ref-type="disp-formula" rid="equ17">17</xref>). In comparison to the solution for the nonchiral case, we here have a factor of cos&#x2009;&#x0398; that contributes to determining the structure of the discrete momenta. However, when the chiral angle takes values as &#x0398; &#x003D; &#x03C0;/2, 3&#x03C0;/2, the discrete momenta have a nontrivial solution for all mass <italic>m</italic> as follows [<xref ref-type="bibr" rid="bib42">42</xref>],
<disp-formula id="equ18">
<label>(18)</label>
<tex-math id="TM0025" notation="LaTeX"><![CDATA[$$\begin{eqnarray}
k^{\prime }_{3n}={(2n-1)\pi \over 2},
\end{eqnarray}$$]]></tex-math>
</disp-formula>which is the same as the discrete momenta solution in the massless case <italic>m</italic> &#x003D; 0.</p>
<p>As has been discussed in previous work [<xref ref-type="bibr" rid="bib42">42</xref>], there are two cases when analyzing the solution for Eq.&#x00A0;(<xref ref-type="disp-formula" rid="equ17">17</xref>). For the case of light mass <italic>m</italic><sup>&#x2032;</sup>( &#x2261; <italic>m</italic>&#x2113;) &#x226A; 1, the solution for the discrete momenta is approximately given by
<disp-formula id="equ19">
<label>(19)</label>
<tex-math id="TM0026" notation="LaTeX"><![CDATA[$$\begin{eqnarray}
k^{\prime }_{3n, l}\simeq {(2n-1)\pi \over 2}+ {2 m^{\prime }\cos \Theta \over (2n-1)\pi }.
\end{eqnarray}$$]]></tex-math>
</disp-formula>We note that the first term of the above solution covers the solution of Eq.&#x00A0;(<xref ref-type="disp-formula" rid="equ18">18</xref>) while the second term gives the correction to the discrete momenta <inline-formula><tex-math id="TM0027" notation="LaTeX"><![CDATA[$k^{\prime }_{3n}$]]></tex-math></inline-formula> depending on the mass <italic>m</italic> and the chiral angle &#x0398;. Whereas in the case of heavy mass <italic>m</italic><sup>&#x2032;</sup> &#x226B; 1, the solution for discrete momenta is approximately given by
<disp-formula id="equ20">
<label>(20)</label>
<tex-math id="TM0028" notation="LaTeX"><![CDATA[$$\begin{eqnarray}
k^{\prime }_{3n, h}\simeq n\pi -{n\pi \over m^{\prime }\cos \Theta }.
\end{eqnarray}$$]]></tex-math>
</disp-formula>In Eq.&#x00A0;(<xref ref-type="disp-formula" rid="equ20">20</xref>), the first term covers the discrete momenta for the Schr&#x00F6;dinger equation&#x00A0;in an infinite potential well under the Dirichlet boundary condition [<xref ref-type="bibr" rid="bib42">42</xref>]. Since <italic>m</italic><sup>&#x2032;</sup> depends on &#x2113;, the case of <italic>m</italic><sup>&#x2032;</sup> &#x226A; 1 and <italic>m</italic><sup>&#x2032;</sup> &#x226B; 1 correspond to small and large distances between two plates, respectively. In other words, one can write the distance between two plates as a function of the Compton wavelength that determines whether the confinement system approaches ultra- or nonrelativistic limits [<xref ref-type="bibr" rid="bib35">35</xref>,<xref ref-type="bibr" rid="bib36">36</xref>].</p>
</sec>
<sec id="sec3-2">
<label>3.2.</label>
<title>Change of spin orientation and energy gap</title>
<p>The two-component spinor <italic>&#x03C7;</italic><sub>R</sub> can be connected to <italic>&#x03C7;</italic><sub>L</sub> using a rotation operator in spin space, which is determined by the boundary condition. Once we know the structure of one of them, we will obtain complete information on the spin orientations for both Dirac field components (<xref ref-type="disp-formula" rid="equ4">4</xref>) and (<xref ref-type="disp-formula" rid="update1673781413345">5</xref>). The rotation operator in spin space is given by [<xref ref-type="bibr" rid="bib40">40</xref>]
<disp-formula id="equ21">
<label>(21)</label>
<tex-math id="TM0029" notation="LaTeX"><![CDATA[$$\begin{eqnarray}
{\cal U} =e^{i\varsigma }\left[\cos \left({\varphi \over 2}\right)I-i\sin \left({\varphi \over 2}\right) \hat{\boldsymbol n} \cdot {\boldsymbol \sigma }\right],
\end{eqnarray}$$]]></tex-math>
</disp-formula>where <italic>e</italic><sup><italic>i&#x03C2;</italic></sup> denotes a pure phase, <italic>&#x03C6;</italic> is the rotation angle, and <inline-formula><tex-math id="TM0030" notation="LaTeX"><![CDATA[$\hat{\boldsymbol n}$]]></tex-math></inline-formula> represents the unit rotation axis generated by the reflection with the plate.</p>
<p>At the first plate, from the relation given in Eq.&#x00A0;(<xref ref-type="disp-formula" rid="update1673781889659">12</xref>), we have <inline-formula><tex-math id="TM0031" notation="LaTeX"><![CDATA[$\chi _{\mathrm{R}}={\cal U}^{(1)}_{\mathrm{R}} \chi _{\mathrm{L}}$]]></tex-math></inline-formula> with <inline-formula><tex-math id="TM0032" notation="LaTeX"><![CDATA[${\cal U}^{(1)}_R$]]></tex-math></inline-formula> is the rotation operator in spin space generated by the reflection with the first plate given as
<disp-formula id="update1673782540873">
<label>(22)</label>
<tex-math id="TM0033" notation="LaTeX"><![CDATA[$$\begin{eqnarray}
{\cal U}^{(1)}_{\mathrm{R}}={C\over B}{\cos \Theta \big [(k^{\prime 2}_{3n}/\ell ^2+m E_n+m^2)I+i(k^{\prime }_{3n}/\ell )(k_2\sigma _1-k_1 \sigma _2+(m+E_n)\tan \Theta \sigma _3)\big ]\over (m+E_n)(ik^{\prime }_{3n}/\ell -m\cos \Theta )},
\end{eqnarray}$$]]></tex-math>
</disp-formula>where we have used the discrete momenta <inline-formula><tex-math id="TM0034" notation="LaTeX"><![CDATA[$k^{\prime }_{3n}$]]></tex-math></inline-formula> and the eigen energies
<disp-formula id="equ23">
<label>(23)</label>
<tex-math id="TM0035" notation="LaTeX"><![CDATA[$$\begin{eqnarray}
E_n=\sqrt{k^2_1+k^2_2+\bigg ({k^{\prime }_{3n}\over \ell }\bigg )^2+m^2}.
\end{eqnarray}$$]]></tex-math>
</disp-formula>Taking the correspondence between the obtained rotation operator (<xref ref-type="disp-formula" rid="update1673782540873">22</xref>) and the general formulation in Eq.&#x00A0;(<xref ref-type="disp-formula" rid="equ21">21</xref>), we have
<disp-formula id="equ24">
<label>(24)</label>
<tex-math id="TM0036" notation="LaTeX"><![CDATA[$$\begin{eqnarray}
e^{i\varsigma ^{(1)} }\cos ({\varphi ^{(1)} \over 2})I ={C\over B}{\cos \Theta (k^{\prime 2}_{3n}/\ell ^2+m E_n+m^2)I\over (m+E_n)(ik^{\prime }_{3n}/\ell -m\cos \Theta )} ,
\end{eqnarray}$$]]></tex-math>
</disp-formula>
<disp-formula id="equ25">
<label>(25)</label>
<tex-math id="TM0037" notation="LaTeX"><![CDATA[$$\begin{eqnarray}
e^{i\varsigma ^{(1)}}\sin \left({\varphi ^{(1)} \over 2}\right)\hat{\boldsymbol n}^{(1)} \cdot {\boldsymbol \sigma } =-{C\over B}{\cos \Theta (k^{\prime }_{3n}/\ell ) \big [ k_2\sigma _1-k_1 \sigma _2+(m+E_n)\tan \Theta \sigma _3\big ]\over (m+E_n)(ik^{\prime }_{3n}/\ell -m\cos \Theta )} ,
\end{eqnarray}$$]]></tex-math>
</disp-formula>which lead to the expression of the rotation angle and its rotation axis at the first plate as follows<xref ref-type="fn" rid="fn1"><sup>1</sup></xref>
<disp-formula id="equ26">
<label>(26)</label>
<tex-math id="TM0038" notation="LaTeX"><![CDATA[$$\begin{eqnarray}
\tan \left({\varphi ^{(1)}\over 2}\right)=-{(k^{\prime }_{3n}/\ell )\sqrt{(2m^2+2mE_n+k^{\prime 2}_{3n}/\ell ^2 )\tan ^2\Theta +{\boldsymbol k}^2_\perp \sec ^2\Theta }\over (k^{\prime 2}_{3n}/\ell ^2+m E_n+m^2)},
\end{eqnarray}$$]]></tex-math>
</disp-formula>
<disp-formula id="equ27">
<label>(27)</label>
<tex-math id="TM0039" notation="LaTeX"><![CDATA[$$\begin{eqnarray}
\hat{\boldsymbol n}^{(1)}={k_2\hat{x}_1-k_1 \hat{x}_2+(m+E_n)\tan \Theta \hat{x}_3 \over \sqrt{(2m^2+2mE_n+k^{\prime 2}_{3n}/\ell ^2 )\tan ^2\Theta +{\boldsymbol k}^2_\perp \sec ^2\Theta }},
\end{eqnarray}$$]]></tex-math>
</disp-formula>respectively, where <inline-formula><tex-math id="TM0040" notation="LaTeX"><![CDATA[${\boldsymbol k}_\perp (\equiv \sqrt{k^2_1+k^2_2})$]]></tex-math></inline-formula> is the perpendicular momentum to the normal surface of the plates. It can be seen that the roles of the pure phase <inline-formula><tex-math id="TM0041" notation="LaTeX"><![CDATA[$e^{i\varsigma ^{(1)}}$]]></tex-math></inline-formula> can be cancelled out from the rotation angle and its axis. In the case of <inline-formula><tex-math id="TM0042" notation="LaTeX"><![CDATA[${\boldsymbol k}_\perp \ne 0$]]></tex-math></inline-formula>, the reflected spin orientation changes for arbitrary chiral angles (both chiral and nonchiral cases). However, for the case of <inline-formula><tex-math id="TM0043" notation="LaTeX"><![CDATA[${\boldsymbol k}_\perp =0$]]></tex-math></inline-formula>, it does not change for &#x0398; &#x003D; 0, &#x03C0; (see, for example, Refs.&#x00A0;[<xref ref-type="bibr" rid="bib30">30</xref>,<xref ref-type="bibr" rid="bib31">31</xref>] for the discussion on the relation of <italic>&#x03C7;</italic><sub>R</sub> and <italic>&#x03C7;</italic><sub>L</sub> under nonchiral boundary conditions, where <italic>B</italic> &#x003D; <italic>C</italic> was used).</p>
<p>At the second plate, from the relation provided in Eq.&#x00A0;(<xref ref-type="disp-formula" rid="update1673782013092">16</xref>), we have <inline-formula><tex-math id="TM0044" notation="LaTeX"><![CDATA[$\chi _{\mathrm{L}}={\cal U}^{(2)}_{\mathrm{L}} \chi _{\mathrm{R}},$]]></tex-math></inline-formula> where <inline-formula><tex-math id="TM0045" notation="LaTeX"><![CDATA[${\cal U}^{(2)}_{\mathrm{L}}$]]></tex-math></inline-formula> is the rotation operator generated by the reflection with the second plate given by
<disp-formula id="update1673782809430">
<label>(28)</label>
<tex-math id="TM0046" notation="LaTeX"><![CDATA[$$\begin{eqnarray}
{\cal U}^{(2)}_{\mathrm{L}}={B e^{2ik^{\prime }_{3n}}\over C} {\cos \Theta \big [(k^{\prime 2}_{3n}/\ell ^2+m E_n+m^2)I-i(k^{\prime }_{3n}/\ell )(k_2\sigma _1-k_1 \sigma _2+(m+E_n)\tan \Theta \sigma _3)\big ]\over (m+E_n)(ik^{\prime }_{3n}/\ell -m\cos \Theta )}.
\end{eqnarray}$$]]></tex-math>
</disp-formula>Again, taking the correspondence between the obtained rotation operator (<xref ref-type="disp-formula" rid="update1673782809430">28</xref>) and general formulation Eq.&#x00A0;(<xref ref-type="disp-formula" rid="equ21">21</xref>), we obtain
<disp-formula id="equ29">
<label>(29)</label>
<tex-math id="TM0047" notation="LaTeX"><![CDATA[$$\begin{eqnarray}
e^{i\varsigma ^{(2)} }\cos \left({\varphi ^{(2)} \over 2}\right)I ={B e^{2ik^{\prime }_{3n}}\over C}{\cos \Theta (k^{\prime 2}_{3n}/\ell ^2+mE_n+m^2)I\over (m+E_n)(i(k^{\prime }_{3n}/\ell )-m\cos \Theta )} ,
\end{eqnarray}$$]]></tex-math>
</disp-formula>
<disp-formula id="equ30">
<label>(30)</label>
<tex-math id="TM0048" notation="LaTeX"><![CDATA[$$\begin{eqnarray}
e^{i\varsigma ^{(2)}}\sin ({\varphi ^{(2)} \over 2})\hat{\boldsymbol n}^{(2)} \cdot {\boldsymbol \sigma } ={B e^{2ik^{\prime }_{3n}}\over C}{\cos \Theta (k^{\prime }_{3n}/\ell ) \big [ k_2\sigma _1-k_1 \sigma _2+(m+E_n)\tan \Theta \sigma _3\big ]\over (m+E_n)(ik^{\prime }_{3n}/\ell -m\cos \Theta )}.
\end{eqnarray}$$]]></tex-math>
</disp-formula>It is then straightforward to show that the rotation angle and the rotation axis are given by
<disp-formula id="equ31">
<label>(31)</label>
<tex-math id="TM0049" notation="LaTeX"><![CDATA[$$\begin{eqnarray}
\tan \left({\varphi ^{(2)}\over 2}\right) = -{(k^{\prime }_{3n}/\ell )\sqrt{(2m^2+2mE_n+k^{\prime 2}_{3n}/\ell ^2 )\tan ^2\Theta +{\boldsymbol k}^2_\perp \sec ^2\Theta }\over (k^{\prime 2}_{3n}/\ell ^2+mE_n+m^2)},
\end{eqnarray}$$]]></tex-math>
</disp-formula>
<disp-formula id="equ32">
<label>(32)</label>
<tex-math id="TM0050" notation="LaTeX"><![CDATA[$$\begin{eqnarray}
\hat{\boldsymbol n}^{(2)}={-k_2\hat{x}_1+k_1 \hat{x}_2-(m+E_n)\tan \Theta \hat{x}_3 \over \sqrt{{\boldsymbol k}^2_\perp \sec ^2\Theta +(2m^2+2mE_n+k^{\prime 2}_{3n}/\ell ^2 )\tan ^2\Theta }},
\end{eqnarray}$$]]></tex-math>
</disp-formula>respectively<xref ref-type="fn" rid="fn2"><sup>2</sup></xref>.</p>
<p>From the above results, one can show that <inline-formula><tex-math id="TM0051" notation="LaTeX"><![CDATA[$\tan ({\varphi ^{(1)}\over 2})=\tan ({\varphi ^{(2)}\over 2})$]]></tex-math></inline-formula> and <inline-formula><tex-math id="TM0052" notation="LaTeX"><![CDATA[$\hat{\boldsymbol n}^{(1)}=-\hat{\boldsymbol n}^{(2)}$]]></tex-math></inline-formula>, which means the reflection at the first plate generates the same rotation angle as at the second plate, but their rotation axes are in the opposite direction. Recalling that at the first and second plates, we have <inline-formula><tex-math id="TM0053" notation="LaTeX"><![CDATA[$\chi _{\mathrm{R}}={\cal U}^{(1)}\chi _{\mathrm{L}}$]]></tex-math></inline-formula> and <inline-formula><tex-math id="TM0054" notation="LaTeX"><![CDATA[$\chi _{\mathrm{L}}={\cal U}^{(2)}\chi _{\mathrm{R}}$]]></tex-math></inline-formula>, respectively, which implies <inline-formula><tex-math id="TM0055" notation="LaTeX"><![CDATA[${\cal U}^{(1)}{\cal U}^{(2)}={\cal U}^{(2)}{\cal U}^{(1)}=I$]]></tex-math></inline-formula> for the allowed momenta (<xref ref-type="disp-formula" rid="equ17">17</xref>) under the reflection in a consistent way.</p>
<p>We next discuss the energy gap between two states, focusing on the case of <italic>m</italic><sup>&#x2032;</sup>( &#x2261; <italic>m</italic>&#x2113;) &#x226A; 1 with <inline-formula><tex-math id="TM0056" notation="LaTeX"><![CDATA[${\boldsymbol k}_\perp =0$]]></tex-math></inline-formula>. Using Eq.&#x00A0;(<xref ref-type="disp-formula" rid="equ23">23</xref>), the energy gap is computed as
<disp-formula id="equ33">
<label>(33)</label>
<tex-math id="TM0057" notation="LaTeX"><![CDATA[$$\begin{eqnarray}
\Delta E=E_{n+1}-E_n = {\pi \over \ell } - {4 m\cos \Theta \over (4n^2-1)\pi },
\end{eqnarray}$$]]></tex-math>
</disp-formula>where the value of &#x2113; is fixed. The role of the chiral angle appears in the second term and can be understood as the energy gap correction. We note that this correction vanishes for &#x0398; &#x003D; &#x03C0;/2 and 3&#x03C0;/2. We can also compute the bound of the energy gap as
<disp-formula id="equ34">
<label>(34)</label>
<tex-math id="TM0058" notation="LaTeX"><![CDATA[$$\begin{eqnarray}
{\pi \over \ell } - {4 m\over (4n^2-1)\pi } \le \Delta E \le {\pi \over \ell }.
\end{eqnarray}$$]]></tex-math>
</disp-formula>From the above equation, the maximum correction of the lower bound for the energy gap is given by <inline-formula><tex-math id="TM0059" notation="LaTeX"><![CDATA[$- {4 m\over (4n^2-1)\pi }$]]></tex-math></inline-formula>.</p>
</sec>
</sec>
<sec id="sec4">
<label>4.</label>
<title>Casimir energy</title>
<p>In this section, we calculate the Casimir energy of a massive Dirac fermion confined between two parallel plates under the chiral MIT boundary conditions. In the presence of this boundary condition, the vacuum energy is given by,
<disp-formula id="update1673783274828">
<label>(35)</label>
<tex-math id="TM0060" notation="LaTeX"><![CDATA[$$\begin{eqnarray}
E_0=-{L^2\over 2\pi ^2}\int ^{\infty }_{-\infty }{\mathrm{d}}k_1\int ^{\infty }_{-\infty }{\mathrm{d}}k_2\sum ^\infty _{n=1}\sqrt{k^2_1+k^2_2+\bigg ({k^{\prime }_{3n}\over \ell }\bigg )^2+m^2},
\end{eqnarray}$$]]></tex-math>
</disp-formula>where <italic>L</italic><sup>2</sup> is the surface area of the plate and the discrete momenta <inline-formula><tex-math id="TM0061" notation="LaTeX"><![CDATA[$k^{\prime }_{3n}\equiv k_{3}\ell$]]></tex-math></inline-formula> satisfies the momentum constraint in Eq.&#x00A0;(<xref ref-type="disp-formula" rid="equ17">17</xref>). In the above expression, we have used the eigen energies of a Dirac field given in Eq.&#x00A0;(<xref ref-type="disp-formula" rid="equ23">23</xref>). In fact, the vacuum energy in Eq.&#x00A0;(<xref ref-type="disp-formula" rid="update1673783274828">35</xref>) is divergent. Then, to solve this problem, one can use an Abel&#x2013;Plana-like summation [<xref ref-type="bibr" rid="bib52">52</xref>] following the procedure used in Refs.&#x00A0;[<xref ref-type="bibr" rid="bib30">30</xref>,<xref ref-type="bibr" rid="bib31">31</xref>] as follows,
<disp-formula id="update1673783361565">
<label>(36)</label>
<tex-math id="TM0062" notation="LaTeX"><![CDATA[$$\begin{eqnarray}
\sum ^{\infty }_{n=1} {\pi f(k^{\prime }_{3n})\over \big (1 -{\sin (2 k^{\prime }_{3n})\over 2 k^{\prime }_{3n}}\big )} =-{\pi m^{\prime }\cos \Theta f(0) \over 2(m^{\prime }\cos \Theta +1)}+\int ^\infty _0 {\mathrm{d}}z f(z) -i\int ^\infty _0 {\mathrm{d}}t {f(it)-f(-it)\over {t+m^{\prime }\cos \Theta \over t-m^{\prime }\cos \Theta }e^{2t}+1}.
\end{eqnarray}$$]]></tex-math>
</disp-formula>Considering the denominator of the left-hand side of Eq.&#x00A0;(<xref ref-type="disp-formula" rid="update1673783361565">36</xref>), from the momentum constraint given in Eq.&#x00A0;(<xref ref-type="disp-formula" rid="equ17">17</xref>), we may replace it with the following relation
<disp-formula id="equ37">
<label>(37)</label>
<tex-math id="TM0063" notation="LaTeX"><![CDATA[$$\begin{eqnarray}
1 -{\sin (2 k^{\prime }_{3n})\over 2 k^{\prime }_{3n}}= 1+{m^{\prime } \cos \Theta \over (m^{\prime }\cos \Theta )^2+k^{\prime 2}_{3n}}.
\end{eqnarray}$$]]></tex-math>
</disp-formula>Then, the above vacuum energy can be rewritten as follows
<disp-formula id="update1673783447283">
<label>(38)</label>
<tex-math id="TM0064" notation="LaTeX"><![CDATA[$$\begin{eqnarray}
E_0=-{L^2\over 2\pi ^3 \ell }\!\int ^{\infty }_{-\infty }{\mathrm{d}}k_1\!\int ^{\infty }_{-\infty }{\mathrm{d}}k_2\bigg (\!-{\pi m^{\prime }\cos \Theta f(0) \over 2(m^{\prime }\cos \Theta +1)}+\!\int ^\infty _0 {\mathrm{d}}z f(z) -i\!\int ^\infty _0 {\mathrm{d}}t {f(it)-f(-it)\over {t+m^{\prime }\cos \Theta \over t-m^{\prime }\cos \Theta }e^{2t}+1}\!\bigg ),
\end{eqnarray}$$]]></tex-math>
</disp-formula>where the function <italic>f</italic>(<italic>z</italic>) is defined as
<disp-formula id="equ39">
<label>(39)</label>
<tex-math id="TM0065" notation="LaTeX"><![CDATA[$$\begin{eqnarray}
f(z)=\sqrt{\left(k^2_1+k^2_2\right)\ell ^2+z^2+m^{\prime 2}} \bigg (1+{m^{\prime } \cos \Theta \over (m^{\prime }\cos \Theta )^2+z^2}\bigg ).
\end{eqnarray}$$]]></tex-math>
</disp-formula>In the next step, we can separate the above vacuum energy in Eq.&#x00A0;(<xref ref-type="disp-formula" rid="update1673783447283">38</xref>) into three terms as follows,
<disp-formula id="equ40">
<label>(40)</label>
<tex-math id="TM0066" notation="LaTeX"><![CDATA[$$\begin{eqnarray}
E_0=\ell E^{(0)}_0+2 E^{(1)}_0+\Delta E_0.
\end{eqnarray}$$]]></tex-math>
</disp-formula><inline-formula><tex-math id="TM0067" notation="LaTeX"><![CDATA[$E^{(0)}_0$]]></tex-math></inline-formula> in the first term of Eq.&#x00A0;(<xref ref-type="disp-formula" rid="equ40">40</xref>) reads
<disp-formula id="update1673783539898">
<label>(41)</label>
<tex-math id="TM0068" notation="LaTeX"><![CDATA[$$\begin{eqnarray}
E^{(0)}_0=-{L^2\over 4\pi ^3}\int ^{\infty }_{-\infty }{\mathrm{d}}k_1\int ^{\infty }_{-\infty }{\mathrm{d}}k_2 \int ^{\infty }_{-\infty } {\mathrm{d}}k_3 \sqrt{k^2_1+k^2_2+k^2_3+m^2},
\end{eqnarray}$$]]></tex-math>
</disp-formula>which represents the vacuum energy in the absence of the boundary conditions. The contribution of <inline-formula><tex-math id="TM0069" notation="LaTeX"><![CDATA[$E^{(1)}_0$]]></tex-math></inline-formula> in the second term of Eq.&#x00A0;(<xref ref-type="disp-formula" rid="equ40">40</xref>) is given by
<disp-formula id="update1673783582884">
<label>(42)</label>
<tex-math id="TM0070" notation="LaTeX"><![CDATA[$$\begin{eqnarray}
E^{(1)}_0=-{L^2\over 4\pi ^3}\int ^{\infty }_{-\infty }{\mathrm{d}}k_1\int ^{\infty }_{-\infty }{\mathrm{d}}k_2 \!\Biggr [-{\pi \over 2}\sqrt{k^2_1+k^2_2+m^2}+m\cos \Theta \int ^{\infty }_0 {\mathrm{d}}z {\sqrt{z^2+k^2_1+k^2_2+m^2}\over m^2\cos ^2\Theta +z^2}\!\Biggr ],
\end{eqnarray}$$]]></tex-math>
</disp-formula>which is the vacuum energy in the presence of one plate only and does not contribute to the Casimir force. Then, the Casimir energy is related to the last term of Eq.&#x00A0;(<xref ref-type="disp-formula" rid="equ40">40</xref>), <italic>E</italic><sub>Cas.</sub> &#x2261; &#x0394;<italic>E</italic><sub>0</sub>, and is given as
<disp-formula id="update1673783652155">
<label>(43)</label>
<tex-math id="TM0071" notation="LaTeX"><![CDATA[$$\begin{eqnarray}
E_{\rm Cas.}={iL^2\over 2\pi ^3 \ell }\int ^{\infty }_{-\infty }{\mathrm{d}}k_1\int ^{\infty }_{-\infty }{\mathrm{d}}k_2\int ^\infty _0 {\mathrm{d}}t {f(it)-f(-it)\over {t+m^{\prime }\cos \Theta \over t-m^{\prime }\cos \Theta }e^{2t}+1}.
\end{eqnarray}$$]]></tex-math>
</disp-formula>By using Eq.&#x00A0;(<xref ref-type="disp-formula" rid="equ39">39</xref>), the above Casimir energy can be rewritten as,
<disp-formula id="update1673783695239">
<label>(44)</label>
<tex-math id="TM0072" notation="LaTeX"><![CDATA[$$\begin{eqnarray}
E_{\rm Cas.}&=&{iL^2 \ell \over 2\pi ^3 }\int ^{\infty }_{-\infty }{\mathrm{d}}k_1\int ^{\infty }_{-\infty }{\mathrm{d}}k_2\int ^\infty _0 {\mathrm{d}}u {u-m\cos \Theta \over (u+m\cos \Theta )e^{2\ell u}+u-m\cos \Theta } \\
&& \times \bigg (1+{m\cos \Theta \over \ell m^2\cos \Theta -\ell u^2}\bigg ) \bigg [\sqrt{(iu)^2+k^2_1+k^2_2+m^2}-\sqrt{(-iu)^2+k^2_1+k^2_2+m^2}\bigg ],
\end{eqnarray}$$]]></tex-math>
</disp-formula>where we have changed the variable, <italic>t</italic> &#x003D; &#x2113;<italic>u</italic>. It is convenient to separate the integration over <italic>u</italic> in Eq.&#x00A0;(<xref ref-type="disp-formula" rid="update1673783695239">44</xref>) into two intervals. The first interval, i.e. from 0 to <inline-formula><tex-math id="TM0073" notation="LaTeX"><![CDATA[$\sqrt{k^2_1+k^2_2+m^2}$]]></tex-math></inline-formula> vanishes, whereas the second interval, i.e. from <inline-formula><tex-math id="TM0074" notation="LaTeX"><![CDATA[$\sqrt{k^2_1+k^2_2+m^2}$]]></tex-math></inline-formula> to &#x221E;, remains. Then, the Casimir energy reads
<disp-formula id="update1673783734617">
<label>(45)</label>
<tex-math id="TM0075" notation="LaTeX"><![CDATA[$$\begin{eqnarray}
E_{\rm Cas.}&=&{-L^2 \over \pi ^3 }\int ^{\infty }_{-\infty }{\mathrm{d}}k_1\int ^{\infty }_{-\infty }{\mathrm{d}}k_2\int ^\infty _{\sqrt{k^2_1+k^2_2+m^2}} {\mathrm{d}}u \sqrt{u^2-k^2_1-k^2_2-m^2} \\
&&\times\, \bigg ({ \ell (u-m\cos \Theta )-m\cos \Theta /(m\cos \Theta +u) \over (u+m\cos \Theta )e^{2\ell u}+(u-m\cos \Theta )}\bigg ).
\end{eqnarray}$$]]></tex-math>
</disp-formula>To further proceed with the above integration, we then use the following formula [<xref ref-type="bibr" rid="bib30">30</xref>]
<disp-formula id="update1673783792578">
<label>(46)</label>
<tex-math id="TM0076" notation="LaTeX"><![CDATA[$$\begin{eqnarray}
\int _{-\infty }^{\infty } {\mathrm{d}}{\boldsymbol k}_\perp \int ^\infty _{\sqrt{{\boldsymbol k}^2_\perp +c^2}} {\mathrm{d}}z(z^2-{\boldsymbol k}^2_\perp -c^2)^{(s+1)/2} f(z)&=&{\pi ^{p/2}\Gamma ((s+3)/2)\over \Gamma ((p+s+3)/2)} \\
&&\times\, \int _c^\infty {\mathrm{d}}x (x^2-c^2)^{(p+s+1)/2}f(x),
\end{eqnarray}$$]]></tex-math>
</disp-formula>where <italic>p</italic> denotes the number of components of the spatial perpendicular momenta (in our case, we have <italic>p</italic> &#x003D; 2). Then, the Casimir energy becomes
<disp-formula id="update1673783863243">
<label>(47)</label>
<tex-math id="TM0077" notation="LaTeX"><![CDATA[$$\begin{equation}
E_{\rm Cas.}={-L^2 \over \pi ^3}{\pi \Gamma (3/2)\over \Gamma (5/2)} \int ^\infty _m {\mathrm{d}}x (x^2-m^2)^{3/2} \bigg ({\ell (x-m\cos \Theta )-m\cos \Theta /(m\cos \Theta +x) \over (x+m\cos \Theta )e^{2\ell x}+(x-m\cos \Theta )}\bigg ).
\end{equation}$$]]></tex-math>
</disp-formula>We next rewrite the following factor
<disp-formula id="update1673783899890">
<label>(48)</label>
<tex-math id="TM0078" notation="LaTeX"><![CDATA[$$\begin{eqnarray}
{\ell (x-m\cos \Theta )-m\cos \Theta /(m\cos \Theta +x) \over (x+m\cos \Theta )e^{2\ell x}+(x-m\cos \Theta )}=-{1\over 2}{{\mathrm{d}}\over {\mathrm{d}}x}\ln {\bigg (1+{x-m\cos \Theta \over x+m\cos \Theta }e^{-2\ell x}\bigg )}
\end{eqnarray}$$]]></tex-math>
</disp-formula>and introduce a new variable <italic>y</italic> &#x003D; &#x2113;<italic>x</italic> &#x2212; <italic>m</italic><sup>&#x2032;</sup>. The Casimir energy now reads
<disp-formula id="update1673783942382">
<label>(49)</label>
<tex-math id="TM0079" notation="LaTeX"><![CDATA[$$\begin{eqnarray}
E_{\rm Cas.}={-L^2 \over \pi ^2 \ell ^3 } {2\over 3} \int ^\infty _0 {\mathrm{d}}y (y^2+2y m^{\prime })^{3/2} {-1\over 2}{{\mathrm{d}}\over {\mathrm{d}}y}\ln {\bigg (1+{y+ m^{\prime }(1-\cos \Theta )\over y+ m^{\prime }(1+\cos \Theta )}e^{-2(y+m^{\prime })}\bigg )}.
\end{eqnarray}$$]]></tex-math>
</disp-formula>Performing integration by parts in Eq.&#x00A0;(<xref ref-type="disp-formula" rid="update1673783942382">49</xref>), we have a simpler form of the Casimir energy as
<disp-formula id="update1673783971364">
<label>(50)</label>
<tex-math id="TM0080" notation="LaTeX"><![CDATA[$$\begin{eqnarray}
E_{\rm Cas.}={-L^2 \over \pi ^2 \ell ^3 }\int ^\infty _0 {\mathrm{d}}y (y+m^{\prime }) \sqrt{y(y+2 m^{\prime })}\ln {\bigg (1+{y+ m^{\prime }(1-\cos \Theta )\over y+ m^{\prime }(1+\cos \Theta )}e^{-2(y+m^{\prime })}\bigg )}.
\end{eqnarray}$$]]></tex-math>
</disp-formula>In what follows, we will discuss the Casimir energy based on Eq.&#x00A0;(<xref ref-type="disp-formula" rid="update1673783971364">50</xref>). The left panel of Fig.&#x00A0;<xref ref-type="fig" rid="fig2">2</xref> depicts the behavior of the Casimir energy as a function of the chiral angle &#x0398; and the parameter <italic>m</italic><sup>&#x2032;</sup>( &#x2261; <italic>m</italic>&#x2113;), while the right panel demonstrates the Casimir energy as a function of the parameter <italic>m</italic><sup>&#x2032;</sup> for several values of the chiral angle. In both panels, we have used a fixed distance between the plates. In general, one can see that the Casimir energy has symmetric shapes with respect to the chiral angle &#x0398; &#x003D; &#x03C0;. In the case of the light mass, <italic>m</italic><sup>&#x2032;</sup> &#x226A; 1, the right panel of Fig.&#x00A0;<xref ref-type="fig" rid="fig2">2</xref> is approximately given by the linear function, as shown below. In the case of the heavy mass, <italic>m</italic><sup>&#x2032;</sup> &#x226B; 1, the Casimir energy tends to zero. In the massless case, Fig.&#x00A0;<xref ref-type="fig" rid="fig2">2</xref> shows that the Casimir energy gives the same value for any chiral angle; it is explicitly given by
<disp-formula id="update1674819697137">
<label>(51)</label>
<tex-math id="TM0081" notation="LaTeX"><![CDATA[$$\begin{eqnarray}
E_{\rm Cas.}={-L^2 \over \pi^2 \ell^3 } \int^\infty_0 dy y^2\ln (1+e^{-2y})=-{7 L^2\pi^2\over 2880 \ell^3},
\end{eqnarray}$$]]></tex-math>
</disp-formula>which is consistent with that of Ref.&#x00A0;[<xref ref-type="bibr" rid="bib34">34</xref>]. Both right and left panels show that the maximum contribution is given by the chiral angle &#x0398; &#x003D; &#x03C0;, while the minimum contribution is given by &#x0398; &#x003D; 0 (nonchiral case).</p>
<fig id="fig2" position="float">
<label>Fig. 2.</label>
<caption><p>The Casimir energy per plate area. The left panel shows the Casimir energy as a function of the chiral angle &#x0398; and dimensionless parameter <italic>m</italic><sup>&#x2032;</sup>( &#x2261; <italic>m</italic>&#x2113;). In the right panel, the Casimir energy is demonstrated as a function of the parameter <italic>m</italic><sup>&#x2032;</sup> for various values of the chiral angle. We used a fixed distance between the plates of &#x2113; &#x003D; 1/5&#x00A0;&#x03BC;m and a fixed plate size of <italic>L</italic><sup>2</sup> &#x003D; 1&#x00A0;cm<sup>2</sup>. The curves show that in the massless case, the Casimir energy for all chiral angles gives the same value, which is analytically given in Eq.&#x00A0;(<xref ref-type="disp-formula" rid="update1674819697137">51</xref>). They also show that the chiral angle &#x0398; &#x003D; &#x03C0; gives maximum contribution. The role of the chiral angle changes depending on the mass <italic>m</italic> and distance between the plates &#x2113;.</p></caption>
<graphic xmlns:xlink="http://www.w3.org/1999/xlink" xlink:href="ptac172fig2.jpg" mimetype="image"/>
</fig>
<p>Figure&#x00A0;<xref ref-type="fig" rid="fig3">3</xref> plots the ratio of the Casimir energy for an arbitrary chiral case to the nonchiral case. The curves show that the ratio is maximum when the chiral angle takes the value &#x0398; &#x003D; &#x03C0;. This ratio increases as the parameter <italic>m</italic><sup>&#x2032;</sup> becomes larger. Since the Casimir energy is symmetric as a function of the chiral angle, the ratio <italic>E</italic><sub>Cas.</sub>(<italic>m</italic><sup>&#x2032;</sup>, &#x0398;)/<italic>E</italic><sub>Cas.</sub>(<italic>m</italic><sup>&#x2032;</sup>, 0) is also symmetric with respect to &#x0398; &#x003D; &#x03C0; (see the right panel of Fig.&#x00A0;<xref ref-type="fig" rid="fig3">3</xref>).</p>
<fig id="fig3" position="float">
<label>Fig. 3.</label>
<caption><p>The ratio of the Casimir energy for an arbitrary chiral case to the nonchiral case. The left panel shows the curves as a function of the parameter <italic>m</italic><sup>&#x2032;</sup> for several values of the chiral angle. The right panel shows the curves as a function of the chiral angle for a given parameter <italic>m</italic><sup>&#x2032;</sup>.</p></caption>
<graphic xmlns:xlink="http://www.w3.org/1999/xlink" xlink:href="ptac172fig3.jpg" mimetype="image"/>
</fig>
<p>Figure&#x00A0;<xref ref-type="fig" rid="fig4">4</xref> plots the Casimir energy as a function of the distance between the plates &#x2113;. The curves in the left panel show that the Casimir energy of a massive Dirac fermion approaches the massless case as the reduction of its mass. From the right panel, one can see that the Casimir energy in the nonchiral case decays faster than in the chiral case. Meanwhile, the slowest decaying occurs in the case of the chiral angle &#x0398; &#x003D; &#x03C0;.</p>
<fig id="fig4" position="float">
<label>Fig. 4.</label>
<caption><p>The Casimir energy per plate area as a function of &#x2113;. The left panel corresponds to the dependence of the Casimir energy on the mass <italic>m</italic> for the nonchiral case. The right panel corresponds to the dependence of the Casimir energy on the chiral angle &#x0398; with fixed mass <italic>m</italic> &#x003D; 1&#x00A0;eV and a plate size <italic>L</italic><sup>2</sup> &#x003D; 1&#x00A0;cm<sup>2</sup>.</p></caption>
<graphic xmlns:xlink="http://www.w3.org/1999/xlink" xlink:href="ptac172fig4.jpg" mimetype="image"/>
</fig>
<p>We next turn to consider the analytical evaluation of the Casimir energy in Eq.&#x00A0;(<xref ref-type="disp-formula" rid="update1673783971364">50</xref>). In the case of <italic>m</italic><sup>&#x2032;</sup> &#x226A; 1, the Casimir energy for an arbitrary chiral angle approximately reduces to
<disp-formula id="update1673784419386">
<label>(52)</label>
<tex-math id="TM0082" notation="LaTeX"><![CDATA[$$\begin{eqnarray}
E_{\rm Cas.}&\simeq &{-L^2 \over \pi ^2 \ell ^3 } \int ^\infty _0 {\mathrm{d}}y \bigg [ y^2\ln (1+e^{-2y})-\bigg ({2y {e^{-2y}} (y+\cos \Theta )\over (1+e^{-2y})}-2y\ln (1+e^{-2y})\bigg )m^{\prime }\bigg ] \\
&=&-{7 L^2\pi ^2\over 2880 \ell ^3} \bigg (1-{120 m^{\prime } \cos \Theta \over 7\pi ^2}\bigg ).
\end{eqnarray}$$]]></tex-math>
</disp-formula>Compared to the massless case (<xref ref-type="disp-formula" rid="update1674819697137">51</xref>), the above expression has an additional term that contributes to the Casimir energy. We also note that this term shows the Casimir energy dependence on the chiral angle. In the case of <italic>m</italic><sup>&#x2032;</sup> &#x226B; 1, the Casimir energy (<xref ref-type="disp-formula" rid="update1673783971364">50</xref>) is approximately given by
<disp-formula id="update1673784454427">
<label>(53)</label>
<tex-math id="TM0083" notation="LaTeX"><![CDATA[$$\begin{eqnarray}
E_{\rm Cas.} &\simeq & {-L^2 \over \pi ^2 \ell ^3 } \int ^\infty _0 {\mathrm{d}}y \\
&&\times \biggr [ \biggr ( {\sqrt{2m^{\prime 3}}y^{1/2} (1-\cos \Theta )\over 1+\cos \Theta }+\sqrt{m^{\prime }\over 2}{y^{3/2}(5+8\cos \Theta -5\cos ^2\Theta )\over 2(1+\cos \Theta )^2}\biggr )e^{-2(y+m^{\prime })}\biggr ] \\
&=&{-L^2 m^{\prime 1/2}e^{-2m^{\prime }} \over 64 (1+\cos \Theta )^2\pi ^{3/2} \ell ^3 }\bigg [{16 m^{\prime }\sin ^2\Theta } +{3(5+8\cos \Theta -5\cos ^2\Theta )}\bigg ].
\end{eqnarray}$$]]></tex-math>
</disp-formula>In this case, the Casimir energy decays and converges to zero with the increase in the parameter <italic>m</italic><sup>&#x2032;</sup>.</p>
<p>From the above Casimir energy, one can investigate the Casimir force <italic><inline-formula><tex-math id="TM0084" notation="LaTeX"><![CDATA[$F_{\rm Cas.}=-\partial E_{\rm Cas.}/\partial \ell$]]></tex-math></inline-formula></italic> as well as the Casimir pressure <italic>P</italic><sub>Cas.</sub> &#x003D; <italic>F</italic><sub>Cas.</sub>/<italic>L</italic><sup>2</sup>. From Eqs.&#x00A0;(<xref ref-type="disp-formula" rid="update1673784419386">52</xref>) and (<xref ref-type="disp-formula" rid="update1673784454427">53</xref>), one can obtain the following Casimir pressure,
<disp-formula id="equ54">
<label>(54)</label>
<tex-math id="TM0085" notation="LaTeX"><![CDATA[$$\begin{eqnarray}
P_{\rm Cas.} =\left\lbrace \begin{array}{ll}-{7 \pi ^2 \over 960 \ell ^4}\bigg (1-{80 m^{\prime } \cos \Theta \over 7\pi ^2}\bigg ), ~~ \text{for $m^{\prime }\ll 1$},\\
-{m^{\prime 1/2}e^{-2m^{\prime }} \over 64 (1+\cos \Theta )^2\pi ^{3/2} \ell ^4 }\\
\qquad\bigg [{ 8( 4m^{\prime }+3)m^{\prime }\sin ^2\Theta } +(6 m^{\prime }+{5\over 2})(5+8\cos \Theta -5\cos ^2\Theta )\bigg ],~~ \text{for $m^{\prime }\gg 1$}. \end{array} \right.
\end{eqnarray}$$]]></tex-math>
</disp-formula>The above Casimir pressures with respect to the chiral angle have a similar behavior to those of the Casimir energy. In other words, the attractive Casimir force in the chiral case is always stronger than that in the nonchiral case.</p>
</sec>
<sec id="sec5">
<label>5.</label>
<title>Summary</title>
<p>We have studied the behavior of a massive Dirac fermion confined between two parallel chiral plates. In our setup, the plates are represented by chiral MIT boundary conditions [<xref ref-type="bibr" rid="bib10">10</xref>], where the condition of vanishing probability current density at the boundary surfaces is satisfied for arbitrary chiral angles. The Dirac field inside the confinement area consists of two-component fields associated with their spin orientations. We discussed the general discrete momenta and the changes in the spin orientations under boundary conditions. The result shows that only momentum <italic>k</italic><sub>3</sub> (the component parallel to the normal plate surface) is discretized depending on the mass, the distance between the plates, and the chiral angle. We also found that, in the case of nonzero perpendicular momenta, the spin orientation changes for an arbitrary chiral angle. In the case of suppressed perpendicular momenta, we found that these features reduce to those of a previous work [<xref ref-type="bibr" rid="bib42">42</xref>] for a confinement system in a one-dimensional box.</p>
<p>We also discussed the energy gap between two states in the case of light mass (<italic>m</italic><sup>&#x2032;</sup> &#x226A; 1). The result shows that the effect of the chiral angle is to correct the energy gap in the massless case. In this context, we may address such an effect on the electron transport in materials such as graphene nanoribbons [<xref ref-type="bibr" rid="bib49 bib50 bib51">49&#x2013;51</xref>]. Since the chiral angle is coupled to the mass, the correction term with the chiral angle is quite small depending on the mass value. Our present study could also be applicable to nanotubes, where one can consider a confinement system of a Dirac field between two parallel plates with compactified dimensions [<xref ref-type="bibr" rid="bib30">30</xref>]. The detailed analysis of such an application is beyond the scope of the present study and will be presented elsewhere.</p>
<p>We have also investigated the effect of the chiral angle on the Casimir energy of a massive fermion field. To obtain the Casimir energy, we calculated the vacuum energy in the presence of the boundary condition. Unfortunately, this vacuum energy is divergent. To solve this issue, we adopt the Abel&#x2013;Plana-like summation [<xref ref-type="bibr" rid="bib52">52</xref>], as previously used in Refs.&#x00A0;[<xref ref-type="bibr" rid="bib30">30</xref>,<xref ref-type="bibr" rid="bib31">31</xref>]. The obtained vacuum energy consists of three parts (see Eq.&#x00A0;(<xref ref-type="disp-formula" rid="equ40">40</xref>)), i.e. (i) the vacuum energy in the absence of the boundary conditions, (ii) the vacuum energy in the presence of a single plate, and (iii) the Casimir energy. We notice that the second term of the vacuum energy in Eq.&#x00A0;(<xref ref-type="disp-formula" rid="equ40">40</xref>) for a single plate is not relevant to the Casimir force. The Casimir energy is defined by taking the differences between the vacuum energy of a Dirac field in the presence of the boundary conditions to that in the absence of one. We investigated the behavior of the Casimir energy as well as its attractive force using numerical analysis. The result shows that the Casimir energy of a massive fermion field can be written as a function of the chiral angle. It is symmetric with the maximum contribution occurring at &#x0398; &#x003D; &#x03C0;; the Casimir energy in the chiral case is always higher than that in the nonchiral case.</p>
<p>In addition to the above results, we also found that the behavior of the Casimir energy depends on the mass of the Dirac fermion. In the analysis, we investigated two approximation cases, i.e. light and heavy masses. In the case of heavy fermion mass, the Casimir energy converges to zero as the mass increases, whereas in the case of light fermion mass, the Casimir energy converges to that of the massless fermion as the mass decreases. We found that, in both cases, the roles of the chiral angle become weaker. For the case of the massless fermion, the Casimir energy gives the same value for all chiral angles. In this case, we recover the expected result according to Ref.&#x00A0;[<xref ref-type="bibr" rid="bib34">34</xref>]. For future work, it will be interesting to study a similar setup by including a background such as a magnetic field (cf. Ref.&#x00A0;[<xref ref-type="bibr" rid="bib46">46</xref>]).</p>
</sec>
</body>
<back>
<ack id="ack1"><title>Acknowledgements</title>
<p>This work was started when A.&#x00A0;R. stayed at Kyushu University, Japan as an academic researcher (postdoctoral fellow) and was completed when he was on the postdoctoral program at the National Research and Innovation Agency (BRIN), Indonesia. A.&#x00A0;R. would like to thank the Theoretical Astrophysics Laboratory of Kyushu University for their kind hospitality. We also thank A.&#x00A0;N.&#x00A0;Atmaja for fruitful discussions.</p>
</ack>
<sec id="sec10">
<title>Funding</title>
<p>Open access funding: SCOAP<sup>3</sup>.</p>
</sec>
<app-group>
<app id="sec7"><title>Appendix A. Complementary derivations for discrete momenta</title>
<p>Two-component Dirac spinors <italic>&#x03C7;</italic><sub>R(L)</sub> can be decomposed as
<disp-formula id="update1673786985037">
<label>(A1)</label>
<tex-math id="TM0091" notation="LaTeX"><![CDATA[$$\begin{eqnarray}
\chi _{{\mathrm{R}}({\mathrm{L}})}= {\begin{pmatrix}\alpha _{{\mathrm{R}}({\mathrm{L}})}\\
\beta _{{\mathrm{R}}({\mathrm{L}})} \end{pmatrix}} .
\end{eqnarray}$$]]></tex-math>
</disp-formula>The relation in Eq.&#x00A0;(<xref ref-type="disp-formula" rid="update1673781889659">12</xref>) can then be rewritten in a more explicit way as follows
<disp-formula id="update1673787057479">
<label>(A2)</label>
<tex-math id="TM0092" notation="LaTeX"><![CDATA[$$\begin{eqnarray}
B= -C {(-ik_3(1+\sin \Theta )-(m+E)\cos \Theta )\alpha _{\mathrm{L}}+i(k_1-ik_2)(1+\sin \Theta )\beta _{\mathrm{L}} \over (ik_3(1+\sin \Theta )-(m+E)\cos \Theta )\alpha _{\mathrm{R}}+i(k_1-ik_2)(1+\sin \Theta )\beta _{\mathrm{R}}},
\end{eqnarray}$$]]></tex-math>
</disp-formula>
<disp-formula id="update1673787102691">
<label>(A3)</label>
<tex-math id="TM0093" notation="LaTeX"><![CDATA[$$\begin{eqnarray}
B= -C {i(k_1+ik_2)(-1+\sin \Theta )\alpha _{\mathrm{L}}+(ik_3(-1+\sin \Theta )-(m+E)\cos \Theta )\beta _{\mathrm{L}} \over i(k_1+ik_2)(-1+\sin \Theta )\alpha _{\mathrm{R}} +(-ik_3(-1+\sin \Theta )-(m+E)\cos \Theta )\beta _{\mathrm{R}}}.
\end{eqnarray}$$]]></tex-math>
</disp-formula>In a similar way, from Eq.&#x00A0;(<xref ref-type="disp-formula" rid="update1673782013092">16</xref>), we have the relation between coefficients <italic>B</italic> and <italic>C</italic> at the second plate <italic>x</italic><sub>3</sub> &#x003D; &#x2113; as follows
<disp-formula id="update1673787141718">
<label>(A4)</label>
<tex-math id="TM0094" notation="LaTeX"><![CDATA[$$\begin{eqnarray}
B= -C e^{-2ik_3\ell }{(-ik_3(-1+\sin \Theta )-(m+E)\cos \Theta )\alpha _{\mathrm{L}}+i(k_1-ik_2)(-1+\sin \Theta )\beta _{\mathrm{L}} \over (ik_3(-1+\sin \Theta )-(m+E)\cos \Theta )\alpha _{\mathrm{R}}+i(k_1-ik_2)(-1+\sin \Theta )\beta _{\mathrm{R}}},
\end{eqnarray}$$]]></tex-math>
</disp-formula>
<disp-formula id="update1673787179423">
<label>(A5)</label>
<tex-math id="TM0095" notation="LaTeX"><![CDATA[$$\begin{eqnarray}
B= -C e^{-2ik_3\ell } {i(k_1+ik_2)(1+\sin \Theta )\alpha _{\mathrm{L}}+(ik_3(1+\sin \Theta )-(m+E)\cos \Theta )\beta _{\mathrm{L}} \over i(k_1+ik_2)(1+\sin \Theta )\alpha _{\mathrm{R}} +(-ik_3(1+\sin \Theta )-(m+E)\cos \Theta )\beta _{\mathrm{R}}}.
\end{eqnarray}$$]]></tex-math>
</disp-formula>By equating Eqs.&#x00A0;(<xref ref-type="disp-formula" rid="update1673787057479">A2</xref>) and (<xref ref-type="disp-formula" rid="update1673787141718">A4</xref>), we have
<disp-formula id="update1673787243678">
<label>(A6)</label>
<tex-math id="TM0096" notation="LaTeX"><![CDATA[$$\begin{eqnarray}
(A_1\alpha _{\mathrm{R}}+A_2\beta _{\mathrm{R}})\alpha _{\mathrm{L}}+(A_3\alpha _{\mathrm{R}}+A_4\beta _{\mathrm{R}})\beta _{\mathrm{L}}=0,
\end{eqnarray}$$]]></tex-math>
</disp-formula>where
<disp-formula id="equ61">
<label>(A7)</label>
<tex-math id="TM0097" notation="LaTeX"><![CDATA[$$\begin{eqnarray}
A_1 &=& e^{-2 ik_3 \ell } \cos \Theta \big [2 i (1 + e^{2 i k_3 \ell }) k_3 (E + m) \\
&&+ \,\, (-1 + e^{2 i k_3 \ell }) (E - k_3 + m) (E + k_3 + m) \cos \Theta \big ],
\end{eqnarray}$$]]></tex-math>
</disp-formula>
<disp-formula id="equ62">
<label>(A8)</label>
<tex-math id="TM0098" notation="LaTeX"><![CDATA[$$\begin{eqnarray}
A_2&=&e^{-2 i k_3 \ell } \cos \Theta (k_1 - i k_2)\big [(1 - e^{2 i k_3 \ell }) k_3 \cos \Theta \\
&&-\,\, i (E + m) (-1 - \sin \Theta + e^{2 i k_3 \ell } (-1 + \sin \Theta ) )\big ],
\end{eqnarray}$$]]></tex-math>
</disp-formula>
<disp-formula id="equ63">
<label>(A9)</label>
<tex-math id="TM0099" notation="LaTeX"><![CDATA[$$\begin{eqnarray}
A_3&=&e^{-2 i k_3 \ell } \cos \Theta (k_1 - i k_2) \big [(-1 + e^{2 i k_3 \ell }) k_3 \cos \Theta \\
&&+\,\, i (E + m) (-1 + \sin \Theta - e^{2 i k_3 \ell } (1 + \sin \Theta ))\big ],
\end{eqnarray}$$]]></tex-math>
</disp-formula>
<disp-formula id="equ64">
<label>(A10)</label>
<tex-math id="TM0100" notation="LaTeX"><![CDATA[$$\begin{eqnarray}
A_4&=& \cos ^2\Theta (k_1 - i k_2)^2 (1-e^{-2ik_3\ell }).
\end{eqnarray}$$]]></tex-math>
</disp-formula>Taking same procedure as above for Eqs.&#x00A0;(<xref ref-type="disp-formula" rid="update1673787102691">A3</xref>) and (<xref ref-type="disp-formula" rid="update1673787179423">A5</xref>), we have
<disp-formula id="update1673787320953">
<label>(A11)</label>
<tex-math id="TM0101" notation="LaTeX"><![CDATA[$$\begin{eqnarray}
(B_1\alpha _{\mathrm{R}}+B_2\beta _{\mathrm{R}})\alpha _{\mathrm{L}}+(B_3\alpha _{\mathrm{R}}+B_4\beta _{\mathrm{R}})\beta _{\mathrm{L}}=0,
\end{eqnarray}$$]]></tex-math>
</disp-formula>where
<disp-formula id="equ66">
<label>(A12)</label>
<tex-math id="TM0102" notation="LaTeX"><![CDATA[$$\begin{eqnarray}
B_1= {(k_1+ik_2)^2\over (k_1-ik_2)^2}A_4,
\end{eqnarray}$$]]></tex-math>
</disp-formula>
<disp-formula id="equ67">
<label>(A13)</label>
<tex-math id="TM0103" notation="LaTeX"><![CDATA[$$\begin{eqnarray}
B_2={k_1+i k_2\over k_1-ik_2}A_2,
\end{eqnarray}$$]]></tex-math>
</disp-formula>
<disp-formula id="equ68">
<label>(A14)</label>
<tex-math id="TM0104" notation="LaTeX"><![CDATA[$$\begin{eqnarray}
B_3={k_1+i k_2\over k_1-i k_2}A_3,
\end{eqnarray}$$]]></tex-math>
</disp-formula>
<disp-formula id="equ69">
<label>(A15)</label>
<tex-math id="TM0105" notation="LaTeX"><![CDATA[$$\begin{eqnarray}
B_4=A_{1}.
\end{eqnarray}$$]]></tex-math>
</disp-formula>The relation given in Eqs.&#x00A0;(<xref ref-type="disp-formula" rid="update1673787243678">A6</xref>) and (<xref ref-type="disp-formula" rid="update1673787320953">A11</xref>) can be written simultaneously in the form of multiplication between 2 &#x00D7; 2 and 2 &#x00D7; 1 matrices as follows
<disp-formula id="update1673787401031">
<label>(A16)</label>
<tex-math id="TM0106" notation="LaTeX"><![CDATA[$$\begin{eqnarray}
{\begin{pmatrix}(A_1 \alpha _{\mathrm{R}}+A_2\beta _{\mathrm{R}}) ~& \quad ~ (A_3 \alpha _{\mathrm{R}}+A_4\beta _{\mathrm{R}})\\
(B_1 \alpha _{\mathrm{R}}+B_2\beta _{\mathrm{R}}) ~& \quad ~ (B_1 \alpha _{\mathrm{R}}+B_4\beta _{\mathrm{R}}) \end{pmatrix}} {\begin{pmatrix}\alpha _{\mathrm{L}}\\
\beta _{\mathrm{L}} \end{pmatrix}} =0.
\end{eqnarray}$$]]></tex-math>
</disp-formula>The nontrivial values of <italic>&#x03B1;</italic><sub>L</sub> and <italic>&#x03B2;</italic><sub>L</sub> require the 2 &#x00D7; 2 matrix determinant in Eq.&#x00A0;(<xref ref-type="disp-formula" rid="update1673787401031">A16</xref>) to vanish, which leads to the following condition
<disp-formula id="update1673787495458">
<label>(A17)</label>
<tex-math id="TM0107" notation="LaTeX"><![CDATA[$$\begin{eqnarray}
D_1\alpha ^2_{\mathrm{R}}+D_2\alpha _{\mathrm{R}}\beta _{\mathrm{R}}+D_3\beta ^2_{\mathrm{R}}=0,
\end{eqnarray}$$]]></tex-math>
</disp-formula>where
<disp-formula id="equ72">
<label>(A18)</label>
<tex-math id="TM0108" notation="LaTeX"><![CDATA[$$\begin{eqnarray}
D_1&=& A_1B_3-A_3B_1 \\
&=&-2 e^{-4 ik_3 \ell } \cos ^2\Theta (E+m) \big [i (1 + e^{2 i k_3 \ell }) k_3+ (-1 + e^{2 i k_3 \ell })m \cos \Theta \big ] \\
&&\times\,\, (k_1+ik_2) \big [-(-1+e^{2 i k_3 \ell })k_3\cos \Theta +i(E+m)(1-\sin \Theta +e^{2 i k_3 \ell }(1+\sin \Theta ))\big ],
\end{eqnarray}$$]]></tex-math>
</disp-formula>
<disp-formula id="equ73">
<label>(A19)</label>
<tex-math id="TM0109" notation="LaTeX"><![CDATA[$$\begin{eqnarray}
D_2&=&A_1B_4+A_2B_3-A_3B_2-A_4B_1 \\
&=&4 e^{-4 ik_3 \ell } \cos ^2\Theta (E+m) \big [i (1 + e^{2 i k_3 \ell }) k_3+ (-1 + e^{2 i k_3 \ell })m \cos \Theta \big ] \\
&&\times\, \big [i (1 + e^{2 i k_3 \ell }) k_3 (E+m)+ (-1 + e^{2 i k_3 \ell })(E^2+mE-k^2_3) \cos \Theta \big ],
\end{eqnarray}$$]]></tex-math>
</disp-formula>
<disp-formula id="equ74">
<label>(A20)</label>
<tex-math id="TM0110" notation="LaTeX"><![CDATA[$$\begin{eqnarray}
D_3&=& A_2B_4-A_4B_2 \\
&=&2 e^{-4 ik_3 \ell } \cos ^2\Theta (E+m) \big [i (1 + e^{2 i k_3 \ell }) k_3+ (-1 + e^{2 i k_3 \ell })m \cos \Theta \big ] \\
&&\times\,\, (k_1-ik_2) \big [-(-1+e^{2 i k_3 \ell })k_3\cos \Theta -i(E+m)(-1-\sin \Theta +e^{2 i k_3 \ell }(-1+\sin \Theta ))\big ].
\end{eqnarray}$$]]></tex-math>
</disp-formula>From the previous expressions, we can see that <italic>D</italic><sub>1</sub>, <italic>D</italic><sub>2</sub>, <italic>D</italic><sub>3</sub> have the same factor as follows
<disp-formula id="equ75">
<label>(A21)</label>
<tex-math id="TM0111" notation="LaTeX"><![CDATA[$$\begin{eqnarray}
2 e^{-4 ik_3 \ell } \cos ^2\Theta (E+m) \big [i (1 + e^{2 i k_3 \ell }) k_3+ (-1 + e^{2 i k_3 \ell })m \cos \Theta \big ].
\end{eqnarray}$$]]></tex-math>
</disp-formula>To satisfy the condition in Eq.&#x00A0;(<xref ref-type="disp-formula" rid="update1673787495458">A17</xref>) for arbitrary chiral angle &#x0398;, the above factor must vanish
<disp-formula id="equ76">
<label>(A22)</label>
<tex-math id="TM0112" notation="LaTeX"><![CDATA[$$\begin{eqnarray}
i (1 + e^{2 i k_3 \ell }) k_3+ (-1 + e^{2 i k_3 \ell })m \cos \Theta =0,
\end{eqnarray}$$]]></tex-math>
</disp-formula>which leads to the allowed condition for discrete momenta in Eq.&#x00A0;(<xref ref-type="disp-formula" rid="equ17">17</xref>).</p>
</app>
</app-group>
<fn-group>
<title>Footnotes</title>
<fn id="fn1"><label>1</label><p>The rotation angle and rotation axis can also be written as <inline-formula><tex-math id="TM0086" notation="LaTeX"><![CDATA[$\tan ({\varphi ^{(1)}/2})=-\tan \Theta (k^{\prime }_{3n}/\ell )\sqrt{2m^2+2mE_n+k^{\prime 2}_{3n}/\ell ^2 +{\boldsymbol k}^2_\perp \cot ^2\Theta }/ (k^{\prime 2}_{3n}/\ell ^2+m E_n+m^2)$]]></tex-math></inline-formula> and <inline-formula><tex-math id="TM0087" notation="LaTeX"><![CDATA[$\hat{\boldsymbol n}^{(1)}={k_2\hat{x}_1-k_1 \hat{x}_2+(m+E_n)\tan \Theta \hat{x}_3 /(\tan \Theta \sqrt{2m^2+2mE_n+k^{\prime 2}_{3n}/\ell ^2 +{\boldsymbol k}^2_\perp \cot ^2\Theta }})$]]></tex-math></inline-formula>, respectively. These expressions reduce to those in Ref.&#x00A0;[<xref ref-type="bibr" rid="bib42">42</xref>] in the case of suppressed perpendicular momentum <inline-formula><tex-math id="TM0088" notation="LaTeX"><![CDATA[${\boldsymbol k}_\perp =0$]]></tex-math></inline-formula>. As has been mentioned in Ref.&#x00A0;[<xref ref-type="bibr" rid="bib42">42</xref>], one may choose the opposite sign of the above rotation axis. As the consequence, the rotation angle has an opposite sign to the above one. This condition holds not only for the first plate but also the second one.</p></fn>
<fn id="fn2"><label>2</label><p>Similar to the result at the first plate, the rotation angle and the rotation axis at the second plate can also be written in the form of <inline-formula><tex-math id="TM0089" notation="LaTeX"><![CDATA[$\tan ({\varphi ^{(2)}/2})=-\tan \Theta k_{3n}\sqrt{2m^2+2mE_n+k^{\prime 2}_{3n}/\ell ^2 +{\boldsymbol k}^2_\perp \cot ^2\Theta }/ (k^{\prime 2}_{3n}/\ell ^2+m E_n+m^2)$]]></tex-math></inline-formula> and <inline-formula><tex-math id="TM0090" notation="LaTeX"><![CDATA[$\hat{\boldsymbol n}^{(2)}={-k_2\hat{x}_1+k_1 \hat{x}_2-(m+E_n)\tan \Theta \hat{x}_3 /(\tan \Theta \sqrt{2m^2+2mE_n+k^{\prime 2}_{3n}/\ell ^2 +{\boldsymbol k}^2_\perp \cot ^2\Theta }})$]]></tex-math></inline-formula>, respectively. In the case of suppressed perpendicular momentum, they reduce to those of Ref.&#x00A0;[<xref ref-type="bibr" rid="bib42">42</xref>].</p></fn>
</fn-group>
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